Molecular Orbital Theory Explained in 11 Minutes
To understand molecular orbital theory
deeply, we will cover these topics in
this video. Main postulates of molecular
orbital theory, difference between
bonding molecular orbitals and
antib-bonding molecular orbitals, what
is bond order and how we can find it.
How to check paramagnetic and
diamagnetic behavior and how to
determine the energy order of molecular
orbitals. First, let's start with the
main postulates of molecular orbital
theory. The first postulate says that
atomic orbitals intermix to form
molecular orbitals. For example, in the
case of a hydrogen molecule, when its
two atomic orbitals intermix with each
other, they result in the formation of
molecular orbitals. And we will discuss
this in detail. According to the second
postulate, the number of molecular
orbitals formed will always be equal to
the number of atomic orbitals that
intermix. This means that if two atomic
orbitals are involved in mixing, it will
always form two molecular orbitals.
According to the third postulate, only
those atomic orbitals will intermix with
each other that have comparable
energies. This means that the 1s orbital
will overlap with the 1s orbital of
another atom. And similarly, the 2s
orbital will overlap with the 2s orbital
of another atom. It is not possible that
the 1s orbital of one atom can overlap
with the 2s orbital of another atom.
Now, we will move towards bonding
molecular orbitals and antib-bonding
molecular orbitals. To understand this,
we will draw the molecular orbital
diagram of a hydrogen molecule. As we
know, a hydrogen atom has one electron
and it is present in the 1s orbital. So,
it means that in order to form a bond,
these atomic orbitals should intermix.
Here we can see that two atomic orbitals
are taking part in mixing. So, it means
that two molecular orbitals will be
obtained. But we need to keep in mind
that half of the molecular orbitals will
have lower energy than the parent atoms
and half will have higher energy than
the parent atoms. So it simply means
that the two molecular orbitals which
will be formed in this case, one will
have lower energy and the other one will
have higher energy than the parent atom.
Now it's time to see what actually is
the difference between bonding molecular
orbitals and antib-bonding molecular
orbitals. Keep in mind that molecular
orbitals that have lower energy than
their parent atomic orbitals will be
called bonding molecular orbitals and
those having higher energy than their
parent atomic orbitals will be
antib-bonding molecular orbitals. We
need to understand one more important
point. Since anti-bonding molecular
orbitals are higher in energy than
bonding molecular orbitals, they will be
denoted by placing a star on them. For
example, sigma star and pi star. Bonding
molecular orbitals due to their lower
energy will be denoted without a star
and they will be called sigma and pi
bonds. Now, we need to understand how we
should place electrons in molecular
orbitals. Keep in mind we need to follow
the rules of electronic configuration
such as Pauliey's exclusion principle,
offbal principle and Hun's rule. For
example, in the case of a hydrogen
molecule since there are a total of two
electrons in the atomic orbitals of
hydrogen, we need to place them in
molecular orbitals. Both electrons will
be placed in the sigma 1s orbital which
is actually a bonding molecular orbital
and no electron will be available for
antib-bonding molecular orbitals. This
happens due to the offbell principle
which states that electrons must be
filled according to their increasing
energy levels. So first we need to
complete the sigma 1s orbital and both
electrons will be filled in it. Now we
will discuss what bond order is and how
we can find it. Actually bond order
refers to the total number of bonds
formed between two atoms when their
atomic orbitals overlap. We can find the
bond order of any molecule with this
formula. Bond order is equal to total
number of electrons in bonding molecular
orbitals subtracting total number of
electrons in anti-bonding molecular
orbitals and divided by two. We can
understand this with the example of a
helium molecule. As we know the atomic
number of helium is 2. So its veence
electrons will be present in the 1s
orbital and its electronic configuration
will be 1 s2. To draw its molecular
orbital diagram, the 1s orbital of one
helium atom should intermix with the 1s
orbital of the other helium atom.
According to the postulates, two
molecular orbitals should be formed. One
will have lower energy than the parent
atom and will be called a bonding
molecular orbital while the other will
have higher energy than the parent atom
and will be called an anti-bonding
molecular orbital. As we can see, there
are a total of four electrons present in
the atomic orbitals of helium. So now we
need to place them in molecular
orbitals. According to the rules, two
electrons should be placed in the sigma
1s orbital and two will be placed in the
sigma star 1s orbital. Now to find the
bond order, we will apply the formula.
As we can see, two electrons are present
in bonding molecular orbitals and two
electrons are present in anti-bonding
molecular orbitals. So it will be 2
subtraction 2 and divided by two and its
answer will be equal to zero. This means
that the bond order of helium is zero.
From this we can conclude that helium
will never form a bond since its bond
order is zero. You can also check this
for a hydrogen molecule and its bond
order will be one which shows that
hydrogen will always form one bond. Now
we will understand the difference
between paramagnetic and diamagnetic
behavior. We need to remember that if
there is any unpaired electron present
in molecular orbitals then that molecule
will always be paramagnetic in nature.
But if all the electrons are paired and
no unpaired electron is present in
molecular orbitals then we should say
that it is diamagnetic in nature. To
understand this deeply and also to
understand the main concepts of
molecular orbital theory. Now we will
take the example of a nitrogen molecule.
As we know the atomic number of nitrogen
is 7. From the electronic configuration
of nitrogen, we can see that in this
case, first of all, the 2s orbital of
the first nitrogen atom should overlap
with the 2s orbital of the second
nitrogen atom and will form two
molecular orbitals of nitrogen. And as
mentioned earlier, electrons will be
placed in them. But here we need to
deeply understand how 2 p orbitals will
overlap and how electrons will be placed
in them. First of all, remember that 3 2
p orbitals of one nitrogen will overlap
with 32 p orbitals of the second
nitrogen. It means that a total of six
orbitals are intermixing in this case.
So according to the postulate, six
molecular orbitals should be formed. But
we need to understand that half will
have lower energy and half will have
higher energy than their parent
orbitals. This means that out of six
molecular orbitals, three will be
bonding molecular orbitals and three
will be anti-bonding molecular orbitals.
In the next step, we need to place
electrons of 2 p orbitals into molecular
orbitals that are being formed. In this
case, as we can see, there are a total
of six electrons present in atomic
orbitals. So, we have to place them in
molecular orbitals. All these six
electrons will be placed in bonding
molecular orbitals and no electron will
go towards anti-bonding molecular
orbitals. Now, if we move towards the
bond order of this molecule again, we
need to apply the formula which shows
that there are six electrons in bonding
molecular orbitals and no electrons are
present in anti-bonding molecular
orbitals. So it will be 6 subtracting 0
and divided by two and its answer will
be three. This shows that the bond order
of nitrogen is three and it will form
three bonds. Now if we look at its
magnetic behavior as we can see all
electrons in molecular orbitals are
paired and no unpaired electrons are
present here. So we can say that
nitrogen is diiamagnetic in nature. Now
we'll discuss how to write the relative
energy order for molecular orbitals.
Keep in mind that molecular orbitals
formed are different in energy from each
other. So in order to assign them an
energy order, we simply need to start
writing their energy levels in ascending
order. For example, in the case of
hydrogen, as mentioned above, sigma 1s
will have lower energy than sigma star 1
s. Similarly, if a molecule also has 2 s
orbitals involved in mixing, we can say
that the energy of sigma 2s will be
lower than sigma star 2s. But one thing
we need to keep in mind is that the
energy of pi^ 2 py and 2pz will always
be equal. So by following this simple
concept we can write the energy order
for any molecule. Now we will discuss
how molecular orbital theory explains
ions such as hydrogen ion, nitrogen ion
and oxygen ion. First let's start with
hydrogen ion. As we know a neutral
hydrogen atom has one electron in its 1
s orbital. When two hydrogen atoms
combine their atomic orbitals intermix
to form molecular orbitals resulting in
bonding and antib-bonding molecular
orbitals. Now if we consider hydrogen
molecular ion we can see that only one
electron is available. According to the
offbound principle this electron will be
placed in the lower energy bonding
molecular orbital which is sigma 1s.
Since there is no electron present in
the anti-bonding molecular orbital which
is sigma star 1 s. The bond order can be
found using the formula. So we can see
bond order will be equal to 1
subtracting 0 and divided by 2 which
will be equal to 0.5. Since the bond
order is not zero, it means that
hydrogen molecular ion is capable of
existing as a weakly bonded species but
it will be less stable than hydrogen
molecule. Now let's move to nitrogen
ion. For a neutral nitrogen molecule, we
know that nitrogen has an atomic number
of 7. Meaning its electronic
configuration is 1 s2 2 s2 2 p3. Now
let's consider nitrogen ion. Since
nitrogen negative ion has one extra
electron, it will be placed in the next
available molecular orbital which is a
pi star 2p orbital. Now the bond order
will also change. Bond order will be
equal to 8 subtracting 3 and divided by
2 which will be equal to 2.5. This means
that when an extra electron is added the
bond order decreases making nitrogen
negative ion less stable than a neutral
nitrogen molecule. Now we will discuss
oxygen ion. Molecular orbital
explanation for O negative ion. Now if
we consider oxygen negative ion, it has
one extra electron which will enter the
pi star 2p orbital. This changes the
bond order as follows. Bond order will
be equal to 8 subtracting 5 and divided
by 2 which will be equal to 1.5. This
means that oxygen negative ion has a
lower bond order than a neutral oxygen
molecule making it less stable and
weaker in bonding strength. Effect of
charge on bond order and stability. From
these examples, we can conclude that
adding an electron as in nitrogen
negative ion and oxygen negative ion
decreases bond order making the molecule
weaker. Removing an electron as in
hydrogen molecular ion reduces bond
order but does not completely eliminate
bonding. More charge generally results
in a weaker molecular bond due to
increased electron repulsion in
antib-bonding orbitals. Now moving
towards limitations of molecular
orbitals theory. It has several
important limitations. Number one, no
clear molecular shape. It does not
explain the exact shapes of molecules
unlike VR theory. Number two, complex
mathematical calculations. The theory
relies on advanced math making it
difficult to apply. Number three, fails
for some molecules. It does not
correctly predict bonding in certain
molecules such as oxygen where
experimental results show differences in
magnetic properties. Number four, weak
explanation of bond strength. It does
not always explain why some bonds are
stronger or weaker in certain molecules.
Number five, contradictions with other
theories. It sometimes disagrees with
valance bond theory, which explains
bonding in a different way.
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