FISIKA KELAS XII || MEDAN LISTRIK - LISTRIK STATIS (PART 2)

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Assalamualaikum warahmatullahi wabarakatuh Hello physical friends still on Yusuf Ahmad's channel In this video we will continue the discussion of Class 12 Physics which is related to static electricity material Now this time for the second part which is related to the field of electricity Okay, what is it like? Let's see the explanation next Okay physical friends, what is the field of electricity?

The field means area or area, so the field of electricity is the area around the object that is still affected by the column or electrical system

The strength of the electric field, symbolized by the letter E, shows the level of the power of the electric current around the object or how strong the electric field is. It can be summarized as E = k times r^2, where E is the strength of the electric field

Ki is the mass, K is the constant of the column, which is the value of 9 times 10 to the power of 9, and R is the distance of the point of the mass.

The direction of the electric field is from the positive field to the negative field. Or if in the positive field, the direction of the electric field is away from the field, or out of the field. While in the negative field, the direction of the electric field is towards the negative field. So the direction is from the positive field to the negative field.

Okay, to make it clearer, let's look at the following example. The point P is at a distance of 30 cm from the key capacity, as in the picture. If KA 9x10^9 determines the direction of the power field at the point P. Okay, friends of KA physics, let's discuss together. So here is the point P, it is 30 cm or

3 times 10 minus 1 meter from the key load. This key load is positive, which means the direction of the electric field is out of the load or away from the load. If the point P is here, the electric field is out of the load or away from the load, until the point P.

So the electric medium direction is to the right. E is to the right. The magnitude of E is equal to kQr^2. The value is equal to 9 times 10^9 multiplied by the key or the capacity of 4 micro columns or 4 times 10^6

R = 3 * 10^-1 ^2 or equal to what? 9 * 4 = 36 * 10^9 * 10^-6 = 10^-3 divided by 3 ^-9 * 10^-1 ^-10 ^-2 so what? 36 divided by 9 equal to 4 * 10 ^-5 N / column where is the direction? yes, the direction is to the right okay, it's pretty easy, right?

That is if 1 is a mass, we see the following example here are 2 mass pieces arranged like the following image, the number of Q1 and Q2 is separated by a distance of 10 cm if Q1 +1 micro column, Q2 -2 micro column and K9 x 10^9 is a large determination and a strong direction of the electric field at the point P which is located 4 cm to the right of Q1

So here are Q1 and Q2, the point P is located 4 cm to the right of Q1, for example, the point is here, this is 4 cm, then the one here is 6 cm. How strong is the electric field at point P? Let's see Q1, Q1 is positive.

positive charge, the current current is out of the charge to the point PO, which means it is directed to the right, that's for E1, then Q2, it's negative charge, negative charge for the current current direction, which means it is directed to the charge, if it is directed to the charge at the point P, it means that the direction is

right also, E2, so there is E1 and E2, okay, let's find E1 first, E1 means the same as KQ1 per R1 squared, equal to 9 times 10 to the power 9 times Q1, 1 micro column or 1 times 10 to the power 6 per R, here 4 cm is the same as 4 times 10 to the power -2, water,

squared, then how much is left? 9 times 10^3 divided by 4 squared is 16 times 10^-2^2 10^-4 so 9/16 times 10^-7 N per column is for E1 then E2 equals to KQ2/R 2^2 or 9 times 10^9 times Q2 2 micro columns or 2 times 10^-6

divided by R2 = 6 * 10^2 = 9 * 2 = 18 * 10^9 * 10^6 = 10^3 then 6^2 * 36 * 10^2 = 10^4

So, we only have half times 10^7 Newton per column. In this point P, there is E1 and E2. Because the direction is in the same direction, the result is the same as... So, just add E1 + E2. So, sigma E = 9/16 * 10^7 + 10^7. Okay, we can match the name. So,

16 times 10^7 = 1.06 x 10^7 N

Okay, physical friends, that was a little simple concept related to the field of electricity. Keep watching other discussions in the next videos. If you think this video is useful, please like and share. Don't forget to subscribe too. I am Yusuf Hamada, thank you. Assalamualaikum warahmatullahi wabarakatuh.