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warahmatullahi wabarakatuh meet again

in Munich elu online

mathematics guidance On this occasion we

will discuss the opportunity of one

easily and easily understood together

with the bom channel As for the opportunity material

that we will learn On

this occasion the first is

the definition then the probability of the event

frequency expectation probability complement

for the first material is the definition What

is a sample space the set of all possible

outcomes that may

appear in an experiment then the

sample point members of the

sample space then the experiment the process that

produces data then the event

subset of the sample space

next we will learn

is the sample space for example

is a dice in the experiment a

dice is thrown once repeated the

sample of the dice there are six 1234566

then the sample point 1234567 sample

part of the sample space then the

event of an odd dice appearing from

this sample space we will choose the

odd one 135 then the event of an

even dice appearing from

Ibn sample we will choose the even

example of the next sample space is

in the experiment 1 coin is thrown

once one coin has a number then the image of the

sample space is the number of images

then the sample point the number of images

then the event that this number appears

is A1 this then the event that the

image appears is J1 then the next is

how to determine the sample space

for example two coins are

thrown together The first way

we use the table means this coin

1 and coin two numbers are the same image the

same image when two coins are thrown

together the appearance is the same number number

Hi the number of images the

last number is the images means the

meaning of the es is the number of numbers the images the

images

then the number of sample points in

this sample space is what we call

NS =

Hi the second way can use the

factor tree one coin 2coin then the

sample space is 12345 Naen esnya

= 4 next is three coins the

coins are thrown together what is the

sample space we will use the table

12 coins when thrown Agam part of the

sample space then the coin that

when is the number of images when three

coins are thrown Then the result is

12345678 meaning the number of

sample points is 81 coins 22 coins 43 coins

8

Hi then four coins the way is even

simpler 2 ^ 12 ^ 2 2 ^ 3

of course 4 coin when thrown then the

sample space is 16 Still on

determining the sample space this time which is

related to two dice 2 dice

thrown simultaneously the method is by

using the first decu table The

second dice when two dice are thrown

then the sample space is if we

calculate then the NS is equal to 36 the

next material is the probability of an event If

a is an event and s is the

sample space then the probability of event a

is defined as pea

cliff antenna per NS where Ena many

members of A then NS The number of members of

S

Hi how to assess the probability between

0 = 0 and 1 means if the probability is equal to

zero it means the event is impossible

to occur if the probability is equal

to one it means the event will definitely

occur

[Music]

Hi for the next material is

practice questions related to the probability of the

event three coins thrown simultaneously the

probability of 2 numbers and one

picture appearing remember n is the number of members

of a two numbers and one picture here are the numbers picture numbers picture numbers

two numbers and one

picture meaning the total is three then the

NS is three Koit remember previously the

sample space of three coins is

eight so the probability = 3 embezzlement

[Music]

Still on practice questions on the probability of an event

one dice is thrown the probability of getting an

odd number is remember one dice the

sample space is

then email the number of members of a

odd 135 the number is three

then ns1 dice the sample space is 6

then the probability = 3 permission that is 1 chapter 2

next practice question two dice are

thrown the probability of getting a number of dice

totaling 10 is remember two dice the

sample space is 36 Ena the number of members of A

means dd1 plus dice 2 = 10

we will look for dice 1 and

dice 2 which total 10 that is 4-6 5564

meaning the number is 3123

Hi the good thing is three then ns2 dice is equal

to 36 then the probability = 3 per 30 6

that is 1/12

[Music]

Hi Still on the practice question of the probability of an

event this time which is related

to cards a card is taken

randomly from a set of bridge cards the probability of a

transfer event is the check card the

children of member A CQ there are four

black two red two then the es

is a set of cards each of these

cards this type of card as many as 13/14

13th multiply

Hi so that the probability = 4 per

Hi is 1/13 Still on the practice of the

probability of the event of a bag containing

five red marbles and 4

white marbles from the bag

will be taken 2 marbles at once

Determine the probability of taking both

red which B red white we

will discuss the first Previously both were

red Ena many members of A are

red We will use a

combination of a combination of two of the five

requested two available

25 factorial both factorial 5 min 2

factorial this so that the combination of 2 and 5

results is ten then NS

sample space of nine

marbles from red and white will be

taken 2 means a combination of two of

nine that is 9 factorial per two

factorial 9 mint two factorial

Hi powerful the result is 36 so that

the probability = 10 per 36 then the question

by red white NB the many members of B

the output is red white one red

and one white combination one of the five

available five then combination

one of the four results is 29 NS is the

same This is the result

Hi so that the probability = 20 m

[Music]

Hi the next material is The

expected frequency is the result of multiplying the probability of an

event by the frequency or number of

trials. Okay, the expected frequency is equal

to the probability multiplied by n. For example,

a die is thrown 300 times.

Determine the expected frequency of an

even number appearing. What does it mean?

What is our expectation? When thrown

300 times, an

even number appears. The first step is to find

the probability. 36 even numbers

are 246, so it's good to be equal to

three. Then the sample space of 1 die is 6 =

half. Then the expected frequency is equal

to the probability of multiplying the number of times it is

thrown. Half multiply 300.

Hi, 150 means our expectation of an

even number appearing in 300 throws

is 150 times. For the last material, the

probability of one is the probability of

a complement. The complement of an event or occurrence is the

same as the event or not

occurring. Pea probability of an event is a complement. The

probability of an event is not a.

Where Pea plus Peak complement = 1.

So, to find Pea complement = 1,

ask for an example. From a deck of

bridge cards, one card is drawn at

random. Determine the probability of not drawing a

King card. Pea probability of drawing a

King card is 4/50. Two then. p a

complement the chance of being drawn is not

one gang Same as one minpha,

namely 1 Min part 52 the result is 48

fans 52 so that was a

brief discussion about the chance of 1

definition of the chance of an event, the frequency of

expectations, the chance of complement easily

and easily understood together with the Bom

channel for the next material is the

two compound chances that we will discuss

are not mutually exclusive,

mutually independent, and conditional. Later

we will discuss it easily and easily

understood together with the Bond channel

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wassalamualaikum warahmatullahi

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