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Resumen completo PAES M1 Regular 2025

4:17:01EnglishTranscribed Jul 28, 2026
0:00

Welcome to the summary of the

0:02

PAES M1 2025. In this video you will

0:05

learn all the content that is included

0:08

in the test, along with learning

0:10

to answer questions like the ones you

0:11

They could appear in the PAES step by step. The

0:14

The methodology of this video is good.

0:16

simple. You're going to have a block for

0:19

each piece of test content and

0:20

later, once you learn the

0:22

Full content, you'll find it here

0:24

down below in the description with the

0:26

exercises that might come up in that

0:29

content and you'll learn, like I told you

0:31

Previously, to solve them, I would...

0:33

passed. We've added something very special.

0:35

which are the M30N cumulative guides.

0:38

These cumulative guides fulfill the

0:40

function of not forgetting the contents

0:42

that you have been learning and that

0:44

exercise at all times. The video

0:46

It has four cumulative guides,

0:48

one at the end of each thematic axis and in

0:50

each cumulative guide, as its name suggests

0:52

It indicates, you accumulate all the materials that

0:54

you have seen up to that point. By

0:56

For example, you finish some things and the guide

0:59

It includes exercises for the entire subject.

1:02

not to that extent so you can practice, no

1:04

forget the contents and take your

1:06

score to the next level. The video

1:08

It also includes a summary book

1:10

where we summarize each piece of content that

1:12

You'll learn in the video. You contain

1:14

all the questions we're going to use

1:16

and of course the guides too

1:18

cumulative ones that I mentioned to you

1:19

previously. All so that they have the

1:21

better experience, you can print it.

1:23

You can have it digitally and for

1:25

To get it, simply go to the

1:26

video description and we'll go with

1:28

all to raise that score. All the

1:30

For years we have had the custom of

1:31

publish this summary and until the year

1:33

In the past we had always published

1:34

math summaries, but this year

1:36

We incorporated all the Prebo M30M

1:39

subjects, so if in this video

1:41

We reached 10,000 likes, let's go

1:43

lead a summary like this for

1:46

each subject, biology, physics, chemistry,

1:49

history, reading comprehension and, therefore

1:51

assumed, M2. Before we begin with the

1:53

In summary, I want to leave you with the following:

1:55

invitation, and it is that in the month of

1:57

In November we will carry out the

1:59

largest ultra-intensive that has been

2:02

Made in Chile to prepare for the test.

2:04

We are going to carry out this ultra-intensive course.

2:06

from November 17th to 30th and

2:09

It is designed so that if you, for

2:11

For example, if you want to save the test,

2:13

you can do. If you want to maximize your

2:15

performance in those two weeks, the

2:17

you can achieve. And of course, if

2:19

you want to fine-tune the final details for

2:21

To get 1000 points, we're going to work for

2:23

to reach this national level. And just in case you're wondering

2:25

You asked, of course, we're going to have

2:27

all subjects in this intensive course.

2:30

Registration opens on Monday, the 3rd.

2:31

November, so if it's that date or

2:34

After that, you can register and

2:36

We're going to work hard so that

2:38

you can upload your score to the next one

2:39

level and stay in that race of your

2:42

dreams. The ultra-intensive has a

2:44

price of $30,000 and obviously you're going to

2:46

You will be able to register and you will be able to access

2:48

all the contents of the test and

2:50

We're going to take that score to the maximum.

2:52

Finally, I want to wish you much success.

2:54

in your preparation. I know it's a summary

2:56

12 hours and suddenly you can see

2:58

It's a huge challenge, but I want to

3:01

Be disciplined, be

3:03

disciplined, that you don't give up, and that

3:04

work towards achieving that goal, that

3:07

dream you have. I know you're going to achieve it

3:08

That score, I know you're going to get that

3:10

career and that you will fulfill each one of

3:12

your dreams, so I wish you much

3:14

success. And as we always say at M30N,

3:17

We're going to go all out, you're going to catch up.

3:20

that goal.

3:22

And we begin with whole numbers.

3:26

First, let's remember what

3:29

These are the natural numbers.

3:32

Natural numbers are those that

3:34

They allow us to count elements of certain

3:38

sets. They are numbers like one, the

3:40

two, the 3, the cu, the 5, the 6, the 7, the

3:43

8, 9, and 10, and so on.

3:46

Now, what is the set of the

3:49

whole numbers?

3:52

The set of integers is

3:55

composed of the natural elements,

3:59

their additive inverses, which we will now discuss

4:02

Let's see in a few minutes, and zero. All

4:07

This is the set of numbers

4:11

wholes.

4:13

Now I mentioned something to you about the

4:15

additive inverse, which is also

4:18

known as the opposite. Look, in

4:21

In very simple words, the reverse

4:25

additive of an integer is

4:27

simply the number, but with the

4:29

opposite sign. I changed the sign no

4:32

further. As a general rule, if you have a

4:35

integer n,

4:38

You can represent its additive inverse

4:42

as - n. And something very, very important,

4:47

I want you to write this down. When I add one

4:51

number with its additive inverse, the

4:55

The result of that operation will be

4:58

zero. Now I want us to look at this in

5:02

Spanish and let's look at some examples. Look,

5:05

Let's suppose you have these numbers and

5:08

you want to see their additive inverses. As

5:10

I told you, it's just a matter of changing.

5:12

the sign. So, if I have here the

5:15

8, its inverse. Ah, I see. -8, it

5:19

We have it ready. 3, its additive inverse,

5:22

-3. We're ready. And what do we have here?

5:27

The -2. What do we do when this question arises?

5:29

Is it negative yet? simple. As we said,

5:33

We changed the sign. So, the

5:35

The additive inverse of -2 is simply

5:39

2. And now we have it ready. So, this

5:43

of the additive inverse is only

5:46

change the sign. Now, something very

5:49

Important, if you add a number to its

5:51

additive inverse, as I told you, the

5:53

The result will always be zero. If you

5:57

You add up each of these numbers, always

6:00

The result will be zero.

6:06

Remember that whole numbers are

6:08

can be represented on the number line,

6:11

where in the middle of this will be located the

6:15

zero. To the right of zero will be

6:18

the numbers that are positive and the

6:22

To the left of zero will be the

6:24

negative numbers.

6:27

Remember that zero is not positive.

6:31

neither negative.

6:33

A very important factor that you must

6:36

Remember, and I ask you to notice, that...

6:39

the further to the right it is

6:42

a number on the number line,

6:45

the greater its value will be. For example, I

6:49

I know that 5 is a number that is greater than

6:54

4, since the 5th is further to the

6:58

right. Similarly, if I, for

7:01

For example, I put -3

7:07

And I also have -4, I know that -3 is going to

7:12

be a larger number, since it is more a

7:15

the right.

7:16

That rule is very important that the

7:19

keep this in mind, since in the test you

7:22

They're going to ask to compare whole numbers and

7:24

If you keep that in mind, you'll never...

7:27

to be wrong.

7:29

And with the little material we've seen

7:30

So far, I want us to resolve

7:32

our first question, PES, of this

7:35

summary. Let's begin. How many numbers

7:39

positive integers are greater than or equal to

7:43

that -4

7:45

and younger than 3? Already. To solve this

7:49

Question, I will use the number line

7:51

that we had here. We're going to copy it,

7:55

Let's stick it here and get started.

8:01

Information always stands out

8:03

important. Look, they have to be numbers.

8:06

wholes.

8:07

positive.

8:09

Already. Which ones are positive?

8:12

This, this, this, this and this. And so

8:16

successively, right? All the

8:18

We ruled out the negative ones, and also the

8:21

zero.

8:23

Now they must be greater than or equal to

8:27

-4. All positive numbers fulfill the condition.

8:30

This condition, so we're doing well. But

8:34

They must be less than three. Therefore

8:38

Therefore, five is not useful to us, four

8:41

Neither, and not three either. It must be

8:45

less than three. Therefore, they are useful to us

8:48

only

8:50

these two little numbers we have here.

8:55

Therefore, the correct alternative is

8:58

The letter A. There are only two numbers

9:02

that meet these conditions.

9:05

And with this, with the little bit of material that

9:07

We have seen so far, we have resolved

9:09

our first question. PES.

9:12

We're going to work 100% so that you can

9:15

answer each question that appears in

9:16

take the test and raise your score. That this

9:19

Let it be a small test of what you are going to

9:22

to achieve and we will continue working to

9:25

that score, as I told you, reaches

9:28

maximum. Now we're going to remember two

9:31

very important concepts in numbers

9:34

wholes, which are the successor and the

9:38

predecessor.

9:40

Let's start with the first one. The successor of

9:44

An integer is the largest integer plus

9:48

close to this on the number line. Is

9:51

the one that is immediately after the

9:54

right. Look, for example, at number two. You

9:59

You see number two and we're going to see its successor, which

10:03

It is the one that comes immediately after

10:07

the right of this. In this case, the

10:10

The successor of two is simply three.

10:14

Now, what would happen, for example, if I

10:17

I want to see the successor to -4?

10:21

Which one would it be? You ask yourself, what is

10:24

the whole number that is to the right of this

10:26

on the number line? Ah, I see. Perfect.

10:29

It is -3 and this is its successor.

10:36

It is very important that you keep in mind

10:38

that the successor of an integer

10:40

It will always be greater than the number

10:41

original. And if you want to represent a

10:45

successor of an integer n, say,

10:49

I have an integer n, the successor

10:52

It will always be given by n + 1. And with

10:58

You'll always be able to represent that.

11:01

Look, for example, if I have the

11:03

Four, the successor to four will be 4

11:08

+ 1, which is 5, and there you get it.

11:14

Now, what about the predecessor of

11:18

a number

11:20

whole?

11:21

The predecessor of an integer is the

11:24

nearest smaller integer to this in the

11:27

number line. is the whole that is

11:30

immediately before to the left of

11:33

this. Look, for example, if I have the

11:36

two,

11:41

His predecessor will be one, which is this one

11:44

that we have here. If I have -2, then...

11:50

The previous one will be here on the left,

11:52

which is going to be -3.

11:56

It is very important that you keep in mind

11:58

that the predecessor of an integer

12:01

It will always be less than the number

12:03

original.

12:05

So, if I want to represent now

12:08

the predecessor of an integer,

12:10

Let's say an integer n, we will always

12:14

obtain by taking n and subtracting one. By

12:18

For example, if I want to extract the predecessor

12:21

of four,

12:23

The predecessor of 4 will always be 4 -

12:27

1, which is 3, which if you look closely is the one that

12:30

It's to the left of this one on the straight

12:33

numerical.

12:35

Now let's look at what numbers are

12:38

consecutive integers. This is good

12:40

simple. Whole numbers

12:42

consecutive integers are integers that come one after the other.

12:45

one after the other on the number line. By

12:49

For example, one and two are numbers

12:52

consecutive integers, since they come one

12:55

one after the other on the straightaway. Now, if I

12:57

Here I add the three, it would have three whole numbers

13:00

consecutive. If I add the four,

13:03

would have four whole numbers

13:04

consecutive. And likewise if I add the

13:08

five. I have five whole ones here.

13:12

consecutive.

13:14

I could even add zero here.

13:17

Here I would have 1 2 3 4 5 6 integers

13:21

consecutive. And that's the characteristic

13:25

that whole numbers have

13:27

consecutive. They come one after the other.

13:30

Now, very importantly, always keep in mind

13:33

He says that when I have two numbers

13:35

consecutive integers,

13:37

These will differ in one

13:40

unit. Between 0 and 1 there is one unit

13:43

distance. Between one and two there is

13:47

a unit of distance. Between two and

13:49

There is one unit of distance in three. AND

13:51

and so on.

13:54

Now let's see how to represent

13:57

consecutive whole numbers.

14:00

Now, what am I referring to by

14:02

represent writing with numbers and

14:06

lyrics what we say with

14:09

words? In this case, for example,

14:11

Suppose a statement tells you,

14:14

"Hey, I want you to act out three

14:17

consecutive integers."

14:19

So, how could we do it? Look, in

14:21

First, we are working with

14:23

our whole numbers and I'm going to say

14:25

as follows. I'm going to have a number soon

14:29

whole n that will speak for all the

14:32

wholes. This integer n will be the

14:35

representative of all numbers

14:37

whole, of this, of this, of this, of

14:40

any.

14:41

So, what's the key here?

14:45

Remember the definition. Ah, I see.

14:46

Perfect. Look, whole numbers

14:48

consecutive ones come one after the other.

14:51

Therefore, the one that comes after n

14:54

+1, right? We saw that we were going

14:57

increasing by one unit. And if I want to

15:00

another whole one, to this one I had here

15:04

I can add one and I have n + 2. Why?

15:08

n + 2? Because you added one unit here.

15:12

In the same way you did it here.

15:15

So, in this way we have

15:18

represented

15:22

three consecutive integers and this works

15:25

for all cases. Because? Because

15:28

You can put any value here

15:30

a n. Look, let's suppose you put it on,

15:33

I'm going to save here, let's suppose that he

15:35

you place

15:37

one, to give you an example. Already. So,

15:39

Here I would have one, here I would have 1 + 1, and here

15:44

I would have 1 + 2. And look, I have 1, I have

15:49

two and I have here the three and which are

15:52

precisely three whole numbers

15:56

consecutive.

15:58

And in this way one represents those

16:01

consecutive whole numbers. I'll do it to you

16:03

I have a question, and I want you to pause here.

16:06

video and you say it. Which one would come

16:09

being the integer that comes after n

16:13

+ 2?

16:16

We add 1 and it becomes n + 3. And here,

16:22

How many consecutive integers?

16:24

Would it have?

16:26

You tell me. There are four of them, right? And from that

16:30

We are representing the numbers in this way.

16:33

consecutive integers.

16:36

Many times you will come across

16:38

exercises where little things appear

16:40

how are you. Let's suppose it appears to you in

16:43

the three between two bars, or let's say the

16:49

-4

16:50

between two bars. Rapier

16:53

means? that you're going to have to calculate

16:55

its absolute value. But what is it?

16:59

absolute value?

17:01

The absolute value of a number is the

17:03

distance between that number and zero

17:06

on the number line.

17:09

Since it is a distance, it will always be either

17:12

positive or zero, but never negative.

17:18

So, let's suppose I want

17:19

calculate the absolute value of 3.

17:25

I wonder, hey, how far away is it

17:27

Find the three from zero on the number line

17:29

numerical? I'll count one, two, three

17:34

units. Ah, yes, perfect.

17:35

Simply three.

17:38

Now I have the absolute value of -4.

17:42

How do we do this? Again we

17:44

we asked. We are already located here in

17:47

-4. How far away am I from the

17:50

zero on the number line? Come on

17:52

counting.

17:54

1, 2, 3 and four units. Therefore, his

17:59

The absolute value is four. So,

18:03

remember that whenever you find yourself

18:06

a number between two bars,

18:07

Let's assume a number n, you are

18:10

calculating its absolute value here. Yeah, one

18:14

Last example, I want you to solve it

18:16

you. What is the absolute value of -3?

18:22

You've got it. I'll do it. Now

18:25

I have -3. Let's keep counting. 1 2 3 units

18:31

to get to zero and we already have it

18:35

list.

18:37

It's important that you remember the value

18:39

positional in integers, already

18:42

which is something that has been asked with

18:44

frequency in the test. Remember that

18:47

We use the decimal base because

18:49

We represent all numbers with 10

18:52

different digits, from 0 to 9. In this

18:56

base, the value of each digit depends on

18:59

assumption. Look, let's see the first one.

19:01

number. Here we have the 345.

19:05

Let's note that here we find the

19:07

Hundred, here the ten, and here the unit.

19:11

Therefore, we can rewrite

19:13

this number in the following way. As

19:16

We have a three in the hundred, this

19:18

This is equivalent to having 3 * 100. To this

19:23

Let's add, since we have a 4 in the

19:27

tens, this is going to be 4 * 10. And here

19:32

We have a five in the unit, therefore

19:34

We add 5 per unit. 1. Let's look at another one.

19:39

example. Here we have number 1234.

19:43

Here we have the 1000 unit, the

19:46

hundred, ten, and one. Therefore

19:50

Therefore, we could rewrite it from the

19:51

as follows. I have one in the unit

19:55

out of 1000, therefore it is 1 * 1000 more I have

20:00

a 2 in the hundreds place, 2 * 100 plus a 3 in

20:06

the ten, 3 * 10 plus a 4 in the unit,

20:13

It's a 4 * 1. And that's how we have

20:17

rewritten this value, which as I told you

20:21

It's something that has been asked in the

20:23

proof. Now let's move on to the next one,

20:25

with 102. Here we have hundreds, tens,

20:30

unit. This is the same as 1 per

20:33

Hundreds, 100 plus the tens digit 0. This is 0

20:37

* 10 plus the unit which is 2 * 1 and of that

20:42

We have rewritten this value. Such

20:46

Once in the test they could reach

20:49

ask

20:51

by a negative number. And here

20:53

Simply put, the only thing that changes is the

20:56

The sign that goes before, indicating that it is

20:58

a number that is below zero in the

21:00

number line or to the left of zero

21:03

on the number line.

21:05

So, how do we rewrite

21:07

This value? According to what we have seen.

21:10

Simple. For example, at -256

21:14

You're going to put less and you're going to open one

21:16

parenthesis. So how do we leave it? Look,

21:19

I have hundreds 2 is 2 * 100 plus tens 5

21:26

* 10 plus unit 6, 6 * 1 and we have it

21:32

ready. And in this way we have

21:34

rewritten this value. Keep in mind that

21:37

This is something that has been asked in

21:38

the test, although they involve powers.

21:41

We'll see this later in the

21:43

powers and there we'll see how it

21:45

we rewrote using mainly

21:47

Powers of 10. But that's material

21:51

which comes later. Now we'll see

21:54

operations on integers.

21:56

We will remember the fundamentals of addition

21:58

subtraction, multiplication, and division. AND

22:01

Let's start with the addition of integers.

22:05

Okay, let's start with case number

22:08

one. When we add two numbers

22:11

of the same sign, the rule is the

22:14

following. The values ​​are added together

22:17

absolutes and the common sign is maintained.

22:21

For example, here we have the sum of two

22:23

Positive numbers, 7 and 5. 7 + 5 is 12. And

22:30

We have it ready. But what happens when

22:32

Add negatives? Well, seeing that

22:35

We are in the case of adding numbers of

22:37

same sign, we know that if I add two

22:39

negative, the result will be a

22:41

negative number. But how much?

22:44

Simple. I see the absolute value of -3,

22:47

how much is it? It is 3. The absolute value of

22:51

-7 is 7. So, I add 3 + 7.

22:58

Therefore, I'm going to give it a 10. And

23:01

Remember that we left you the least because

23:04

we keep the sign that both have

23:07

numbers.

23:10

Now, what happens when we add numbers?

23:13

of different signs? Usually this

23:16

We also do the process in a more

23:18

intuitive, so to speak. However,

23:21

Here I'm going to teach you the logic that

23:22

We're still following. Already? Well, firstly

23:25

In this place, the absolute values ​​are subtracted.

23:28

You subtract the smaller from the larger one and you get

23:32

retain the sign of the larger number

23:35

absolute value.

23:37

So let's suppose that I'm going to

23:40

I have -5 and I'm going to add 2. What is

23:44

Logic? I'm already wondering, what is it?

23:46

What is the absolute value of -5? Perfect, it's a 5.

23:52

What is the absolute value of 2? It's two.

23:56

So, we have everything ready for

23:59

solve the exercise. Well, like

24:02

We indicate here, we subtract the values

24:05

absolutes. The biggest one is the rest

24:07

smaller. 5 - 2 is 3 and the

24:14

sign of the number with the highest value

24:16

absolute. In this case, the highest value

24:19

absolute is 5 and corresponds to the number

24:22

-5. Therefore, we keep the sign

24:26

From that -5 and we have it ready.

24:29

We usually do this process by

24:31

in a more mechanical, automatic way, by

24:34

So to speak. However, it's never okay.

24:37

more to remember. And well, here we have the

24:40

sum of 10 and -4. We're still in the same situation.

24:44

logic. I already have the 10, its value

24:47

The absolute value is 10. I have -4, its value

24:50

Absolute is 4. Perfect. Here we subtract

24:54

absolute values. 10 - 4 is 6. And

25:00

we keep the sign of the number that

25:01

has a greater absolute value than in this

25:03

In this case, the largest absolute value is 10 and

25:06

It corresponds to 10. Therefore, we keep

25:09

a positive sign, although it is not

25:11

It is necessary to write it. Simply

25:13

number six remains.

25:16

Now we are going to remember something very

25:18

important about subtraction.

25:21

Suppose I have the subtraction between

25:23

two integers A and B in that order,

25:28

where it is remembered that A is the minuend and B

25:32

is the subtrahend. I want you to remember

25:35

This is fundamental because...

25:37

They might suddenly ask you about it in the

25:38

proof. Remember that if I have the

25:41

subtracting a from b, this is equivalent to

25:47

add A to the additive inverse of B.

25:54

Look, I know that with letters it can be seen very

25:57

complex, therefore, let's look at some here

25:59

examples. Now let's look at the examples.

26:03

We have 5-10. This is very likely the

26:07

can solve it mentally, but if

26:09

That's not the case, I'm going to show you properly the

26:12

logic of how to do it with the

26:14

principles we have learned. Already

26:16

We have 5-10. Remember then that the

26:20

Subtraction can be rewritten as addition

26:22

and we already know the principles of

26:24

the sum. So, look, I'm going to

26:27

rewrite this as a 5 plus the inverse

26:31

additive of 10, which is -10. And look, here

26:36

I have a sum of two integers of

26:39

different signs. I see its value

26:41

absolute. Here it's 5, here it's 10. The rest

26:46

absolute values. The greatest one

26:48

the smallest rest. 10 - 5 is 5. And

26:53

I keep the sign of the number that has

26:56

the largest absolute value, in this case the

27:00

-10. And we've solved it. Let's go with the

27:04

following. Look, here I have a -4 - 3.

27:09

I'm going to rewrite it as a sum. This is

27:12

-4

27:14

further. And here I'm going to take the reverse.

27:18

additive of 3, which is -3. Today I have here

27:22

a sum of two numbers with the same sign,

27:25

two negatives, therefore, I keep the

27:27

negative. We extract their absolute values.

27:30

This is 4. This is 3. 4 + 3 = 7 and the

27:35

We have a list. The result is -7.

27:39

Now, what happens next?

27:41

example? We have here 2 - -3.

27:47

So, this is going to be 2 + the inverse

27:52

The additive product of -3 is 3. Therefore, +3 is

27:59

5. And now it's ready. Having seen

28:04

The subtraction, now I want us to remember

28:07

Something very important, which is distance.

28:10

on the number line. This is the question and

28:13

frequently and I want you to please

28:16

Write this down too because it's very important.

28:18

You need to keep that in mind.

28:21

Often they'll give you two numbers in

28:23

the number line. For example,

28:25

Let's say they give you the 3 and they give you the

28:29

-4. And they ask you, "Hey, what's the

28:33

distance between these two numbers and what

28:35

What are you going to do to be able to calculate the

28:38

distance?" Simple. Always. to the number

28:42

elderly,

28:44

You're going to subtract the smallest one in that order.

28:49

That way you'll always be able to get

28:51

the distance.

28:53

So here the oldest is the one who is most

28:56

to the right. We subtract the three

29:00

smaller, which is -4.

29:05

This is equivalent to having 3 plus the

29:11

additive inverse of -4, which is 4 and 3 + 4

29:18

It is 7. Therefore, this is the distance

29:22

between those values. Now it too

29:25

You can see it on the number line. Look,

29:27

Let's keep counting.

29:29

Of the three. I need to move. One, two, three,

29:33

4, 5, 6, seven units to reach the

29:38

-4. But so I don't have to walk

29:40

counting, simply the oldest

29:43

subtract the smaller one. As a piece of advice,

29:47

whenever you calculate the distance,

29:49

Be careful with the signs, because it is the

29:52

most common mistake that is usually

29:55

commit. You have to be organized or

29:58

organized so you don't make a mistake. And the

30:00

You're going to have a good question. Now

30:03

I want us to look at something very important

30:05

which is the sum on the number line.

30:08

Note that this will also apply

30:10

for subtraction, since you can subtraction

30:12

receive as a sum so that you have it in

30:15

account. Look, let's suppose I have the

30:18

Number two and I add three units, I

30:25

I add three. You know that the result of

30:27

This is five. But I want you to have in

30:30

It says the following. If I place myself in

30:33

a number, for example, two, and it

30:35

I add a positive number, which I will

30:39

What to do is move to the right in

30:42

as many units as the value

30:45

absolute of said value. So, in

30:49

In this case, I have to move three

30:51

units to the right. Story 1, two and

30:56

three and we arrive precisely at five.

31:01

Now, what happens when we add

31:04

a negative number? For example, at two

31:06

We're going to add -4.

31:10

What's going on? What's happening here

31:13

When we add a negative number, it means we...

31:16

Let's move to the left. in

31:19

Indicate the value in as many units as indicated.

31:22

absolute of said value. For example,

31:25

We have here the 2. The absolute value of

31:30

-4 is 4. Therefore, we're going to move here.

31:35

four units to the left.

31:38

We counted 1, 2, 3 and 4 and arrived at -2,

31:45

which is the result of this operation.

31:48

Why am I telling you this is so, so

31:51

important? Because it is asked in the

31:54

proof. Look, let's look at this question.

31:58

And it says: "Consider the following

32:01

number line. Which of the following

32:04

procedures represents the operation

32:07

-5 + -8 using the number line? Already

32:12

Let's read the alternatives. To position oneself in the

32:16

-5.

32:18

Already. And travel in eight units to the

32:23

left. And this is indeed going to be

32:26

So, if we place ourselves at -5 and...

32:30

In this case, we add the negative -8, we

32:33

Let's move to the left, since it's

32:36

a negative number, and we're going to move

32:39

units, since it is the absolute value of

32:41

-8. Therefore, the correct one is letter A.

32:46

In fact, you represented everything

32:48

You could do this on the number line

32:51

do it in the following way. Tea

32:53

You were located here at -5. You know that

32:55

The result of this operation is -13.

32:59

And here to get to this -13 that will

33:02

to be further to the left on the straight

33:04

Numerically, we had to move eight

33:07

units to the left

33:11

And that's how we arrived at the result

33:15

of the operation. Now let's see how

33:18

solve operations like these when

33:21

we have a series of pure sums and

33:24

subtractions.

33:25

Well, there are different ways, but

33:28

I want you to consider something

33:30

fundamental

33:32

And that's because addition and subtraction have the

33:35

same priority. And in case you have

33:39

a series of pure additions and subtractions, the

33:41

The key to solving it is to follow the

33:44

following. You're going to solve them in order.

33:48

And in what order? In order from left to right

33:51

right. It is enough to perform the

33:54

operations in sequence and you will be able to

33:56

to reach the result. If you have already

33:59

trained more, there are ways that are a

34:01

A little faster, but if you're

34:03

newly inverting, there is no

34:04

problem in doing it that way. I only know

34:07

very tidy. Already? So,

34:10

Look, let's solve the sequence.

34:13

1 - 2 is -1.

34:16

To this we add 3 - 4 + 5 - 6 + 7.

34:26

We continue.

34:28

-1

34:29

+ 3, what is that? It's 2. -4

34:34

+ 5 - 6 + 7. We continue. 2 and -4 is -2

34:45

+ 5 - 6 + 7. We continue. -2 + 5

34:54

- 6 + 7 and we're almost there.

34:58

3 - 6 -3 + 7 and -3 + 7 gives us as

35:06

Result 4. And in that way we have

35:10

solved this series of additions and subtractions.

35:15

Here, if you look closely, it was a process that

35:17

It depended a lot on not making a mistake when

35:19

continue rewriting. Therefore, it is a

35:22

valid form, although possibly you

35:24

Perhaps you can solve it in a slightly different way.

35:26

different. And now I'm going to show you another one

35:30

form and you can also reorder

35:32

mentally or in writing the terms

35:36

grouping together everything that is adding up and

35:38

everything that is subtracting. Let's see here

35:43

how to do it. Look, what do we already have?

35:45

Adding that it's positive. Have

35:47

one, we have three, we have

35:50

five and we have seven. So, it

35:54

I'm going to write here. Maybe you will

35:56

Mentally, I'm going to do it

35:57

purely for the purpose of the example. I'm coming

35:59

Write here 1 + 3 + 5 + 7. And here

36:08

I'm going to subtract this and open

36:11

parentheses and I'm going to put it here. Which

36:13

I'm subtracting, I'm subtracting two.

36:15

I'm subtracting five and I'm subtracting

36:18

a six. And I write them just like that, 2, 4

36:24

6. So, what does this equal? 1 + 3, 4

36:30

+ 5, 9 + 7 results in all this,

36:35

16.

36:37

And from this I will subtract the sum that

36:41

We have it here. 2 and 4 6 + 6 12 16 - 12 is =

36:50

4. And in this way we have arrived

36:53

exactly the same result. Ideal

36:57

It's that I do it the way you want me to.

36:59

Choose whatever is most comfortable for you.

37:03

Now we're going to look at mathematical language

37:06

common. Let's suppose we have

37:08

that a number x

37:11

is increased

37:13

in i. If they tell you that, it means that...

37:17

You will add i units to the value of x,

37:21

You're going to add i. Nothing more than that. Without

37:26

However, what if they tell you that a

37:29

number x

37:31

Does it increase? And we're going to highlight this here.

37:34

with red. Increase to and when you

37:39

This appears means that the value

37:43

It will be transformed into i. That is to say,

37:48

We're going to go from having x to transforming it

37:52

in i.

37:54

S means that it transforms it and is

37:57

fundamental because in the questions of

38:00

The test comes out exactly like this.

38:05

Now, let's suppose we now go with

38:07

a decrease. This remains the same

38:10

logic. If I have a number x, it is

38:14

decreased by i, is decreased by i,

38:18

This means that you will subtract i from x,

38:22

nothing more than that. On the other hand, if they tell you

38:26

that a number x is decreased to y this

38:31

a, as I told you before, means

38:33

that is transformed, that is, that

38:36

value changes from x to directly

38:40

Yo. That's the result. Please,

38:44

Keep this little chart.

38:47

Now, if we have, for example,

38:49

the difference between x and y in that order,

38:53

Simply subtract y from x, that's all

38:57

That's it. This is going to be x - i. And in the

39:01

in case the number x is greater than the

39:04

number y and they ask you the excess of x

39:08

about and, they are simply telling you

39:10

asking by how much x exceeds y this is

39:13

calculates only by calculating the

39:16

difference of x - y.

39:20

Nothing more than that.

39:23

In this video we won't see how

39:26

multiply or divide. However, it is

39:28

essential things to keep in mind for the

39:31

multiplication and division the rule of

39:34

the signs. What does the following tell me?

39:37

If I multiply or divide numbers of

39:40

with the same sign, the result will be

39:44

positive. However, if I multiply

39:48

or I divide numbers of different signs, the

39:51

the result will be negative. By

39:54

For example, I could have 5 * 10 here, the

39:58

The result is 50, a positive number. EITHER

40:01

It could have, for example, a -3 * a

40:05

-4. Since they have the same sign, the

40:09

The result will be positive, and in this

40:11

Case number 12. Now, here we have a positive result.

40:15

For example, a negative number could be 5

40:19

* -4 and the result will be -20. Or by

40:25

For example, I could have a -3 * a which is

40:30

-6.

40:32

So, keep in mind that this is

40:33

It works for both multiplication and

40:36

for the division.

40:40

Now we will look at the property of the

40:41

lock. Ownership of the lock

40:44

The integers tell me that if I

40:46

I add, subtract or multiply two numbers

40:49

whole numbers, the result is always different

40:52

whole. For example, if I add 2 + 3,

40:58

This equals 5, which is a number

41:01

whole. If I have 5 - 10, the result

41:06

It is -5, which is an integer. And if by

41:10

For example, I multiply -3 * 5, the result

41:15

It is -15, which is another integer. And you

41:19

You realize that it always seems to give us...

41:20

result is an integer. Always

41:23

when performing addition, subtraction or

41:26

multiplication of two integers, I'm going to

41:28

obtain an integer as a result. And you

41:32

You might ask what happens to the division. AND

41:35

In division, it happens that not always the

41:37

Dividing two integers will give me

41:39

resulting in an integer. Look,

41:42

Let's look at an example. Let's suppose that I

41:44

I divide 2 into 5.

41:47

[Music]

41:51

And this isn't a whole number, it's a

41:54

rational number that we will study further

41:57

forward. Therefore, it holds true for addition,

41:59

subtraction and multiplication.

42:03

a little common language that can

42:05

appear in the exercises. If you

42:07

They ask for the double of a number x,

42:09

This will always be 2 * x. If you

42:12

They're talking about three times a number x, it's 3 *

42:14

x. If they tell you about four times x, it's 4

42:18

* x. The quintuple,

42:20

5 * x. and so on.

42:24

They might also ask you about the

42:26

half of a number x, which is

42:28

simply x divided by 2, or one third

42:32

of x, which is oxide in 3, or 1/4 of x, which

42:36

is oxide in 4, or even a fifth of x

42:40

which is x divided by 5 and so

42:45

successively.

42:47

Now let's remember the papo mudas. He

42:50

papo mudas is an abbreviation that we

42:54

remember the correct order in which

42:56

We must perform the operations.

42:59

First we start with the parentheses,

43:02

then with the powers, then with the

43:04

multiplications and divisions and

43:06

Finally, additions or subtractions

43:11

which would be addition and subtraction.

43:15

Now let's look at some examples so that this...

43:17

Let it be clearer. We have this operation.

43:21

To perform it in the correct order,

43:24

Let's remember the mute papo. What do I

43:26

says? Start with the parentheses.

43:28

Perfect. We start with what we have

43:30

here. We'll end up with 7 - 25 - 21, which is

43:37

4. So here we put 4 * 5 - 3.

43:45

Next, let's talk about powers. There is no

43:48

powers, so we move on to the

43:50

multiplications or divisions. In this

43:53

In this case, we only have one

43:54

multiplication, which is this 4 * 5.

43:59

So

44:01

- 4 * 5 will be 4 * 5 20 - 3. And

44:08

Finally, let's move on to the additions or

44:11

subtractions. In this case, this is what

44:14

same as 7 men

44:17

20 - 3, which is less here 23 and 7 - 23 us

44:24

It will result in -1.

44:28

And we have now solved this exercise.

44:32

Now let's move on to a second exercise that

44:35

It's very interesting. Let's begin

44:38

solving the parentheses as usual.

44:41

We only have one parenthesis,

44:42

then we only place 8 - 4 which

44:47

It's 4 divided by 2. Let's continue. Here, if

44:53

We noticed that there is no

44:55

Therefore, powers must be passed with

44:57

multiplications or divisions. And it is

45:00

It is important that you consider the following.

45:02

If I have a series of pure

45:04

multiplications with divisions,

45:07

Whenever I have to solve it

45:10

do in order from left to right,

45:13

since multiplication and

45:15

divisions have the same priority. AND

45:17

in order to solve the exercise,

45:20

The convention is that this is done in

45:22

left to right.

45:26

So, let's begin. We have here 2 + 9

45:31

* 4 which is 36

45:35

say

45:36

2.

45:38

Now, 2 + 36/

45:42

2

45:44

and 2 + 18.

45:47

And this is the result of this

45:50

operation.

45:52

Now, with what we've learned, let's solve

45:54

some questions. What is the value of

45:57

This operation? Yes, simple. We use the

46:01

We'll talk and resolve what's going on.

46:03

within the parentheses. Here we have

46:05

to solve something. So, we have 1 -

46:11

-3

46:12

multiplied by -2 - 6 which gives us as

46:16

result -8.

46:19

We continue. Here we have one

46:22

multiplication between two numbers

46:24

negative. -3 * -8. The result of this

46:28

It's going to be positive and it's going to be 24.

46:32

So, how is this turning out? He's going to

46:35

be 1 less

46:38

the result of this multiplication

46:42

which is, and I'm going to write it here in red,

46:44

24.

46:47

So

46:50

It is - 23. And the correct one is letter B.

46:58

This was the first question of a

46:59

Try it and we've already solved it. Let's go

47:02

another question. If five times -10 is

47:05

Subtract three times -1, what numbers

47:09

Does it get? Already. What is the quintuplet of

47:13

-10? simple. 5

47:17

* -10

47:20

and 5 * -10 is -50.

47:25

Here, it will be subtracted

47:29

triple of -1. How much is this? 3 *

47:34

-1, which gives you the result

47:38

-36.

47:40

So what are they telling him? A -50

47:45

-50

47:47

it is subtracted, we subtract it

47:52

-36

47:54

And here we have to solve this

47:58

operation.

47:59

Then we'll be left with -50.

48:03

Less is more

48:06

36

48:08

and 50 - 36 is = -14,

48:14

The correct answer is B. Also

48:18

You could propose this exercise

48:20

I'll leave it as an alternative.

48:22

so that you keep in mind that always

48:24

There are different ways you can do it

48:26

you can suggest. You could directly

48:29

arrive and place the operation. Look,

48:31

quintuple of -10 5 * -10 is subtracted

48:37

subtract three times -1. The triple 3 * -1

48:44

and here

48:46

5 * -10 is -50

48:50

- 3 * -1

48:55

3 * -1 is = -36.

49:00

And if you look closely, you arrive exactly

49:03

to the same operation. Do you realize that

49:07

Is it exactly the same?

49:10

Therefore, -50 - men is +36

49:16

and -50 + 36 is -14 and you arrive exactly

49:22

to the same result. Now we're going to

49:25

remember what even numbers are and

49:27

odd numbers. Even numbers are integers

49:31

that can be divided exactly by

49:35

two, that is, when performing the

49:37

division leaves no remainder or the remainder is

49:40

zero. Any whole number ending in 0 2 4 6

49:48

u 8 is an even number.

49:52

An even number can always be written

49:55

such as 2 times an integer n. In fact,

50:00

This is how to represent a

50:03

even number.

50:05

So, let's look at some examples. Look,

50:08

I believe that 12 is an even number.

50:13

Because? Because it ends in two, which is

50:16

one of the conditions we saw.

50:18

For example, the 126

50:23

It is also an even number, and so is it.

50:26

You have to consider something very

50:28

important, and that is that whole numbers

50:31

Negatives can also be even or

50:33

odd numbers. For example, -1

50:37

It is an even number because it ends in 2.

50:41

-14 too.

50:43

Now, what about zero?

50:47

Remember, the number 0 is also a number.

50:51

even, therefore, zero is even. Now,

50:55

Another important thing, all of these being

50:59

Even numbers can be rewritten

51:02

always as the product between two and one

51:04

whole. For example, 12 is 2 * 6,

51:09

the 126

51:11

It's a 2*

51:14

63.

51:16

Well, that's it. Now, look,

51:19

-12 is the same as an integer 2 * 1,

51:22

which is -6 and -14 is 2 * -7. From the

51:29

Similarly, 0 is 2 * 0. And you

51:32

You notice that you can find each even number

51:34

rewrite as the product between two and

51:36

an entire. Now let's look at the numbers.

51:39

odd numbers. And these are whole numbers that

51:42

cannot be divided exactly by

51:45

two.

51:46

In other words, the rest is different from

51:47

zero when performing the division.

51:50

Any integer ending in 1, 3, 5,

51:53

7 or 9 is odd. An odd number is always

51:59

can be written as 2 * n + 1, where

52:04

n is an integer. Let's look at some examples.

52:07

of odd numbers. For example, the 19th.

52:12

Why do they end up nine?

52:14

They end on the 27th if the 21st

52:20

They can also be negative numbers.

52:22

For example, -15 is an odd number.

52:29

Now, another important thing, as you

52:31

I said, you can always represent or

52:33

rewrite it this way as 2 * 1

52:36

integer + 1. In this case, 19 is 2 *

52:40

9, which is 18 + 1, 19. The 27th

52:45

* 13 + 1 2 * 13 26 + 1 27

52:52

* 10 + 1 2 * 10 20 + 1 21 And in the case

52:58

It's a little more difficult to do from -15

53:00

to the eye, but in reality it also

53:03

It can because it's an odd number.

53:05

in that way. In this case it's 2 * -8

53:10

+ 1. Look, 2 * -8 -1 + 1 gives us as

53:16

result -15.

53:19

Therefore, every odd number is always

53:22

can be rewritten or can be represented

53:25

like 2 * 1 whole + 1. Now let's

53:30

learn what even numbers are and

53:33

consecutive odd numbers.

53:36

Consecutive even numbers are even numbers

53:40

that come one after the other on the straightaway

53:43

numerical. For example, the number zero and the number two.

53:47

are consecutive even numbers, since

53:50

They come one after the other on the straightaway

53:52

numerical. Again, they are even numbers.

53:55

that come one after the other on the straightaway

53:57

numerical. If I, for example, add the

54:00

Four, here I would have three pairs

54:03

consecutive. If I add -2, I would have

54:07

four consecutive pairs and so on

54:10

successively.

54:12

I want you to realize something, and it is

54:14

that they will always be separated by

54:16

two units of distance.

54:20

There will always be two units of

54:24

distance between them.

54:27

Now, how do we represent

54:30

consecutive even numbers? Simple, no.

54:33

It's as complex as it seems. Look,

54:36

Remember that any even number you

54:39

You can write it as 2 * an integer n,

54:43

TRUE? And as you know, it's

54:46

They differ by two units, it is enough that

54:48

For the next one, you add 2 * n

54:54

two units and in this way you have

54:58

two consecutive pairs represented.

55:02

Let's suppose you now want another one

55:05

simple.

55:06

To this last one we will add two

55:09

units because we know we're going in twos

55:11

in two. So, we add 2 to this and

55:15

We are left with 2n² + 2 = 4. And so

55:20

successively.

55:22

In this case we would have 1, 2, 3 pairs

55:26

consecutive and this is the way to

55:29

represent them.

55:31

Now,

55:33

with consecutive odd numbers is

55:35

exactly the same logic. Look, the

55:40

consecutive odd numbers are odd numbers that

55:42

They come one after the other on the straightaway

55:45

numerical. For example, one and three

55:48

They are consecutive odd numbers, since they come

55:51

They are odd numbers that come one after the other

55:52

the number line. And in the same way,

55:55

If I add five, I would have three

55:57

consecutive odd numbers. If I add -1,

56:00

would have four consecutive odd numbers and

56:02

and so on.

56:05

Now, how do we represent them?

56:08

The same logic. I want you to notice that

56:10

Here we go two by two. Do you realize?

56:14

Let's go in pairs

56:17

units, two at a time, right? By

56:21

Therefore, it is enough to simply place your

56:24

odd number, which in this case you

56:27

You represent it as 2 times an integer n + 1,

56:30

which is what we saw earlier.

56:33

And depending on how many you want to represent,

56:35

You add two units. Let's suppose

56:37

that you want to represent three odd numbers

56:39

consecutive. So, to this

56:42

We add 2 and we get 2 * n + 1 + 2 3.

56:48

Here we have

56:50

an odd number too. So, the

56:53

same logic, as we want to add one

56:55

Furthermore, to this we add two units and

56:58

It would be 2 * n 3 + 2 is 5. And here I have

57:04

an odd number, the one that's coming and the

57:08

next, which are three odd ones

57:11

consecutive and that is a form of power

57:15

represent them. Now I ask you

57:17

Next, and I want you to leave it here.

57:19

the comments. What would the

57:23

next odd?

57:26

And how many consecutive odd numbers would it have?

57:29

In this case, the next odd number would come

57:32

being

57:34

2 * n, we add 2 to 5 and it becomes 7. And

57:39

Here we would have 1, 2, 3, four odd numbers

57:43

consecutive.

57:45

To move on to the next content,

57:48

I want you to answer this question.

57:51

What do these numbers have in common with you?

57:54

What do you see here?

57:56

What do you notice?

57:59

Do you realize that each of these

58:01

Are these numbers multiples of three? The 3, 6,

58:04

9, 12, 15, 18, 21. They are all multiples.

58:07

of three. Now, by definition, what

58:11

What's happening here? Any integer that

58:16

If it is a multiple of 3, it will always be possible

58:19

rewrite as 3 times an integer n. In

58:23

In this case, 3 is the result of

58:27

write 3 * 1.

58:30

6 is the result of multiplying 3 *

58:34

2. The 9 3 * 3. The 12 3 * 4. The 15 3 * 5.

58:44

18 is 3 * 6 and finally 21 which is 3

58:49

* 7. And if you notice, it comes true

58:53

that we just said. All the

58:55

Multiples of three can be written as

58:57

that way, like three times one whole.

59:01

Having seen this little one,

59:05

So to speak, spoiler alert, let's see what

59:08

which is a multiple. We say that a

59:11

integer A is a multiple of another

59:14

integer B. If A is the result of

59:17

multiply bun

59:19

whole. For example, in the previous case

59:22

We saw that 18 is a multiple of three,

59:26

since it could be written as 3 * a

59:29

integer n, which in this case is that integer

59:33

It used to be 6.

59:36

So 18 is a multiple of 3.

59:41

Then it leads us to see the following

59:44

questions that are fundamental.

59:46

Is -21 a multiple of 3? Let's respond

59:51

this question. If -21 is a multiple

59:55

of 3, it must be fulfilled that it will be equal to

59:59

3 * 1 integer n. Is there any whole number that I

1:00:04

Will this condition be met? In this

1:00:07

Yes, that's the case, because -7, which is a

1:00:11

whole number, if I multiply it by

1:00:14

3, will give me a result of -21. Therefore,

1:00:17

-21 is indeed a multiple of 3. Now you

1:00:22

I ask the following. Is he a multiple?

1:00:25

of 3? If 0 is a multiple of 3, then it is possible

1:00:29

write as

1:00:32

3 * 1 integer n. So I ask you

1:00:36

Is there any whole number that would allow me to...

1:00:39

Does it meet this condition? And indeed

1:00:42

Yes, because if I replace this n

1:00:45

by a 0,

1:00:47

3 * 0 is 0. Therefore, it is a multiple.

1:00:52

3. In fact, I'm going to tell you that the

1:00:55

cer is a multiple of all numbers

1:00:59

wholes.

1:01:01

Now, 3 is a multiple of 0. If 3 is

1:01:07

A multiple of 0, 3 can be written

1:01:10

as 0 times an integer n. And I ask you

1:01:15

By what integer should I multiply the

1:01:18

Zero so that I get three? And the answer

1:01:21

There isn't one. There is no whole that

1:01:24

fulfill that condition. Therefore, the 3

1:01:28

is not a multiple of zero.

1:01:32

And this is very important. I told you

1:01:36

that zero is a multiple of all

1:01:39

whole, but—and pay attention here—the only one

1:01:44

A multiple of zero is zero. That is, 0

1:01:50

It is a multiple of zero, no other multiple

1:01:56

of cer and is its only multiple since

1:01:59

0 is the same as 0 times an integer n,

1:02:04

where n is any integer. For example,

1:02:05

You could put n * 5 and 0 * 5 here.

1:02:10

0. Therefore, so that it doesn't sound

1:02:12

tangled, I'll say it again and

1:02:14

write it down. Zero is a multiple of all

1:02:18

whole numbers,

1:02:20

But zero has only one multiple that

1:02:25

It's the same zero. Let's suppose that you

1:02:28

Do you want to check what the multiples are?

1:02:31

of an integer. For that, I'm going to

1:02:33

Leave the following note that may

1:02:35

be quite useful. This will serve to

1:02:38

any nonzero integer P. And it is

1:02:42

Simply put, all its multiples will be

1:02:45

These that are in this note that you

1:02:47

let. Look, to make it clearer,

1:02:50

Let's suppose, going back to case 3,

1:02:53

P = a 3 and I want to see all the

1:02:56

multiples. Obviously there are infinite ones

1:02:58

multiples, but I want to write

1:03:00

multiples of three. So I follow this

1:03:02

Point it obviously as far as I want.

1:03:04

write. First we place the

1:03:06

zero. Because? Because zero is

1:03:08

multiple of all integers.

1:03:11

Then we'll add more - 3. What

1:03:16

Does this plus -3 mean? Here it goes

1:03:19

meaning that both -3 and 3 are

1:03:25

Multiples of 3. Now we continue.

1:03:31

We're also going to place

1:03:33

the most - 2 * p, where p = 3.

1:03:40

It's 6. And again, what does he want?

1:03:42

Say this? that both the positive 6 and

1:03:45

-6 are multiples of 3 and so on

1:03:49

successively. 3 * here I would be doing

1:03:51

3 * p which would give us 9, would be more - 9,

1:03:56

both multiples of 3 and continuing here

1:03:59

It would be more - 12 and so on. AND

1:04:03

I'll even add one more here, it would be

1:04:07

plus -5p, which would be plus -5* 3,

1:04:11

which is plus -15 and so

1:04:14

successively. And here, if you look closely, they go

1:04:17

coming out all multiples of 3.

1:04:22

Now, if for example your number P were

1:04:26

equal to zero, because here we are talking

1:04:27

only of non-zero values, it is so

1:04:29

simple. As I told you before,

1:04:33

the only multiple of cer is itself

1:04:37

zero.

1:04:41

Finally, I want to leave you with a little

1:04:43

This note might be quite useful to you in

1:04:45

some exercises. Look, remember that

1:04:48

whenever you add or subtract two multiples

1:04:51

From the same number, the result will be

1:04:54

be a multiple of that number. By

1:04:56

For example, here I'm going to take some of the

1:04:58

multiples of three. Look, I'm going to take a drink here.

1:05:01

The 6 positive and I'm going to take the

1:05:05

-15. Already?

1:05:07

So, if I add 6 to -15, in

1:05:13

In this case, since both are multiples of

1:05:15

3, I will get as a result a

1:05:17

multiple of 3. Look, notice, the

1:05:19

The result of this is -9, which is a multiple

1:05:23

3. Do you realize? So, write it down.

1:05:27

When I add or subtract two multiples of

1:05:30

the same number, the result will be

1:05:34

multiple of that number. Now, it

1:05:38

The same thing will happen for the

1:05:39

multiplication. For example, and here it is

1:05:41

I'm going to do a little more with numbers

1:05:42

small ones. Let's suppose I'm going to

1:05:45

multiply eh

1:05:48

the three with the 12, for example. It's not

1:05:52

the smallest. I said, already with the six.

1:05:54

Already. 3 * 6 = 18. And you realize that 18

1:06:01

It is also a multiple of 3. Therefore,

1:06:03

This also applies in the

1:06:05

multiplication. Write it down here. When

1:06:08

I multiply two multiples of the same

1:06:11

number, the result will be a multiple

1:06:14

of that number. It's quite a point

1:06:16

useful for certain types of questions and

1:06:19

I want you to keep that in mind. Before

1:06:22

Moving on to the next concept, I want you to

1:06:24

Let's make two divisions. Look, let's suppose

1:06:28

that we are going to divide the number 135

1:06:34

in 5. Now, to carry out the division

1:06:37

We do as usual. How many times

1:06:39

Does 5 fit inside 13? It fits twice. 2 *

1:06:43

5 is 10. We subtract 10 and we are left with 13.

1:06:47

- 10 3. And now we go down 5 and we

1:06:52

We ask, how many times does 5 fit into

1:06:55

35? And it fits seven times. So here

1:06:59

5 * 7 35 - 35 remainder 0.

1:07:05

When the remainder of a division is zero,

1:07:10

We say that this division is

1:07:13

Exactly, right? Now, what would happen?

1:07:17

For example, if I had instead of

1:07:19

a 135,

1:07:21

Let's say a 137

1:07:25

and we divide it into 5, we follow the same

1:07:28

logic. How many times does 5 fit into the

1:07:31

13? It fits twice. 2 * 5 = 10, remainder 3.

1:07:36

And now we go down to 7. And how many times

1:07:40

Does 5 fit into 37? It fits seven times. 7

1:07:44

* 5 is 35.

1:07:47

And here, look, we still have a bit left of

1:07:51

two.

1:07:52

However, when the rest of the

1:07:55

division between two integers is different

1:07:58

From scratch, let's say it's a

1:08:01

division that is not exact.

1:08:05

Because? Now let's remember what

1:08:07

means that a number is divisible

1:08:10

on the other hand. Look, if we have two

1:08:12

integers A and B with b not equal to 0, if

1:08:16

We perform the division between a and b and the

1:08:20

The result of this is a whole number,

1:08:23

then we say that a is divisible by

1:08:27

b. It is very important that you have in

1:08:30

account that when a number is divisible

1:08:33

On the other hand, when performing the division we will

1:08:36

to always have to, the rest will be

1:08:38

zero. The rest is zero. How did it happen?

1:08:43

here? For example, in this case 135

1:08:47

is divisible by 5 because the result

1:08:50

It's a whole and we have here that the rest

1:08:53

is zero. However, 137 is not

1:08:56

divisible by 5, since we had a

1:08:59

remainder other than cer. It is very important

1:09:04

also keep in mind that if a

1:09:07

number A is divisible by another number B,

1:09:11

This means that B is a divisor of A.

1:09:16

In this case that we just saw,

1:09:18

We simply had to for the 135

1:09:22

5 was one of its divisors, but not

1:09:25

So with the 137, since it didn't work here.

1:09:29

an exact division.

1:09:33

Now let's look at some examples. The 27th is

1:09:36

divisible by 3. Let's see. If I perform

1:09:40

the division of 27/

1:09:42

3, this will give us exactly a

1:09:46

the whole number will be 9. Therefore,

1:09:48

It is indeed divisible by 3. This

1:09:52

This implies that 3 is a divisor of 27.

1:09:58

Now, 29 is divisible by 5. Let's see.

1:10:03

If I divide 29 by 5, how many times

1:10:08

Does 5 fit into 29? It fits five times and 5

1:10:12

* 5 is 25. Therefore, here we perform

1:10:16

After the subtraction, we are left with a remainder of four and

1:10:19

as we have a remainder of four which is

1:10:23

if not zero, this division is not

1:10:25

exact, therefore it is not divisible by

1:10:30

5.

1:10:31

Now, 0 is divisible by 2. If you

1:10:35

You divide 0 by 2, the result of this goes

1:10:40

to be zero. In this case too

1:10:43

You could write it like this. 0 divided by 2 is

1:10:47

simply 0. Therefore, since it gives you a

1:10:51

whole as a result,

1:10:53

It will indeed be divisible by 2.

1:10:58

Now, let's do it the other way around. 2 is

1:11:01

divisible by 0. If I divide 2 by 0,

1:11:06

Something very important happens here, and that is that

1:11:09

Remember that division by 0 is not

1:11:13

defined. Therefore, since it is not

1:11:16

defined, this is not going to be an integer and

1:11:20

We ruled it out.

1:11:23

Now we're going to review some of the

1:11:26

divisibility rules that will help you

1:11:28

to determine if a number is

1:11:30

divisible by any of these

1:11:32

quickly.

1:11:33

We've already started with the rule of

1:11:35

divisibility by two. If you have a

1:11:38

even number, this even number always,

1:11:41

It will always be divisible by two. By

1:11:44

For example, numbers like 52,

1:11:48

100, 26, or 28 are all

1:11:55

divisible by 2, since they are numbers

1:11:59

peers.

1:12:00

Now, what is the rule of

1:12:02

divisibility by 3? simple. If I

1:12:06

I have an integer and the sum of

1:12:08

all its digits are a multiple of

1:12:11

three, this number will be divisible by

1:12:14

3. For example, if I have the 729

1:12:20

And I add up its digits, I add this one, this one and

1:12:23

I'm going to write this up here. 7 + 2

1:12:27

+ 9. Notice that the result of this

1:12:29

The operation is 18. And since 18 is a multiple

1:12:34

3 will mean that 729 will be

1:12:40

divisible by 3. Another example, 243.

1:12:46

If I add its digits, 2 + 4 + 3, this

1:12:50

It will give us 9 as a result. And being

1:12:54

9 1 multiple of 3, 243

1:12:59

It will be divisible by 3.

1:13:02

Now let's look at the rule of

1:13:04

divisibility by 4. Look, if I have

1:13:07

whose last two digits form a

1:13:10

multiple of four or both are zeros,

1:13:12

I'm going to have to make that whole number

1:13:14

be divisible by four. For example,

1:13:17

If I had the number 264 here,

1:13:21

I see its last two digits. Ah, I see.

1:13:24

It is 64 and 64 is a multiple of four.

1:13:29

Another example, if I have 216,

1:13:33

I look at the last two digits and say,

1:13:35

"Ah, now its last two digits form

1:13:38

The number 16 and 16 is a multiple of 4.

1:13:42

Therefore, this value is divisible by

1:13:44

4." Now, another example, let's suppose the

1:13:48

100. Look, if its last two digits

1:13:52

They are zero, it will also be divisible by

1:13:55

4. And all these numbers fulfill the

1:13:58

condition for being divisible by 4.

1:14:02

Now let's look at the rule of

1:14:03

divisibility by 5, which is good

1:14:06

It makes it easier. Look, if you have a whole and

1:14:08

This integer ends in zero or cco,

1:14:12

It means that the number will be

1:14:14

divisible by 5.co. For example, on the 25th,

1:14:18

the 35th,

1:14:20

the 55

1:14:22

divisible by 5 and also, for example,

1:14:26

100 or also

1:14:30

1000, which is the score that will be

1:14:32

Saar, yes or yes. So, all these

1:14:35

numbers, as they meet the condition of

1:14:36

that end in 0 or cco, will be

1:14:40

divisible by 5. Now let's look at the rule

1:14:45

divisibility by 6. And this has to

1:14:49

fulfill the following. Our number is

1:14:52

Multiple of 2 and 3. Okay, look here

1:14:57

Let's take an example. The 30th. The 30th is

1:15:01

a number that is even, therefore, being

1:15:04

even multiple of 2 and is also a number

1:15:08

which is a multiple of 3. Notice that 30

1:15:13

It is the result of multiplying 3 * 10.

1:15:16

Therefore, being 30, a number that

1:15:20

is both a multiple of 2 and a multiple of

1:15:22

3 will be divisible by 6.

1:15:27

Now, the divisibility rule for 9.

1:15:30

It's simple here. The sum of its digits

1:15:33

is a multiple of nu. Let's look at a

1:15:35

example. Look, the same 729.

1:15:38

The 729, as we saw, if I add up all its

1:15:41

digits, gives 18 and 18 is a multiple of

1:15:47

wildebeest. Therefore, we know right away that this

1:15:49

value is divisible by 9.

1:15:54

And finally, let's look at the rule of

1:15:56

divisibility by 10, which tells me that if

1:15:58

the whole number ends in zero, the

1:15:59

number is divisible by 10. For example,

1:16:02

the 250,

1:16:04

the 500,

1:16:06

100, 100. All these numbers

1:16:11

numbers ending in zero are divisible by 10.

1:16:15

Before concluding this topic of the

1:16:17

divisibility and divisors, I want

1:16:19

that we fill in this next table

1:16:22

together. I want you to pause the video and

1:16:24

try to place all the dividers

1:16:26

positive aspects of these values. It's very

1:16:30

It's important to keep in mind that for

1:16:32

to find the divisors of a number, this

1:16:34

It requires practice, that is, that

1:16:37

Hopefully you have the session beforehand. Without

1:16:39

However, I'm going to do it here too,

1:16:41

But that requires that you have practiced.

1:16:44

Maybe a little bit so you have that

1:16:46

connection there. If you're not going to start building it

1:16:48

as you practice more. So,

1:16:51

Look, I'll go with number 12.

1:16:53

Already. Divisors of 12, divisors

1:16:56

positive. First, let's

1:16:59

place the one. Remember that every number

1:17:02

an integer is divisible by 1.

1:17:06

Subsequently

1:17:07

Number two works for us too, right?

1:17:11

Number three works too, number one works too.

1:17:14

Four, six also works. and also

1:17:18

The same 12 works. I also remember that

1:17:22

every integer other than zero is

1:17:25

divisible by itself.

1:17:29

Now let's move on to the next number, the

1:17:33

18. We are placing subdividers. He

1:17:36

First, the one. The second, the two, the

1:17:40

three. Then comes the six, then comes

1:17:43

the ninth and finally the 18th.

1:17:49

Now let's go to 30. It would be 1 2 3.

1:17:55

Then we have number five. Then we have the

1:17:58

Six, then we'll have 10. We're going to

1:18:04

We'll have the 15th and we'll have the same one here

1:18:09

30. And here we have the divisors

1:18:12

positive out of 30. And now I want you to

1:18:15

Let's solve a question that came up in a

1:18:18

proof. It says, "With respect to the

1:18:21

positive divisors of nu, is correct

1:18:24

to state that there are already positive divisors of

1:18:28

no, we have the one, we have the three and

1:18:33

we have the same nine. So what

1:18:36

What do they tell us about the alternatives? There are two of them,

1:18:39

No? Neither. There are four of them, too. And they are

1:18:43

three and their sum is 13.

1:18:46

Indeed, 1 + 9 10 + 3 is 13.

1:18:50

The letter D is correct. Now let's go

1:18:54

remember what prime numbers are.

1:18:57

Prime numbers are whole numbers

1:18:59

greater than one who only possess

1:19:03

two distinct positive divisors between

1:19:05

Yes, one and themselves. For example, the

1:19:09

two. The number two has the following divisors:

1:19:13

positive to one and to the same two. The three

1:19:17

to one and to the same three.

1:19:20

Five, one, and the same five. And so

1:19:24

successively.

1:19:26

Remember that by definition the number

1:19:29

One is not a prime number. Many times

1:19:32

that mistake is made. And here I want you to

1:19:35

keep this in mind. One is not a number

1:19:39

cousin.

1:19:41

Now let's talk about composite numbers.

1:19:44

Composite numbers are numbers

1:19:47

integers that have more than two divisors

1:19:52

positive.

1:19:54

In this case, for example, the four. He

1:19:57

Four has one as a divisor, it has

1:19:59

as a divisor of two and also has as

1:20:02

divisor to the same four. The number six has

1:20:06

as a divisor of one, two, three and

1:20:10

to the same six. And the number eight, for example,

1:20:13

has as divisors one, two, four and

1:20:17

to the same 8. And if you notice, each one

1:20:21

of these values ​​they have more than two

1:20:24

divisors.

1:20:25

Here I've left you a small table

1:20:28

indicating the numbers, both prime

1:20:32

as compounds, from 1 to 100, where the

1:20:36

The numbers in red are prime numbers.

1:20:39

and the green ones are the composite numbers.

1:20:43

It's also important that you have in

1:20:45

He says that one is neither a cousin nor

1:20:48

compound. Look, one good thing

1:20:51

important, suddenly in questions of

1:20:53

probability they ask you, "Hey, if you

1:20:55

You have a number, I don't know, from 1 to

1:20:57

20, what is the probability that it

1:20:59

"Choose a prime number?" And I'll tell you

1:21:01

I recommend that you always learn the

1:21:04

prime numbers from one up to

1:21:08

Except for number 37, at least it's there.

1:21:12

because they might suddenly appear

1:21:13

questions from those contexts and there you don't

1:21:16

You're going to make a mistake.

1:21:20

Now let's look at the fundamental theorem

1:21:22

from arithmetic, which tells me that everything

1:21:24

an integer greater than one can

1:21:26

to write in a single way like the

1:21:29

product of prime numbers. Let's see now

1:21:34

how to do this process. I'm going to

1:21:36

show two paths. Use the one that best

1:21:38

I'll make it comfortable for you. Look, let's suppose I have

1:21:40

number 72.

1:21:43

I'm going to write number 72 here.

1:21:47

Let's make a little table.

1:21:50

and I'm going to divide it by numbers

1:21:52

cousins ​​to the extent possible. By

1:21:55

For example, I have two, I have three,

1:21:58

I have five, I have seven, and so on

1:22:01

successively.

1:22:03

So, look, let's see. Let's begin

1:22:05

with the two. Is 72 divisible by 2? Yes.

1:22:09

since it is an even number. Therefore,

1:22:12

We divide by 2 and here we will get

1:22:15

36. And I ask myself again, can I

1:22:18

Should we continue dividing by 2? And the answer

1:22:20

Yes, because 36 is an even number.

1:22:24

36/2 is 18. And I'll do it again.

1:22:29

Same question, can I divide 18

1:22:32

in 2? And the answer is yes. By

1:22:35

Therefore, 18/2 is 9. And I'll do it again.

1:22:39

Same question. Is 9 divisible by 2? AND

1:22:43

The answer here is no. Therefore

1:22:46

Therefore, we move on to the next one, the

1:22:48

three. 9 is divisible by 3 and

1:22:52

The answer is yes. 9 div 3 we have left

1:22:56

3. And then I do the same thing again.

1:22:59

ask. 3 is divisible by 3 and the

1:23:02

The answer is yes. We divide by 3 and

1:23:04

We have one left here and we've reached this point.

1:23:09

Therefore, if I multiply all of these

1:23:12

values, 2 * 2 * 2 * 3 * 3, I'm going to

1:23:16

Write here, 2 * 2 * 2 * 3 * 3, this goes

1:23:21

to be exactly equal to 72. Look, here

1:23:25

Getting ahead of myself with the subject, this 2 * 2

1:23:28

* 2 is the same as 2 raised to the power of 3. This

1:23:33

3 * 3 is 3 raised to the power of 2.

1:23:37

And 2, sorry, and 3 raised to the power of 2 is 9 and 8 * 9

1:23:44

es = 72. And we arrive at exactly that

1:23:49

worth. You could also multiply

1:23:52

One by one, there's no problem. Already

1:23:54

We will look at the powers later.

1:23:58

So, here we're going to see the other one

1:24:01

manner. I told you I was going to share with you

1:24:03

two ways, you can do it one

1:24:04

whatever way suits you best. Obviously it goes

1:24:06

It depends on how much you've practiced.

1:24:09

Look, here's another way we can go about it

1:24:11

This is rewriting this 72 of the

1:24:14

as follows. Look, 72 is the

1:24:17

same as a 2 * 36.

1:24:19

Similarly, 36 is the same as

1:24:23

2 *

1:24:25

18. Similarly, 18 is the

1:24:29

same as a 2 * 9. And in the same way

1:24:33

9 is the same as 3 * 3, right?

1:24:39

And then we rewrote it. Obviously not you

1:24:42

I recommend leaving the

1:24:44

multiplications like this, since it is very

1:24:47

It is possible that at the time of writing it

1:24:49

I can pass you a two and you can

1:24:51

to be wrong. Therefore, I recommend you go

1:24:53

leaving it as powers. In this case,

1:24:55

2 * 2 * 2 is 2 raised to the power of 3 and 3 * 3 is

1:24:59

a 3 raised to the power of 2. Don't worry, this

1:25:02

We'll see about that later, so...

1:25:05

Let me tell you, a small spoiler, but here

1:25:07

You already know two different ways to

1:25:09

do it. And in fact, now I want you to

1:25:12

Pause the video and tell me how

1:25:15

120 would remain.

1:25:18

Pause the video, do it yourself, and now...

1:25:21

I develop myself. I'm going to do it now.

1:25:24

using this form we have here.

1:25:27

If you want to do it the other way

1:25:28

No problem. So, 120,

1:25:32

Let's put it here,

1:25:36

120.

1:25:39

and we're going to divide it up. I'm going to...

1:25:42

delete this part

1:25:44

And we're going to use these prime numbers

1:25:47

that we were using before.

1:25:51

Already. So, I'm wondering, is he...

1:25:55

divisible by 2? Yes, because it's a number.

1:25:57

pair. So, this is 60. Then, the 60

1:26:02

is divisible by 2. Yes, therefore, this

1:26:05

It's 30.

1:26:07

30 is divisible by 2. Yes.

1:26:11

because it's an even number and you're left with 15.

1:26:14

Then I can continue dividing by two,

1:26:16

No? Let's move on to the next one. Already. The 15th

1:26:20

It is divisible by 3. Yes, indeed. So

1:26:22

You're left with 5 here, and then the 5 is divisible

1:26:26

by 3 no. Then we moved on to the

1:26:28

following. 5 divisible by 5 and the

1:26:31

The answer is yes. Therefore, 5 say 5 tell

1:26:35

There's 1 left and here are your numbers ready

1:26:38

cousins. You multiply them together, 2 * 2

1:26:42

* 2, which is the same as 2 raised to the power of 3

1:26:46

* 3 * 5. And there we have it ready. AND

1:26:53

We have reached the last part of the subject

1:26:55

of integers, which is the least common,

1:26:57

multiple and greatest common divisor.

1:27:00

Let's start with the first one. The minimum

1:27:03

common multiple of two or more numbers

1:27:05

integers is the smallest positive integer that

1:27:09

is a multiple of those numbers. It is the

1:27:12

smallest multiple that two or

1:27:16

more numbers. Let's see how

1:27:19

An immediate example. The minimum com a

1:27:21

What is a multiple of 6 and 8? Look,

1:27:24

One way you could do this is

1:27:27

start placing the positive multiples that

1:27:30

We have dates for the sixth and the eighth, and we'll see when

1:27:34

We have one in common. For example, already

1:27:37

multiples of six, positive multiples,

1:27:41

the 6th, the 12th, the 18th, the 24th,

1:27:47

30, 36, we have 42, 48 and so on

1:27:54

successively.

1:27:56

Now, positive multiples of 8, the 8,

1:27:59

the 16th,

1:28:01

24, 32, 40, 48 and so on

1:28:08

successively. And here I want you to give yourself

1:28:10

It tells you something, and that is that there are multiples.

1:28:13

what they have in common. Do you realize? But

1:28:15

We're going to look for the minimum, the

1:28:18

smaller. In this case, the multiple

1:28:21

The smallest thing we have in common is the

1:28:24

24.

1:28:26

Therefore, the least common multiple between

1:28:29

These values ​​are 24.

1:28:32

Now, there will also be infinite

1:28:35

multiples that we have in common. By

1:28:37

For example, here we have 48 and there will be

1:28:40

further. However, at the lowest common denominator

1:28:43

multiple one directly searches for the most

1:28:46

little.

1:28:48

Now,

1:28:50

Is this the only way to do it? No,

1:28:53

Obviously, if they have numbers that are more...

1:28:55

larger, more complicated, it can be very

1:28:58

This process is tedious. For some

1:29:00

This process works perfectly for these exercises.

1:29:02

but not for everyone. I would tell you that

1:29:05

The more complex it becomes, the better

1:29:07

Use this second method that I'm going to show you.

1:29:08

show now. Look, what are we going to do?

1:29:12

We're going to place the number six and the

1:29:17

Number eight. And again we're going to call

1:29:19

our prime numbers, two, the

1:29:22

three, five, seven, and so on

1:29:24

successively.

1:29:25

And here's what we'll do:

1:29:27

Look, this is the method. I

1:29:29

I'll ask, are any of these numbers

1:29:32

divisible by 2? If it's divisible, let's go

1:29:35

to divide it. In this case, both are

1:29:38

divisible by two. Therefore, we are going to

1:29:40

Divide 6 into 2 and 8 into two. Here you go

1:29:43

three and here you have four. And now you

1:29:46

You ask the same question again.

1:29:49

Are any of these divisible by two? AND

1:29:52

In this case, four yes, but three

1:29:54

No. But since some are divisible,

1:29:58

We're going to divide. So, what do we do?

1:30:00

Look, we left number three untouched because

1:30:04

It is not divisible by 2, but four is.

1:30:06

We can divide it by 2 and you get two.

1:30:08

TRUE? We divide again by two and

1:30:11

We arrived at these results.

1:30:14

Now I ask myself again, did any of them

1:30:16

Are these numbers divisible by 2? And the

1:30:18

The answer is yes. Therefore, I can

1:30:20

divide by 2 again.

1:30:23

And we've come this far. And the three

1:30:25

We left it intact because it is not divisible.

1:30:28

by 2. Then now that I know that no

1:30:31

I can continue dividing by two, I move on to

1:30:33

three. I can divide three into three and the

1:30:35

The answer is yes. Well, 3 divided by 3

1:30:38

You have 1 left and we're done here. And if

1:30:41

You multiply all these numbers by

1:30:43

Yes, you reached the least common multiple.

1:30:46

Look, 2 * 2 * 2 * 3. 2 * 2 * 2 is 8 * 3

1:30:54

It's 24, which is exactly the number

1:30:57

that we had arrived. Now let's look at another one

1:31:01

example. Here we have the lowest common denominator

1:31:04

A multiple between 2 and 45. I want you to pause.

1:31:07

Watch the video and calculate it yourself.

1:31:10

Yes, I'm going to start putting the

1:31:12

small board. I'll put it here

1:31:15

the 12th

1:31:18

and I put the 45 here.

1:31:21

Therefore, I place my numbers

1:31:23

cousins ​​who are going to help us 2 3 5 7 and

1:31:27

and so on.

1:31:28

Already? Is any of these divisible by

1:31:31

2? The answer is yes. The 12th

1:31:34

There are 6 left and we'll leave this one exactly.

1:31:37

equal.

1:31:39

Now, are any of these divisible by

1:31:41

2? Yes, 6. We divide 6 into 2.

1:31:46

3 remains and 45 remains intact. Now then

1:31:50

We cannot continue dividing by two.

1:31:51

None of these numbers are divisible

1:31:53

times two. Therefore, for the house. We spent

1:31:56

with the three. Are any of these numbers

1:31:58

divisible by three? Yes, well,

1:32:00

Exactly both. If I divide by

1:32:02

three, here's one left for you. We got as far as

1:32:04

Here and here, if we divide by three, we'll get

1:32:06

15 remains. And we can continue dividing

1:32:09

In this case, by 3. 15 is divisible

1:32:12

times 3. Then say 3 is 5. And

1:32:18

We continue.

1:32:19

Already. Look, is 5 divisible by 3? No,

1:32:23

So we'll move on to the next one. The 5 is

1:32:25

divisible by 5, right? So then 5

1:32:28

Divided by 5 is 1. And we're ready. Yeah

1:32:31

You multiply all these values

1:32:35

Now, in this case 2 * 2 * 3 * 3 * 5, 2

1:32:40

* 2 4 3 * 3 9 * 5 4 * 9

1:32:48

* 5 gives us a result of 180

1:32:52

And there it is, ready. If you realize

1:32:55

We could also use the method

1:32:56

I was writing earlier, but here

1:32:59

The numbers were going to increase over time and

1:33:01

larger and you could put a little bit

1:33:03

more complex. And now suppose that

1:33:06

we want to calculate the least common

1:33:08

multiple of three numbers. That

1:33:10

What do we do in this case? I can't wait for

1:33:13

Pause the video and do it yourself because it's

1:33:16

exactly the same logic.

1:33:19

So let's make the table here.

1:33:23

We placed our numbers 24, 32 and 48 and

1:33:28

We placed our friends the numbers

1:33:30

cousins ​​who are going to help us solve

1:33:33

This will be quick.

1:33:35

Already? So,

1:33:37

Are any of these numbers divisible?

1:33:39

x 2? And the answer is yes.

1:33:41

So, 24/2 is 12. 32/2 is 16. 48/

1:33:49

in 2= 24. And we're doing well. Then

1:33:53

is one of these numbers divisible by

1:33:55

two. All. In fact, we divided by 2,

1:33:58

You have 6 left, you have 8 left, and here you have

1:34:00

12. I can continue dividing by two. Yeah.

1:34:04

So here we divide by two, you get

1:34:06

three, you have four left and you have six left. AND

1:34:09

Here, not everything is divisible by 2.

1:34:12

but there are still divisible numbers

1:34:15

by 2. So we divide by two. This

1:34:18

It remains intact. 4 / 2 is 2. 6 / 2 is 3.

1:34:25

Now, here

1:34:28

Let's ask ourselves, can we continue

1:34:30

Dividing by two? Yes, there's one more.

1:34:33

which can be divided by two. In this

1:34:35

In that case, we're going for two. This remains

1:34:37

intact. This gives you 2 divided by 2 1.

1:34:40

We've come this far. 3 divide is not possible,

1:34:43

Therefore, we left it untouched.

1:34:46

Already. So, now we move on to the

1:34:48

Next, and with this one, it's finished.

1:34:51

Both are divisible by three. So

1:34:53

we divide by three. You have one left,

1:34:56

We're finished. You have one left, we're done.

1:34:58

We're ready. We multiply all of this.

1:35:02

That is, I have 1 2 3 4 5 2 2 * 2 * 2 * 2

1:35:08

* 2 * 3. Okay, I already recommend

1:35:11

Leave it as a powerhouse, but that

1:35:13

We'll see later, don't worry.

1:35:15

The same with 2 raised to the power of 5 * 3.

1:35:22

And we multiply this by 3 and 32 * 3

1:35:25

It's 96. Therefore, this is the minimum here.

1:35:29

common multiple.

1:35:31

Now we're going to apply the least common factor

1:35:34

multiple to a question that could

1:35:36

to go out in the test. Look, how

1:35:39

Identify a least common question

1:35:41

multiple in context? The most typical case

1:35:45

It is the following. They tell you there's a certain

1:35:48

an event that occurs periodically and

1:35:51

They tell you that another event is happening

1:35:53

every so often and they ask you when

1:35:56

They will meet again.

1:35:59

In that case you're going to encounter the

1:36:01

a sign that that question is a

1:36:04

least common multiple question as

1:36:07

the one we have here. Let's read it. The

1:36:10

The World Cup is held every 4 years,

1:36:12

while Bad Bunny releases a new

1:36:15

album every 3 years. If both events

1:36:18

occurred simultaneously

1:36:21

In 2022, in what year will they return to

1:36:24

coincide? Yami, do you agree?

1:36:27

with me that the World Cup

1:36:30

Since it occurs every 4 years, it will happen in 4.

1:36:35

years, in 8 years, in 12 years, in 16 years,

1:36:40

in 20 years and so on.

1:36:44

Similarly, Bad's album

1:36:47

Bunny, you know it happens every so often

1:36:50

time, in this case every 3 years. Is

1:36:53

In other words, there will be an album in 3 more years, in

1:36:55

six also, in nine, in 12 and

1:37:00

Let's set it to 15 and so on.

1:37:04

So, what's important here? yes

1:37:09

You realize, here I have only multiples

1:37:12

of four and here I have only multiples of

1:37:16

three. Therefore, since I want to see in what

1:37:18

They're going to meet again this year, I'm going to

1:37:21

find the smallest multiple they have in

1:37:23

common. In this case

1:37:26

It's the 12th. Therefore, they will return in 12 years.

1:37:31

to coincide. And if the events occurred

1:37:35

simultaneously in 2022, I know that if

1:37:39

I add 12 years, we will be in 2034.

1:37:43

where the events will coincide again.

1:37:48

Please note that this question is

1:37:51

it reduced to finding the lowest common denominator

1:37:53

multiple between 4 and 3. Therefore, it

1:37:56

You could do it this way or also

1:37:59

using the table we learned

1:38:01

previously. Both, both ways you

1:38:04

They led to exactly the same result.

1:38:08

Now let's look at the greatest common factor

1:38:10

divider. The greatest common divisor of two

1:38:14

or more integers is the largest integer

1:38:18

positive that exactly divides those

1:38:22

numbers. In other words, it is the largest number

1:38:25

which is a common divisor of those numbers.

1:38:29

Let's look at some examples. Look, the

1:38:33

Find the greatest common divisor of 24 and 36.

1:38:38

I'm going to show a method of how to calculate

1:38:41

This quickly, which is what

1:38:43

we have learned. Look, I'm going to put one

1:38:46

small table with the numbers 24 and 36

1:38:51

and we're going to divide by numbers

1:38:53

cousins ​​following the following way that

1:38:56

I'm going to show you next.

1:38:59

Okay, look, what's the key? Here you

1:39:02

You're going to ask if the numbers I have

1:39:05

I can divide them here. simultaneously

1:39:09

in one of the prime numbers that

1:39:11

We have it here. If that is not possible,

1:39:13

We'll leave it at that. For example,

1:39:16

Can I divide simultaneously?

1:39:18

24 and 36 * 2? And the answer is that

1:39:22

Yeah. We'll have 12 left here, and here we go

1:39:26

to leave 18. Now I ask you,

1:39:30

Can I split again simultaneously?

1:39:33

times two? And the answer is yes.

1:39:36

we can divide by 2 again

1:39:38

simultaneously.

1:39:40

So, 12/2 is 6 and 18/2 is 9. And

1:39:47

Now I wonder, can I go back to

1:39:49

divide simultaneously by 2? And the

1:39:52

The answer is no. Therefore, the two already

1:39:55

We can't use it. Here's the difference from him

1:39:59

minimum with a multiple when we did

1:40:01

the little board. Here we need to verify

1:40:03

that simultaneously, that is, at the same time,

1:40:06

the values ​​can be divided

1:40:08

We have it there. Next up is number three.

1:40:11

We can divide simultaneously by three

1:40:14

And the answer is yes. We divide by

1:40:16

three, you have two left and you have three left. AND

1:40:19

I want you to pay attention to the following. Here

1:40:22

we can no longer divide simultaneously

1:40:25

by three, nor by any cousin

1:40:27

elderly. Therefore, we'll leave it here.

1:40:32

Nothing more than that. Therefore, that's enough

1:40:35

by multiplying these values ​​together

1:40:37

to find the greatest common divisor. 2 *

1:40:41

2 * 3 2 * 2 4 * 3 is = 12. That is the

1:40:46

greatest common divisor of these numbers.

1:40:50

Now I want you to pause the video and

1:40:53

calculate the greatest common divisor between

1:40:55

36 and 54.

1:40:59

Do you have it?

1:41:01

I'm making the table here.

1:41:05

So let's put ours here

1:41:06

prime numbers. 2 3 5 7 and so on

1:41:11

successively. And we'll see if

1:41:14

we can divide simultaneously.

1:41:16

We can now divide 36 simultaneously

1:41:19

and 54 * 2 and the answer is yes.

1:41:24

Here you'll have 18 and here 27.

1:41:28

Now, we can continue dividing

1:41:29

simultaneously by two, right? Since

1:41:32

27 is an odd number. So,

1:41:35

Let's move on to the next one. Can

1:41:36

divide simultaneously by 3 and the

1:41:38

The answer is yes. 18/3 is 6. 27/3

1:41:43

It's 9. And we continue. We can continue

1:41:47

dividing simultaneously by three. The

1:41:49

The answer is yes. Here it will stay

1:41:51

two and here you'll have three. So,

1:41:55

Since we divided by three, here's what you got

1:41:56

two and here you have three. Therefore,

1:42:00

because we can no longer continue to divide

1:42:01

simultaneously by three, as you know

1:42:03

account, nor by any older cousin. It

1:42:06

We'll stop here and multiply these

1:42:09

values ​​among themselves. 2 * 3 * 3 2 * 3 6

1:42:15

* 3 is 18. And we have it ready. Now

1:42:20

I want us to do one last example and

1:42:22

I want you to pause the video and...

1:42:24

You solve it. What is the greatest common factor?

1:42:26

A divisor between these values? I'm going to

1:42:30

I'll do it here. 30 60 75.

1:42:35

Let's place our prime numbers.

1:42:39

We're going to place the two, the three, the five,

1:42:42

7 and so on. And we're going to go

1:42:44

seeing if we can divide

1:42:45

simultaneously.

1:42:47

Here we can divide simultaneously by

1:42:50

two, and the answer is no, since

1:42:53

Here we have a number that is odd, therefore

1:42:56

Therefore, it is ruled out. Fists divide

1:42:59

simultaneously by three and the answer

1:43:01

Yes, that's right. It's going to be 10 here, it's going to be

1:43:05

It will be 20 and here it will be 25.

1:43:09

We can continue dividing

1:43:10

simultaneously by three and the answer

1:43:13

No, that's not it. Therefore, we're going to go with the

1:43:16

five. You mean all these numbers

1:43:17

are divisible by five, end in 00 and

1:43:19

5. So we're doing well. We divide by 5,

1:43:22

You have 2 left. We divide by 5, you get 4.

1:43:26

We divide by 5, you get 5. And if you

1:43:28

fixed here, we can no longer divide

1:43:30

simultaneously by 5 nor by any

1:43:32

older cousin. Therefore, we'll leave it until

1:43:34

there. We multiply 3 * 5 and 3 * 5 = 15,

1:43:39

this being the greatest common divisor.

1:43:42

Finally, we answer a typical question.

1:43:44

PES of how the maximum might appear

1:43:47

common divisor in context. It says: a

1:43:50

The school has 3/4 averages. Fourth A

1:43:53

It has 36 students, B has 45 and C has 54.

1:43:59

For an event, the following will be grouped together:

1:44:02

students in equal teams

1:44:04

amount. in each course to compete

1:44:07

with the others and thus win a prize.

1:44:10

What is the maximum amount of

1:44:12

students who can have a team?

1:44:16

To answer this question, the key is

1:44:18

finds in the quantity of

1:44:21

students in each team must be a

1:44:24

divisor of these quantities of students

1:44:28

totals we have in each course. Look,

1:44:31

an example. Suppose I say that

1:44:34

I want each team to have four

1:44:38

students.

1:44:40

So, if I divide 36 by 4 here,

1:44:43

we reached the point where I can form nine

1:44:45

teams and no student is left out.

1:44:49

But, for example, if I don't place a

1:44:51

If a divisor of 36 is a factor, it will happen that, because

1:44:53

For example, I mean, I already want them to have

1:44:55

five students per team. And if you

1:44:58

You realize, the 36 di 5 is not a

1:45:03

exact division and in fact a student

1:45:05

will be left out.

1:45:06

So here I need to find a divisor of

1:45:10

36, but also as the amount should

1:45:14

To be the same in each course, I must look

1:45:16

a divisor of 45 and also of 54 and that to

1:45:22

the time is exactly the same divisor

1:45:26

that we're going to have for each of these

1:45:29

values. Therefore, we need to look for a

1:45:32

common divisor so that no one is left out. AND

1:45:37

Similarly, here they ask me to be

1:45:40

the greatest common divisor we have.

1:45:44

Therefore, they are asking me for the maximum.

1:45:45

common divisor. Therefore, here I am going to

1:45:48

I'm going to put the 36, I'm going to put the 45 and I'm going

1:45:52

to place the 54.

1:45:54

We're going to apply

1:45:57

the method we've seen all this

1:45:59

a while. So,

1:46:04

already

1:46:06

These numbers are simultaneously

1:46:08

divisible by two. The answer is that

1:46:11

No. Therefore, we're going to move on to the

1:46:14

following. I can go simultaneously through

1:46:16

three and the answer is yes. In this

1:46:19

In this case, 36/3 leaves us with 12. 45/3

1:46:24

There are 5 and 54/3 left, we have 18 left. I can

1:46:29

How can we continue dividing simultaneously by 3?

1:46:32

The answer is yes. Here we're going to

1:46:35

If there are four left, we'll have five here.

1:46:38

And here we'll have six left. And if you

1:46:41

fixed here, I can't go anymore

1:46:43

simultaneously by three, nor by

1:46:46

no older cousin. Therefore, this comes

1:46:50

up to this point. Therefore, we multiply 3

1:46:54

* 3 and this gives us 9, which is the maximum

1:46:58

common divisor of these values ​​and that goes

1:47:01

to be the maximum possible amount that

1:47:04

I can have students in each

1:47:06

equipment.

1:47:08

Before continuing with the summary,

1:47:10

I want to congratulate you on completing

1:47:12

the subject matter of the first topic in the summary,

1:47:15

which was whole numbers, which was the

1:47:18

longer part of the summary. And from

1:47:20

I'm really happy that there is

1:47:22

reached this part of the video. Speaks

1:47:24

much of the discipline you are

1:47:25

having and of course everything that

1:47:28

you can achieve. Therefore, I want

1:47:30

that you continue down that same path, that you don't

1:47:33

Don't give up, keep showing what you're capable of.

1:47:35

You'll be able to when it's your turn to practice with

1:47:37

the exercises. See step by step how it is

1:47:39

Solve each one and practice with them.

1:47:42

exercises so you can reach the

1:47:44

next level. I am completely

1:47:47

I'm sure that if you continue on this path you'll have

1:47:50

tremendous results, that score is going to

1:47:52

go up and you'll be in that race that

1:47:55

You deserve to be there.

1:47:58

Before we continue, I want to leave you with the

1:48:00

Invitation to join the ultra-intensive

1:48:03

M30M, the largest intensive care unit that has ever been

1:48:06

Made in Chile to prepare for a test.

1:48:09

We're going to take care of transforming your

1:48:11

score in 14 days, from the 17th to the 30th

1:48:15

November. And this is going to be a festival,

1:48:18

the biggest festival ever held

1:48:19

in Chile to prepare for a test that will

1:48:22

to be the PES. And what will the

1:48:25

grill? Look, here's the stage

1:48:28

national maximum. What is a grill?

1:48:30

general? If you want to have one

1:48:32

balanced preparation and attendance

1:48:34

Obviously, to the classes you want.

1:48:37

where you will be able to attend M1, to

1:48:39

reading comprehension, obviously

1:48:42

science, history and of course M2,

1:48:44

Where is the trip going to be? Where are we going?

1:48:45

to be in charge of learning the content and

1:48:48

exercise and above all enjoy it

1:48:51

M30M community to make this trip

1:48:53

as entertaining as possible. This is a

1:48:57

main general grill. Obviously

1:48:59

Then we'll give the details of what's going to happen

1:49:01

to be in each block. However,

1:49:03

Let's suppose that you directly...

1:49:05

you want to focus on science, on

1:49:07

mathematics or in any test of

1:49:09

humanities area. Of course they're going to

1:49:11

There will be stages that will run in parallel,

1:49:14

literally while these are being made

1:49:16

Classes will also be held in parallel to

1:49:18

You are where, if you want, you can

1:49:20

Focus 100% on science during the stage

1:49:23

scientist, studying physics, biology,

1:49:26

chemistry and of course also the stage

1:49:28

mathematical, where we are going to solve almost

1:49:30

all the questions that have come up in the

1:49:32

test or very similar to those that will

1:49:35

to go out in the test. And of course

1:49:37

also the humanist stage where you go

1:49:39

to be able to focus on reading comprehension and

1:49:41

in history. Then you'll have for

1:49:44

to enjoy being on stage

1:49:46

whatever you want, and we'll live one

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a unique experience to take that

1:49:49

score to the next level.

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The price of the ultra-intensive treatment is

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For just 30,000 pesos, you'll have

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access to the preparation of all the

1:50:00

tests at this great festival we're going

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to do, where we are going to take care of

1:50:04

with a clear routine to be able to carry that out

1:50:06

score to the next level. The

1:50:09

Registration opens on the 3rd

1:50:12

November, so if you're watching

1:50:14

The video before, you have to wait until that

1:50:16

Date to register. or if you are

1:50:18

watching the video after the 3rd

1:50:19

In November, you can now register for

1:50:21

Ultra Intensive 30M and we're off to

1:50:24

to be in charge of bringing that score to

1:50:27

next level. You can join by

1:50:30

Click on this QR code. In fact, it's going to

1:50:32

There will be a waiting list if you

1:50:34

Register before November 3rd to

1:50:36

Secure your spot and we'll be there too.

1:50:38

to maybe have one as a little gift. So

1:50:41

Also, if this doesn't work for you

1:50:42

QR code, you can go here to the

1:50:45

description and that's where it obviously always goes

1:50:46

to have the link. We'll take care of it.

1:50:49

that those two weeks, those two

1:50:51

the last few weeks, which are the most important.

1:50:53

impact they can have on your score

1:50:56

really worth it. Make your score

1:50:59

rise like foam and of course we're going

1:51:02

to work so that you stay in that

1:51:04

career of your dreams.

1:51:07

Now we're going to learn how to solve it step by step.

1:51:09

I'll pass on the questions from this content that

1:51:12

They might come out in peace. To do this,

1:51:15

Go down to the description and you'll find them.

1:51:17

to find all the questions and then

1:51:20

return to this part of the video so that

1:51:23

Let's keep learning.

1:51:26

And now let's talk about rational numbers.

1:51:30

First, let's remember what

1:51:32

is a fraction.

1:51:35

A fraction is the expression of

1:51:39

an amount divided into equal parts.

1:51:44

It is represented by two numbers

1:51:46

integers separated by a slash

1:51:49

fraction.

1:51:50

We call the number above the

1:51:53

numerator

1:51:55

and we call the little number below the

1:51:58

denominator with the latter being different from

1:52:02

since it recalls that division by

1:52:05

0 is undefined in numbers

1:52:09

real.

1:52:11

With this in mind, we will now

1:52:14

see how to represent fractions, which is

1:52:17

something that has been asked in the

1:52:19

proof. To do this, we will begin

1:52:23

remembering proper fractions and how

1:52:26

represent them.

1:52:28

A proper fraction is a fraction

1:52:31

where the absolute value of the numerator

1:52:35

is less than the absolute value of

1:52:38

denominator. In this case we have the

1:52:41

fraction 1/

1:52:44

4. Yes. How do we do the representation?

1:52:48

To do this we will work with

1:52:50

little circles.

1:52:52

So, what will we do? In

1:52:54

First, you're going to take your little circle and

1:52:57

You're going to see the denominator. The denominator

1:53:01

It's four. Therefore, our little circle

1:53:04

We're going to divide it into four parts

1:53:07

equal.

1:53:08

After that, let's look at the numerator,

1:53:13

which in this case is one. And we're going to say

1:53:15

as follows. Ah, I see. Perfect. Of the

1:53:18

four equal parts, let's take

1:53:20

a. Therefore, we're going to...

1:53:24

paint exactly as it appears in this

1:53:28

We left the drawing and the rest untouched. Of

1:53:31

That's how we've represented the fraction

1:53:35

1/4.

1:53:37

Now let's look at another example. Come on

1:53:40

Let's see how to represent the fraction 2/3.

1:53:46

The fraction 2/3 to represent it

1:53:50

We follow exactly the same logic. In

1:53:53

First we look at the denominator.

1:53:57

In this case, our denominator is

1:54:00

three. Therefore, our little circle

1:54:03

We're going to divide it into three equal parts.

1:54:08

Next we look at the numerator.

1:54:11

The numerator is two. Therefore,

1:54:14

From our three equal parts, we will

1:54:18

Take two, and those are the ones we're going to

1:54:20

paint. We left the other one untouched, that's all

1:54:23

which can be seen in the figure here. Of this

1:54:27

We have represented the fraction in this way.

1:54:29

23.

1:54:31

We continue. See what happens with one

1:54:34

fraction like this. In this case 4/4 or

1:54:41

4/4.

1:54:42

Look, as always you're going to start by watching

1:54:46

the denominator.

1:54:49

Denominator four. We're going to take

1:54:50

our little circle and we're going to divide it

1:54:52

into four equal parts. But here

1:54:55

Something interesting happens, and that is that

1:55:00

We're going to take all four parts. By

1:55:03

Therefore, in this case we are going to have to

1:55:06

paint each of our four

1:55:09

parts to represent this fraction.

1:55:13

In this way we have learned how to

1:55:15

represents this type of fraction

1:55:18

when the numerator and denominator are

1:55:22

equal.

1:55:24

Now we're going to see how to represent a

1:55:27

improper fraction. We called a

1:55:30

improper fraction when the value

1:55:32

absolute value of the numerator is greater than the value

1:55:36

absolute of the denominator. How can we

1:55:39

How do you represent these fractions? We continue

1:55:42

the same logic. Look, we see the

1:55:46

denominator. In this case, the

1:55:48

The denominator is four. Therefore, we took

1:55:51

our little circle and we divide it into

1:55:53

four equal parts, right? By

1:55:55

For example, this one we have here is

1:55:57

divided into four equal parts,

1:55:59

TRUE?

1:56:01

But we have a small problem, and it is

1:56:04

that the little circle split into four

1:56:07

equal parts, but let's take five

1:56:11

parts. Therefore, the key here is

1:56:15

find it in drawing another little circle

1:56:18

until we can fulfill the agreements

1:56:20

that are needed. So we draw here

1:56:24

The first one, the first little circle tells me,

1:56:27

"Okay, here's a part of it, here you go

1:56:31

"Two, three, and here there are four." It's not enough.

1:56:35

Another small circle is drawn, and then it's done again.

1:56:38

divide into four equal parts and let's go

1:56:41

to take one of those parts. And from this

1:56:44

In this way we have 1, 2, 3, 4 and the fifth one that

1:56:48

We were missing it. And in that way

1:56:51

We represent this type of fraction.

1:56:55

Let's look at another example. Let's suppose now

1:56:58

we want to represent

1:57:00

this fraction 7/4. Once again we have

1:57:04

to take the little circle. We divided it into

1:57:06

four equal parts, but we want

1:57:09

Take seven. Therefore, we are going to have

1:57:10

than drawing more than one little circle. And let's go

1:57:13

counting. Here I have one, two, three, four

1:57:17

parts, but we are missing three parts to

1:57:20

arrive at seven. Therefore, we draw

1:57:23

another little circle, we divide it into four

1:57:25

equal parts and we paint the ones that

1:57:27

are missing. One, two, three. And in this way

1:57:32

We have represented the fraction 7/4.

1:57:36

Like I said, this is something that's coming.

1:57:38

asking in the test and if you handle it

1:57:41

You're going to have another good question in

1:57:44

the pairs.

1:57:47

Now let's see how to calculate the value

1:57:50

numerical value of a fraction. And here

1:57:53

You simply need to perform the

1:57:55

division. In this summary, I will not see

1:57:58

how exactly it is divided, however,

1:58:01

I'll leave you with the results of these

1:58:02

fractions obtained by performing

1:58:04

the corresponding divisions. And how

1:58:06

Are they carried out? Simple. Divide the

1:58:10

numerator in the denominator. In this

1:58:13

case 3/4. If you perform the division of 3

1:58:16

Dividing by 4 gives you the result

1:58:20

0.75.

1:58:23

Now, if you divide 12 by 5, you get...

1:58:27

result 2.4. If you divide 1 into 5, you get

1:58:33

gives 0.2.

1:58:35

And if you divide 1 by three, the result that

1:58:39

It's going to give you 0.33

1:58:42

3

1:58:43

and so on indefinitely. And when this

1:58:46

This happens, as we will see later,

1:58:48

We will say that this number is a decimal.

1:58:50

newspaper. We'll see this in a couple of

1:58:54

a few more minutes.

1:58:57

We will now study the equivalence

1:58:59

between fractions. We say that two or more

1:59:03

fractions are equivalent if

1:59:05

They represent the same amount, although

1:59:08

let their numerators and denominators be

1:59:11

different. For example, these fractions

1:59:13

that we have here, which are 3/ 6/8 and 75/

1:59:18

100, are all equivalent fractions,

1:59:21

because if you perform each of

1:59:23

These divisions, you'll reach the same

1:59:26

result. In this case, if you perform

1:59:29

These divisions, any of these,

1:59:32

The result will be 0.75.

1:59:38

Now, you'll often find yourself

1:59:40

with negative fractions and often

1:59:44

They can also be expressed in different ways.

1:59:46

ways, but I want you to see that this

1:59:49

that you're going to have next

1:59:51

They represent exactly the same number.

1:59:53

For example, if I have -3 here and

1:59:56

divided by 4, is the same result as

2:00:00

have 3 and divide it by -4. Is

2:00:04

exactly the same. And that's exactly it.

2:00:07

The same goes for having the least, so...

2:00:10

to say it, outside the fraction, to carry out

2:00:13

The division of 3/id into 4 and this will be

2:00:16

I simply keep the minus 3/4.

2:00:19

0.75

2:00:21

and each of these operations leads you

2:00:24

exactly the same result. Because

2:00:28

Is this very important to remember?

2:00:29

Because depending on the developments,

2:00:32

often one writes it as one writes

2:00:34

one way or another. However, all

2:00:37

They represent exactly the same value.

2:00:40

Now we are going to study simplification

2:00:42

of fractions, which consists of finding

2:00:45

an equivalent fraction by dividing

2:00:47

both the numerator and the denominator

2:00:51

by some common divisor.

2:00:54

We can find two types of

2:00:56

fractions. Those that are reducible, are

2:00:59

In other words, we can simplify them, and the

2:01:01

that are irreducible, that is, not the

2:01:04

We can continue simplifying. Let's go

2:01:06

See some examples here. To do the

2:01:10

simplification process, we have to

2:01:13

ask ourselves the following. Let's go with the

2:01:15

first part. Is there a divisor that

2:01:18

have in common both the numerator and

2:01:22

the denominator? find a divisor

2:01:24

different from one, because if it doesn't suit you

2:01:26

to remain exactly the same. So,

2:01:29

Is there a divisor we have in

2:01:30

common? For example, the 16th and the 64th

2:01:36

These are numbers that are divisible by 4.

2:01:39

So, what are we going to do? Come on

2:01:41

to divide both the numerator and the

2:01:45

denominator times four. Always for

2:01:48

To simplify, you divide the top and bottom.

2:01:52

So, 16/4 is 4. 64/4 16. And from

2:02:01

We're doing great! Now I'm going back to

2:02:03

ask, is there any divisor that has

2:02:06

What do they have in common, both the 4?

2:02:10

In this case, I was able to simplify.

2:02:13

dividing by 4 again. Both are

2:02:17

divisible by 4. So 4/4 is 1.

2:02:22

All of this divided into 16/4, which is 4. And

2:02:26

Here we reach 1/4. And I return to

2:02:29

ask the same question. Is there a divisor?

2:02:31

that we have in common? If you look closely, the

2:02:33

The only common divisor will be one. By

2:02:37

Therefore, we can no longer continue here.

2:02:39

simplifying and we have arrived at a

2:02:42

a fraction that is irreducible, cannot be

2:02:45

You can continue simplifying.

2:02:47

Now, in an ideal world,

2:02:50

What can we do? Instead of walking

2:02:52

dividing each time as

2:02:54

We find divisors, ideally,

2:02:58

Obviously this requires practice,

2:03:00

It's about you finding the highest common denominator.

2:03:02

divisor to make that process a single

2:03:05

time. In this case, the greatest common

2:03:08

The divisor between 16 and 64 is 16.

2:03:13

Therefore, I could directly do this here.

2:03:15

divide by the greatest common divisor, which

2:03:18

It's 16 here too. and 16/16 is a is 1

2:03:24

and 64/16 is 4 and we arrive exactly at

2:03:29

same result which is 1/4. Very

2:03:32

It's important to keep in mind that no

2:03:34

It is mandatory that you seek the maximum

2:03:37

common divisor. You can start doing it.

2:03:39

looking for divisors as it goes

2:03:42

simplifying. However, it is the way

2:03:45

faster to reach the result.

2:03:48

Obviously, do what works best for you.

2:03:51

comfortable. Look, let's see another example. In

2:03:54

This case, number 120, was born in 15 days. Yeah, look.

2:03:58

One might look at this and say, "Ah, I see,

2:04:00

Look, you know that both are divisible

2:04:03

by 5, then I divide by 5 both the

2:04:05

numerator as the denominator. So,

2:04:08

120/5, what is it? It's the 24th.

2:04:13

15/5 is 3. Now I could also continue

2:04:18

simplifying here the 24 with the 3

2:04:20

dividing by 3, which is the divisor that

2:04:22

what they have in common, or just focus on

2:04:24

that 24/3 is equal to 8. You arrive exactly

2:04:30

the same result by performing the

2:04:32

division or simplifying.

2:04:35

Now you could do it directly

2:04:37

performing the division here, because if you

2:04:39

You state that 120 is divisible by 15 and if

2:04:43

You performed the division here, and it left you with

2:04:45

eight and you arrived at exactly the same

2:04:48

result. We're trying to see

2:04:50

different types of fractions that you

2:04:52

could appear. Many times

2:04:54

Performing the division you will arrive at a

2:04:55

whole number without any problem. No

2:04:58

always, but it can happen.

2:05:00

Now we have the fraction 20/ in 3. In

2:05:04

In this case, the only positive divisor that

2:05:06

What we have in common is one. Therefore,

2:05:09

Here we already have a fraction which is

2:05:13

irreducible, it cannot be followed

2:05:15

simplifying.

2:05:17

We were studying the

2:05:19

whole numbers and now the moment has arrived

2:05:22

to know rational numbers.

2:05:25

Rational numbers are all

2:05:27

those numbers that we can

2:05:30

represent as a fraction, that is,

2:05:33

a division between two integers with the

2:05:37

denominator other than zero. Now, one

2:05:40

very important thing, previously

2:05:43

We study integers, right? But

2:05:46

You have to take into account that all the

2:05:48

Integers are rational numbers.

2:05:53

Because? Because every whole number is

2:05:56

can be represented as a fraction. Let's see

2:05:58

Here are some examples. The 2 is exactly

2:06:02

The same as 2 born in 1. I have the here

2:06:06

division between integers, therefore, it

2:06:09

can be represented as a fraction.

2:06:12

Another example, the cer. Zero is what

2:06:15

same as 0 divided, for example, by 5.

2:06:19

0 divided by 5 0. Therefore, here we have

2:06:22

representing zero as a fraction.

2:06:25

Negative numbers too, because

2:06:27

For example, -5. The -5 can be

2:06:31

rewrite with a -5 divided by 1. And

2:06:35

Here we have represented it as a

2:06:38

fraction. Therefore, all integers

2:06:41

They are rational.

2:06:43

So, what's happening here? And there are

2:06:47

rational numbers that are not integers.

2:06:49

For example, we saw earlier that the

2:06:52

fraction 3/4, if you perform the division

2:06:55

The corresponding result gives you the

2:06:58

number 0.75.

2:07:00

And 0.75

2:07:02

It is a rational number. Because? because

2:07:05

There is a fraction that represents it and of

2:07:08

In that way, we have found a

2:07:12

rational number that is not an integer. Others

2:07:15

rational numbers, for example, 0.1

2:07:19

which is the same as 1/gone in 10. eh

2:07:22

periodic issues that we will now

2:07:24

study. For example, the 0.3 periodic,

2:07:28

which is the result of

2:07:31

perform the division between 1 and 3 or

2:07:34

semi-periodic numbers, which also

2:07:36

Let's study how to start from 0

2:07:39

1, 2, and with the 2 newspaper. All these

2:07:43

are rational numbers, since as

2:07:45

We'll see more about these later.

2:07:48

we can represent it as a fraction. Don't

2:07:50

Don't worry, we're going to learn to

2:07:52

represent these values ​​as a fraction,

2:07:54

But that's the definition of numbers.

2:07:58

rationals and that is the set that

2:08:00

We're going to start studying from now on.

2:08:02

Before we continue, I want you to

2:08:04

Let's remember the structure and the

2:08:07

fundamental about numbers

2:08:10

decimals.

2:08:11

Remember that decimal numbers

2:08:13

They have a whole part and a part

2:08:16

decimal, which are separated by

2:08:20

a comma. One might encounter

2:08:23

decimals that are finite, decimals

2:08:25

periodic, semi-periodic decimals and

2:08:29

decimals that have a quantity

2:08:32

infinitely many decimal numbers, but that

2:08:35

They do not follow a specific pattern. Let's go

2:08:37

study each one of them. For example,

2:08:40

The first one we see here is a decimal

2:08:42

finite, it has a certain amount here of

2:08:45

decimals. We have 1.25,

2:08:49

but you can also observe here a

2:08:53

decimal repeating decimal. Why is this

2:08:56

newspaper? Because the entire decimal part

2:09:01

It has a bar at the top. And

2:09:03

Does that mean? It means that this 25th will be

2:09:08

It will repeat endlessly, following

2:09:11

that pattern. In this case, this would come

2:09:14

being 1,

2:09:16

25

2:09:24

and so on.

2:09:27

But decimal numbers also exist

2:09:31

semi-periodicals,

2:09:33

That is, decimals where we have this

2:09:36

bar, but it's not found everywhere

2:09:40

decimal part. In this case only

2:09:42

He's with number five. What's this all about?

2:09:44

means? This is going to be number 1, 2

2:09:49

and here put 5 5

2:09:54

and so on indefinitely.

2:09:57

There are also other decimal places that

2:09:59

we will study later, what they are

2:10:02

irrational numbers. But as I say,

2:10:04

That comes later, those are numbers.

2:10:07

decimals that have a quantity

2:10:10

infinite decimal places, but not

2:10:12

They follow a specific pattern. These the

2:10:16

We will study this further later. Now we

2:10:19

We're going to focus only on these three.

2:10:21

first.

2:10:24

Now, remember what it is anyway.

2:10:26

the structure of a decimal number. In

2:10:28

the whole part, as always, we're going to

2:10:29

to have unit, ten, hundred, etc.

2:10:32

And in the decimal part, that is, what

2:10:34

It comes after the comma, we're going to have

2:10:37

a tenth, then comes the hundredth, the

2:10:40

thousandth, the 10th thousandth, and so on

2:10:44

successively.

2:10:47

Now, a very, very important consideration.

2:10:50

important.

2:10:51

Here you will often find

2:10:53

fractions that are 2.5, 2.50,

2:10:57

2,500,

2:10:58

2,500 and so on.

2:11:02

It's important that you keep this in mind

2:11:04

following. One usually writes

2:11:08

down to the last digit, which is different

2:11:11

from scratch. For example, here we write the

2:11:14

2.5. However, this is equivalent,

2:11:18

It's the same value at 2.50, at 2.500,

2:11:22

to 2,500. It could even be the same thing

2:11:25

than 2,500

2:11:29

and so on, and they represent

2:11:32

exactly the same value. But

2:11:34

obviously so I don't have to write all this

2:11:36

one only leaves until the last

2:11:40

a number that is not zero, comes

2:11:44

being the five. Obviously the last one

2:11:48

number from left to right until

2:11:50

you get this far and that way you don't

2:11:54

we are writing all these zeros.

2:11:58

In the PAES we will often have

2:12:00

to perform the comparison between

2:12:02

numbers. This occurs mainly among

2:12:05

rational numbers, but also you

2:12:07

It can come out in whole numbers, in numbers

2:12:09

real, etc.

2:12:11

So, what are we going to do?

2:12:14

We're going to have to remember the symbols.

2:12:17

of inequalities, which is going to

2:12:18

to indicate that a certain number is less or

2:12:22

greater than another, or less than or equal to,

2:12:25

etc. And this can often

2:12:27

to be very confusing. Look, first

2:12:30

I'm going to show you what that means.

2:12:32

each of these symbols here and

2:12:35

Later I'll give you a great trick that

2:12:38

will ensure you never make a mistake in

2:12:40

interpret it. Look, if I have two

2:12:42

numbers, a number A and a number B, if

2:12:45

This appears here, it means that A

2:12:48

It's a number less than B. If it appears

2:12:52

This here means that A is greater

2:12:55

that b. Often it will also

2:12:57

A bar will appear down here. And

2:12:59

Does this imply? Look, if this appears

2:13:02

Here, it means that A is less than or equal to

2:13:05

B. On the other hand, if this appears,

2:13:08

This means that A is greater than or equal to B.

2:13:12

And as I told you, this issue here

2:13:14

It can be quite confusing, but there is a

2:13:17

A pretty practical trick. Look, already because

2:13:20

For example, suppose we have this here

2:13:21

And you're having trouble figuring out which one it is.

2:13:24

which is greater, which is smaller, and I confused you, no

2:13:26

I worried you. What you're going to do here is

2:13:29

draw a Pacman. You can put this on it now.

2:13:32

Just keep an eye on it, it's still there. And Pacman always

2:13:34

He's going to point to the one who is older. In this

2:13:38

The case is pointing to B. Therefore,

2:13:42

We know that A is less than B because the

2:13:44

Pacman is aiming for B, then. And it

2:13:46

Right here, look, if I draw Pacman,

2:13:48

Let's draw Pacman here. Look

2:13:51

Here's where Pacman aims for the biggest one, because

2:13:53

then A is greater than B. And nothing.

2:13:55

more than that. Now, if the

2:13:59

Does the bar down here change anything?

2:14:01

Our method? No, look, the only thing that

2:14:03

What we're going to do is take Pacman,

2:14:07

For example, here, and Pacman is...

2:14:09

pointing to A. And what we're going to say

2:14:11

It means that A is greater than or equal to B. And nothing else.

2:14:16

more than that.

2:14:19

Now we are going to study the comparison of

2:14:21

decimal numbers. Here we're going to learn

2:14:24

to order them from smallest to largest.

2:14:27

We will look to compare decimals that are

2:14:29

of values ​​very close to each other. and

2:14:31

We're going to look at different strategies for

2:14:33

compare them. Look, the first case and more

2:14:36

It's simple: you'll find two.

2:14:38

decimals that are positive and have the

2:14:41

same number of decimal places. In

2:14:44

In this case I have two decimal places and

2:14:46

here too. Now, what will the

2:14:50

clue? Simple. You're going to compare which one

2:14:52

has a greater absolute value than another. A

2:14:55

A good strategy to avoid confusion is

2:14:57

Write the complete numbers. I have the

2:14:59

3.23

2:15:01

3.27

2:15:03

aligning the commas together so that we can

2:15:05

to properly establish the comparison between

2:15:08

figures. So, look, listen, look, the

2:15:10

part of the unit is the same, no

2:15:13

We can make a comparison there. The

2:15:15

part of the tenth is also the same,

2:15:19

so we cannot establish the

2:15:20

comparison there. However, the part

2:15:24

of the hundredth

2:15:27

Here we do have a difference, therefore

2:15:30

We establish the comparison. Here you will

2:15:32

You realize, 3 is less than 7, because

2:15:35

Therefore, 2, sorry, 3.23

2:15:39

is a number that is less than 3.27

2:15:44

and in that way we carried out the

2:15:46

comparison. I know, this was visible

2:15:49

It's quite simple, but as I said, it's a

2:15:51

A very useful strategy for all types

2:15:53

of exercises that you come across with two

2:15:56

decimals that have the same amount

2:16:00

of decimal places and establish the

2:16:02

comparison, even if you have to

2:16:04

add more numbers. It's very, very useful.

2:16:07

Now, what would happen, for example, if we

2:16:10

we find with decimal numbers that

2:16:14

Are they negative again, two-digit numbers?

2:16:18

Simple. What he's going to do here is

2:16:20

compare the values ​​again

2:16:22

absolutes. In fact, we already did it with

2:16:23

those of us who are above, but remember

2:16:26

that when we are working with

2:16:28

negative numbers, as they increase

2:16:30

The absolute value means that the

2:16:32

The number is further from zero in the

2:16:34

number line, therefore, is going to be more

2:16:36

small in negative numbers. In

2:16:38

In this case, if you place the line here

2:16:40

numerical, you place the 0, you know that the

2:16:43

-3.23 will be here and the other value that

2:16:47

-3.27 will be found here

2:16:49

which has a greater absolute value. By

2:16:52

Therefore, -3.27

2:16:56

It will be less than -3.23.

2:16:59

[Music]

2:17:02

And that way we have it ready

2:17:05

order relation. Finally we're going to

2:17:08

see how to compare decimal numbers that

2:17:11

They have a different number of digits

2:17:14

decimals. Look, it's very simple here.

2:17:18

As always, we're going to take our

2:17:20

decimals and we're going to align the comma.

2:17:23

Let's put this comma down here.

2:17:25

This is a 3, 2, 4, and 5. And what you're going to

2:17:28

What to do here is fill the with zeros

2:17:31

number that has the smallest amount of

2:17:33

decimal numbers. In this case, this

2:17:36

I'm going to put two zeros so that they have

2:17:38

exactly the same. So, let's go

2:17:41

comparing figure by figure. Three no se

2:17:45

can compare. Here it's two, you can't

2:17:47

compare, but here

2:17:50

if it allows us to compare in order to establish

2:17:52

which one is greater than the other.

2:17:54

In this case

2:17:57

I know that he is less than 4. Therefore

2:18:01

3.2

2:18:02

is less than 3 com 2

2:18:09

and we have already established the relationship of

2:18:13

order. And now we're going to see all this

2:18:15

topic of converting fractions to decimals,

2:18:18

decimals to fractions, being decimals

2:18:21

finite, periodic, semi-periodic,

2:18:24

everything we could possibly find. Is

2:18:27

It's very important that you keep in mind that

2:18:29

What we're about to see, we've already seen.

2:18:31

When one has a fraction and wants

2:18:34

To know its value, what one does is

2:18:36

perform the division by the numerator

2:18:38

and the denominator. For example,

2:18:40

again, the same as before,

2:18:42

3/4 is a 3/4 that results in

2:18:47

0.75.

2:18:49

12/5 is a 2.4.

2:18:54

The division is performed by dividing 1 by 9.

2:18:58

0.11

2:19:00

1

2:19:02

and so on, which gives us as

2:19:05

result 0.1

2:19:08

newspaper. It's exactly the same.

2:19:12

Now, we've already seen that. Without

2:19:14

However, I want to share some things with you

2:19:15

small tips that can be quite useful

2:19:17

useful. The first tip is when you divide

2:19:20

the number one in some power of 10,

2:19:23

which are numbers like 10, 100,

2:19:27

1000, 100,000, 1000 and 1.00on,

2:19:29

10,000ones, etc. Always the

2:19:33

The numbers you're going to have left are going to have

2:19:35

In this way, there will be zero, starting

2:19:37

with zero, comma, then place a certain

2:19:41

number of zeros depending on which one

2:19:43

the number by which we are dividing

2:19:44

and then you end up in one. So, to

2:19:47

see, 0.001 0.01

2:19:50

eh 0.0001

2:19:53

or even 0.1.

2:19:55

And how do we determine which one we'll be left with?

2:19:57

Look, this is very simple, as you

2:19:59

I mean, it's purely a tip. Can

2:20:00

You can edit if you want, there's no need to.

2:20:02

No problem, but with the tip it works out

2:20:04

faster. Look, let's suppose I have 1

2:20:07

Part 10, what I'm going to do is

2:20:08

following. I'll count the amount now.

2:20:10

of zeros. I have a cer ende the result

2:20:13

It will have a single decimal number.

2:20:16

So you're going to start from zero, you're going to

2:20:18

Add the comma and you should always end

2:20:21

in one. In this case, since we have a

2:20:24

only one decimal place

2:20:26

We will place the one. And here we have

2:20:28

our only decimal place. Let's look at another one

2:20:31

Here's an example to make it much clearer.

2:20:33

We have 1 birth in 100. We count 1 2.

2:20:36

In other words, the result must have two

2:20:38

decimals. So, I put 0 comma, I go

2:20:42

to place a cer and to already have two

2:20:45

numbers ending in one and there we have it

2:20:48

list. Remember that you will always

2:20:50

to end in one. So, again, here

2:20:53

I have 1, 2, 3. I have to have three.

2:20:56

decimals. 0 com 1 2 and I end in one

2:21:01

to have those three figures. Now

2:21:04

I want you to pause the video and do it yourself.

2:21:06

with which it comes.

2:21:09

Do you have it? We'll go. This is 0

2:21:13

coma. We counted 1, 2, 3, 4, 5. I want five.

2:21:18

decimals. I place 1 2 3 4 and we close with

2:21:23

one to have the five decimal places and

2:21:26

We carried out the division quickly.

2:21:30

That's the trick, and I actually want you to

2:21:32

Let's do one more and you tell me what 1 is

2:21:34

match in and we're going to put it here

2:21:37

10,000ones.

2:21:39

Pause the video and tell me how much it is. I do it

2:21:42

me at this moment. We already counted. 1 2 3 4

2:21:46

5 6 7. So it's going to be 0 com 1 2 3 4 5

2:21:52

6 and we close with the last one which will be

2:21:55

one and we have the seven decimal places.

2:21:59

Now let's see how to do it

2:22:01

divisions with a power of 10. But

2:22:03

when the numerator, that is, the

2:22:05

The little number we have up here is

2:22:07

different from one. There's also a trick. AND

2:22:10

Here's a trick, I'm going to do it right away

2:22:11

a little slower and then,

2:22:14

Obviously, when we meet

2:22:15

operations like that I simply go to

2:22:17

result. So, look, we have here

2:22:21

25/

2:22:22

In 10. How do we do it? Look, I'm going to

2:22:26

Put 25 here. 25. And I'm going to

2:22:29

insert a comma. 25. and I'm going to put

2:22:33

25.0 purely for the purposes of

2:22:35

illustrative. So, what are we going to do?

2:22:37

do? Let's count the number of zeros

2:22:40

that we have in the denominator, in

2:22:43

Our power of 10. And in this case

2:22:45

we have a single zero. Therefore, what

2:22:47

What we're going to do is move the comma towards the

2:22:50

left

2:22:52

depending on how many zeros we have. In

2:22:54

In this case we only have one zero, we

2:22:56

we move only once towards the

2:22:58

left comma. Therefore, here we are going to

2:23:00

The comma will be located here and it will be a

2:23:03

2.5.

2:23:05

And that's done quite quickly.

2:23:08

process. We now have a 25/id at 100,

2:23:12

same process. I'm 25, I've been in a coma

2:23:16

Úetamente to guide us. And how much

2:23:19

the zeros? 1 2 We need to move two

2:23:22

units to the left.

2:23:24

We move the comma 1, two. The comma has

2:23:28

that stay here. Notice that the comma

2:23:31

remain after the first digit that

2:23:34

We had, what are we going to do for

2:23:36

To represent the result is to add a

2:23:40

zero here to the whole part we have.

2:23:43

So here it's going to be the same

2:23:46

color,

2:23:48

25. And that way we have it ready

2:23:52

result and we do it again with the

2:23:55

coming. We already counted. Here I have 1 2 3.

2:24:00

I set my 25.0

2:24:03

and we'll keep counting

2:24:05

1, 2, and 3. The comma should go here.

2:24:11

So what do we do with the spaces?

2:24:12

What do we have here? Simple, we're going to

2:24:15

fill with zeros. We put a zero here

2:24:18

in the whole part and in that way already

2:24:22

We have our value. This is 0.025.

2:24:28

Now we're going to study how to move on

2:24:30

finite decimals to fraction. Look,

2:24:34

We start with a number that is 0.25.

2:24:38

What we're going to do when we pass a

2:24:40

Converting a finite decimal to a fraction is what

2:24:43

following. Let's write the number

2:24:46

complete without considering the comma or the

2:24:49

first zeros. In other words, we consider

2:24:51

from the first non-cer number

2:24:58

And we're going to divide it, pay attention here, into

2:25:01

a one and both zeros and digits

2:25:05

decimals we have. In this case we have

2:25:08

1 2. We put two zeros here and we arrive

2:25:13

at 25/ in 100, which is the same as 0.25,

2:25:18

which we had actually done here.

2:25:21

Look, we had that right here.

2:25:25

already. And here, obviously, if one wishes, one can

2:25:28

simplify the fraction to the extent that

2:25:30

if possible. In this case, purely the

2:25:33

I'm going to leave it untouched.

2:25:35

Now we have a 1.25 here. The same,

2:25:40

we write the complete number without

2:25:42

Considering the comma, it would be 125

2:25:46

and we divide it into a 1 and so many zeros

2:25:50

as decimal places. We have counted 1 2

2:25:54

decimals 1 and 2 and we have it ready.

2:25:59

Like I said, many times you'll be able to

2:26:02

simplify the fractions. In this

2:26:03

In that case, I'm not going to do it. But also

2:26:06

He can do it without any problem.

2:26:09

Now, what happens when we have

2:26:12

repeating decimals and we want them

2:26:15

convert to a fraction? Yes, one of the methods

2:26:18

It is the following. Let's look at it in three

2:26:20

simple steps. Step number one,

2:26:23

we write the complete number without

2:26:25

consider neither the comma nor the period nor the

2:26:28

first zeros that we're going to have.

2:26:30

Obviously, it considers from the first

2:26:32

a number other than zero. In this case

2:26:35

We placed 25. Step one completed. Passed

2:26:39

Number two, you're going to subtract the number

2:26:42

that is formed with what we have outside

2:26:44

of the period. In this case only

2:26:47

We have a zero, therefore we are going to

2:26:48

subtract zero. Step number three, you are going to

2:26:52

place a nine for each digit

2:26:54

that period. In this case we have

2:26:57

1 2. We placed 2 nu 9 and 9. And we are

2:27:02

Ready. these 25/idos in 99.

2:27:07

And now we have it ready. Now the

2:27:10

next, 1.25 newspapers. Again,

2:27:13

Step number one, we write the number

2:27:15

complete without considering the comma or the

2:27:17

period. Then, step number two, he

2:27:21

We subtract the number formed with the

2:27:23

that we have outside of the period.

2:27:25

Obviously a whole number, no

2:27:27

We consider the comma there. In this case

2:27:30

We're going to subtract one and we're going to

2:27:33

divide into nines for each digit

2:27:36

that period. We have here 1 2.

2:27:39

So this is going to be

2:27:41

29 and this is 124

2:27:45

divided into 99 parts. And now we have it ready.

2:27:50

Now, what if we have a number

2:27:53

semi-periodic decimal? Okay, I'll change one here.

2:27:56

The third step was a little bit, but the logic

2:27:59

It's the same. Already. Step number one,

2:28:01

we write the complete number without

2:28:03

Do not consider the comma or these zeros.

2:28:05

It would be 25 and neither would the period

2:28:08

without even considering this little bar that

2:28:10

We have it here. We're going to subtract that from this

2:28:14

the whole number that is formed with what

2:28:16

is outside the period. Not here either

2:28:19

Let's consider the zeros that we're going to

2:28:21

to have at the beginning, nor the comma,

2:28:23

always from the first different digit

2:28:25

zero. In this case we only have one

2:28:28

two and we're going to divide it. And here it is

2:28:32

difference. We're going to put a nine out of ten.

2:28:35

each periodic figure. In this case

2:28:37

we have a single recurring digit, a

2:28:39

unique nine. And then we're going to place a

2:28:43

zero for each decimal point outside the

2:28:46

period. In this case, there is only one

2:28:48

decimal point outside the period. We placed

2:28:50

just one more and there we have it

2:28:53

list. Well, and here we would only have to wait

2:28:56

perform the subtraction. 25 - 2 23/

2:29:01

90.

2:29:02

Now let's move on to the next one. 1.25

2:29:06

newspaper. It's the same thing again.

2:29:09

We write the complete number without

2:29:10

consider the comma in the period. A 125

2:29:13

We still have. Step two, we subtract the

2:29:16

whole number formed with what

2:29:18

There are some outside the period. And in this case,

2:29:21

Remember that we don't consider the comma.

2:29:24

So, you put the digits 1 and 2 here.

2:29:28

in that order and we form the number 12.

2:29:32

And we're going to divide this into nine

2:29:36

for each recurring figure there is. In

2:29:38

In this case there is only one, and one zero.

2:29:42

for each decimal place that is outside of it

2:29:45

period. In this case, there is only one

2:29:47

single decimal place. Therefore, here

2:29:50

We perform the subtraction and we are left with 113

2:29:54

Born in 90 and we have transformed

2:29:57

our semi-periodic number as a fraction.

2:30:01

And now we have it ready. Now we're going to

2:30:04

remember a fundamental property

2:30:06

about rational numbers and it is

2:30:09

which reminds us that it's always between two

2:30:11

rational numbers that are different go

2:30:14

to exist an infinite number of numbers

2:30:17

rational among themselves.

2:30:18

For example, you know that two and the

2:30:21

Three are rational numbers, but what

2:30:25

happens? It happens because they are different numbers.

2:30:27

It will always be fulfilled as long as between them

2:30:30

There will be an infinite amount of

2:30:33

other rational numbers. For example,

2:30:35

These include 2.1 and 2.2.

2:30:40

2.35

2:30:42

2.39,

2:30:45

2.5, 2 eh 76, etc. is going to

2:30:51

there exists an infinite number of numbers

2:30:55

rational among themselves. Having seen

2:30:59

that property of numbers

2:31:02

Rational people, I want us to see something

2:31:05

An interesting thing that came out in the test.

2:31:08

The repeating decimal 0.9 is equal to 1.

2:31:12

Look, let's look at it from this perspective.

2:31:15

0.9 periodic is 0.99

2:31:19

and so infinitely nuo

2:31:22

I need to know if this equals 1. I'll do one for you.

2:31:26

ask. Is there any value between

2:31:30

These two numbers? Is there a number?

2:31:33

between them? And if you look for it, you won't find it.

2:31:36

find because there is no number

2:31:39

located between them. And since there is no

2:31:41

no number located between them, will

2:31:44

It will happen that these numbers are going to be

2:31:47

equal, they represent exactly the

2:31:49

same value. And in fact, you could

2:31:52

pass this 0.9 periodic fraction of

2:31:56

method or the way we had done it

2:31:57

seen previously. And look what's going to happen

2:31:59

occur.

2:32:01

The 0.9 periodic table is we write the 9 without

2:32:03

consider the comma in the period, le

2:32:05

We subtract the number that is formed outside,

2:32:07

which is zero. We divided it into nine

2:32:11

for each recurring figure we have.

2:32:14

In this case we only have one, which

2:32:16

It's going to be 9. And you'll end up with 9.

2:32:19

0 9 div 9. And 9 di 9 is = to 1, which is

2:32:26

exactly this value. In conclusion

2:32:30

I want you to answer the following:

2:32:32

Ask this question and leave it down here in the

2:32:35

comments.

2:32:37

The number 2.9 newspaper

2:32:41

It equals 3. Pause the video and write it down.

2:32:45

in the comments.

2:32:48

Now let's look at the methods of

2:32:50

comparing fractions. To do this,

2:32:54

Here in the description you will find a

2:32:57

video that I have prepared in a special way

2:32:58

for you, where I share different

2:33:01

methods for comparing fractions. There

2:33:04

You can use whichever one suits you best.

2:33:06

whichever one you like best. You watch the video and

2:33:09

then you later return to this

2:33:12

part of the summary to continue with the

2:33:15

subject.

2:33:17

Now we are going to study the operation with

2:33:19

fractions, particularly

2:33:21

beginning with the addition and subtraction of

2:33:23

fractions.

2:33:25

Here's what we're going to try to do

2:33:27

The goal is to find that when you have one

2:33:29

Addition or subtraction of fractions, let's leave everything

2:33:32

in the same fraction. That's the

2:33:35

an objective that we will try to achieve.

2:33:38

So, let's start with the first case, which

2:33:40

It's the simplest. When you add or

2:33:42

subtracting fractions that have the same

2:33:44

denominator, what one does is operate

2:33:47

the numerators and retains the

2:33:49

denominator. For example, here we have 4/

2:33:54

5 + 6/ 5. Since they have the same denominator,

2:33:59

1. What it does is preserve the

2:34:03

denominator and what operates are the

2:34:06

numerators. In this case, 4 + 6. 4 + 6

2:34:14

born in 5 and 10/ 5 results in 2.

2:34:20

And we have already resolved this operation. Of

2:34:23

In the same way, here we have a subtraction.

2:34:26

Since they have the same denominator,

2:34:29

We keep the denominator which is 6 and

2:34:31

We operate the numerators. 3 - 4 which is

2:34:35

ig a -1/

2:34:38

in 6. And now the operation is complete.

2:34:45

But what would happen, for example, if

2:34:48

Are the denominators different? Here you

2:34:53

I propose a little formula, so to speak,

2:34:56

how this is done. However,

2:34:58

I prefer that we look at it with examples for

2:35:00

so you don't have to memorize this. For

2:35:03

solve the addition and subtraction of fractions of

2:35:06

different denominator, I'll show you

2:35:07

two paths. The first path

2:35:10

We will call it the butterfly method and the

2:35:12

The second path will be an equalization

2:35:14

of denominators. Both paths lead you

2:35:16

They lead to exactly the same result.

2:35:20

Now, what is the first method like? He

2:35:22

butterfly method. What you're going to

2:35:24

To do this is to multiply the numerator of a

2:35:28

with the denominator of the other. By

2:35:30

For example, in the case of this subtraction, 5 * 3

2:35:33

It's 15. Now, what kind of operation

2:35:35

have? We have a subtraction. What

2:35:38

Do we subtract? The product of those who

2:35:41

There were some left over here, that is, the denominator

2:35:44

of the first with the numerator of the

2:35:47

second. 6 * 1, 6 divided into, attention,

2:35:52

the product between 6

2:35:57

and 3, that is, the product between the

2:35:59

denominators.

2:36:01

6 * 3 is

2:36:04

18.

2:36:05

So here it will be 15 - 6 which is 9

2:36:09

divided into 18.

2:36:12

In this case we can simplify

2:36:15

dividing both the numerator and the

2:36:17

denominator times the greatest common divisor

2:36:20

which is 9. 9/ 9 is 1. 18/ in 9 is 2. By

2:36:27

Therefore, we arrive at the result of

2:36:29

This operation is 1/2.

2:36:33

Now I want you to pause the video and

2:36:35

Apply this method with the following

2:36:37

fraction.

2:36:39

You have it perfect. In this case it's a 5

2:36:44

which is 5 + 4 * 3 which is 12 divided by 4

2:36:51

* 5 which is 20. Result 17. And that's it

2:36:56

We have a list. Now, what is the only

2:37:00

But in my opinion? Well, two buts

2:37:02

of this butterfly method. First

2:37:05

But, what happens when there are more than two?

2:37:08

Fractions can be a little tricky

2:37:11

Apply this method, since you will have

2:37:13

than to do it with the first two and then

2:37:15

You have to apply the result of that

2:37:17

the amount you are short, by

2:37:19

example. But it could also happen

2:37:21

case that when carrying out the

2:37:23

multiplications

2:37:24

you end up with quite large numbers and

2:37:27

then it may be necessary to simplify, and that can

2:37:30

be a little more complicated. Therefore,

2:37:32

What is the alternative route? Look, I

2:37:36

I told you there was a second method that

2:37:38

It is the equalization of denominators, which

2:37:41

It will generally lead you to

2:37:43

results that are easier to work with.

2:37:45

So, see how it works. I'm going to

2:37:48

see the denominators of my fractions,

2:37:49

In this case, 6 and 3. And I'm going to ask myself

2:37:52

as follows. What is the least common

2:37:55

What is the multiple of these two? Common minimum

2:37:58

multiple between 6 and 3. In this case it is the

2:38:02

same 6. Therefore, here it is enough to leave

2:38:05

This intact and here multiply by something

2:38:08

value in such a way that I am left with as

2:38:11

denominator 6 in the second fraction.

2:38:15

So I ask myself, hey, why

2:38:17

I must multiply the value by 3 so that I

2:38:19

6? Multiply by 2 and multiply by 2 above

2:38:22

and down. In this case we are left with 5/ 6 - 2

2:38:28

* 1, which is 2 divided into 3 * 2 which is

2:38:32

6. And in this case you keep the

2:38:35

denominator which is six because you are

2:38:36

Adding, well, subtracting in this case

2:38:38

fractions with the same denominator.

2:38:41

You keep the denominator and operate the

2:38:44

numerators.

2:38:46

5 - 2

2:38:48

5 - 2 and we are left with 3/6. In this case

2:38:53

We're going to have to simplify.

2:38:54

We simplify here by dividing by the

2:38:56

The greatest common divisor is 3. 3 / 3 is

2:39:01

1. 6/3 is 2. So we are left with 1/2 here.

2:39:06

and you arrive at exactly the same result.

2:39:09

Look, you applying this method of

2:39:11

Equalizing denominators does not imply

2:39:13

so that it doesn't have to be simplified later,

2:39:15

only you might work with

2:39:17

smaller values ​​and you don't have to

2:39:20

simplify so much. Taking into account

2:39:22

Therefore, we are going to apply this method to

2:39:25

the operation of three fractions that

2:39:27

We have it here. I can't wait for you to tell me which one.

2:39:30

is the least common multiple of 3, 4 and

2:39:34

6.

2:39:36

Obviously that requires practice, but

2:39:38

We've already seen methods of how that works

2:39:39

You can calculate it if you want.

2:39:41

View it manually. In this case, the

2:39:44

The least common multiple of 3, 4, and 6 is

2:39:46

12. Therefore, I will see to it that

2:39:48

each of these fractions has a

2:39:50

denominator 12.

2:39:52

To that end, I ask myself, hey, why

2:39:55

I must multiply the value by 3 so that I

2:39:57

12? Multiply by 4. And you multiply by 4

2:40:00

up and down. Now, at what value?

2:40:03

How do I multiply 4 to get 12?

2:40:06

By 3. I multiply by 3 both top and bottom.

2:40:09

Then, what value should I multiply by?

2:40:11

How do I use 6 to get 12? by 2.

2:40:14

We multiply by 2 both top and bottom.

2:40:17

So, taking all of this into account,

2:40:19

Here we will have 2 * 4 / 8 divided into

2:40:24

3 * 4 12 - 6 * 3 = 18 divided by 4 * 3

2:40:32

It's 12 + 5 * 2 is 10 and down here we

2:40:36

There are 12 left. Therefore, here I have one

2:40:39

operation, a sum and subtraction of

2:40:41

fractions with the same denominator.

2:40:43

We keep the denominator which is 12 and

2:40:45

We operate the numerators only.

2:40:49

8 - 18 + 10. Look, notice, 8 + 10 is 18

2:40:57

- 18 divided all this into 12

2:41:02

It's the same as having 18 - 18 which is 0

2:41:05

div and 0 div gives us 0 as a result. AND

2:41:10

That's how we've resolved this

2:41:13

operation. Like I said, it was also possible

2:41:16

Use the butterfly method, no

2:41:18

problem, but for that you would have to

2:41:19

to have done it, for example, here. Then

2:41:22

Add the result of this fraction to the

2:41:25

5/6 and maybe it would have taken longer.

2:41:28

I, in particular, already consider the cases of

2:41:31

addition and subtraction of two, sorry, three or more

2:41:34

fractions, I recommend equating the

2:41:37

denominators.

2:41:39

Now, something quite typical, the sum between

2:41:41

an integer and a fraction or the subtraction

2:41:44

between an integer and a fraction, which is

2:41:46

the same logic. Look, here I want you to

2:41:48

See it from the following perspective. If I

2:41:51

I have a whole number, that number

2:41:53

You'll always be able to rewrite the whole thing

2:41:55

like the whole divided by one, right?

2:41:58

1 divided by 1. And you are adding this to your

2:42:02

Adding up 3 games played in 5. Therefore, here we already

2:42:07

You are adding two fractions of different sizes

2:42:09

denominator. Therefore, you could occupy

2:42:12

any of the methods that already

2:42:13

We study. In this case, the method

2:42:15

butterfly. What would it look like?

2:42:17

1 * 5 5 + 3 * 1 3 divided into 1 * 5, which

2:42:26

It's 5 + 3 is 8/ in 5 and we have it ready.

2:42:34

Nothing more than that. You could do that too

2:42:37

with the equalization method of

2:42:39

denominators. Look, let's see here a

2:42:42

example. Well, this same example.

2:42:45

Here I have denominator 1 and denominator 5.

2:42:49

Least common multiple 5. Therefore, here

2:42:53

I amplify by 5 up and down. Us

2:42:56

It will remain here 5/ in 5 + 3/ 5. Sum of

2:43:03

fractions with the same denominator.

2:43:06

You keep the denominator which is 5 and

2:43:08

You operate the numerators. 5 + 3 is 8.

2:43:12

We arrived at exactly the same conclusion. Now,

2:43:15

Look, I usually when I do

2:43:17

This, and this is the way that I

2:43:19

It is more convenient and faster to avoid

2:43:21

having to do so much

2:43:22

Development is simply doing this,

2:43:24

But this is already the trick and the way that

2:43:26

I do it. I multiply the whole

2:43:30

by the denominator. 1 * 5

2:43:33

I add what we had here in the numerator

2:43:35

which is 3 born in 5.

2:43:41

and you arrive at exactly the same thing. If that

2:43:44

If you find this trick convenient, there's no trick.

2:43:46

problem, occupy it or if you don't occupy the

2:43:48

alternatives that I showed you

2:43:50

previously. It has different forms

2:43:52

to arrive at exactly the same

2:43:54

result. Personally, I apply

2:43:56

This trick works 99.9% of the time

2:43:59

of the times. Now we are going to study the

2:44:02

multiplication of fractions. When you

2:44:04

You are multiplying two or more

2:44:06

fractions, what one does is

2:44:08

multiply the numerators together and

2:44:12

You divide it into the product among the

2:44:15

denominators with each other. So, because

2:44:18

For example, here you have 3/2 * 11/7.

2:44:21

We multiply numerators. 2 * 11 22

2:44:26

divided into 3 * 7 21. And we have it

2:44:30

ready.

2:44:32

So, what's happening here? In the fraction

2:44:35

What's coming, we have a 12/5 * 25/4. And

2:44:41

Look, let's solve it by applying what

2:44:44

we saw earlier. I'm going to multiply

2:44:47

12 * 25 and this gives you 300.

2:44:51

And we divide this into 5 * 4, which gives us

2:44:56

There are 20 left. And what's the problem with that?

2:44:59

arrive and multiply many times? That

2:45:02

Many times we will then have to

2:45:03

to perform divisions or simplifications

2:45:06

from the results we obtain. And so

2:45:09

It might complicate things a bit. Here

2:45:11

Good luck, I know that 300 is divisible by

2:45:14

20, which in fact will look like this for you

2:45:16

Result 15. However, there is a way

2:45:21

to avoid having to simplify

2:45:23

all the time.

2:45:25

And the trick to avoid having to simplify

2:45:28

all those big numbers that we

2:45:30

The last thing they are left with is trying to simplify.

2:45:34

before multiplying. I want that

2:45:37

always keep that rule in mind. Before

2:45:40

to arrive and multiply fractions,

2:45:42

Let's try to simplify as much as possible.

2:45:45

if possible. Now, where can we

2:45:49

simplify? First, if the

2:45:52

fraction allows it, within the same

2:45:54

fraction, if it is reducible,

2:45:57

but also to the extent that it

2:46:00

If possible, you can simplify

2:46:03

the numerator of a fraction with the

2:46:06

denominator of the other.

2:46:10

So here, if you look,

2:46:13

You can simplify the 12 with the

2:46:16

four, since both are divisible by

2:46:19

four. So, you always have to

2:46:22

Simplify by dividing the two values

2:46:25

that you're going to try to simplify.

2:46:27

So, look,

2:46:30

If I divide 12 * 4, what will we get?

2:46:32

is left over? 3. Perfect. And here I also have

2:46:36

which divide by 4.

2:46:39

It's 1. And we have that simplification

2:46:42

list. Similarly, in a

2:46:44

Crossing the 5 with the 25, I can

2:46:47

Simplify by dividing by 5. Here, 5 = 5

2:46:51

We have 1 left. And 25/5 leaves 5. And

2:46:56

Finally, what does one do?

2:46:59

multiply these remaining numbers

2:47:02

here after having simplified.

2:47:04

So, this is going to be 3 * 5, which will

2:47:09

be our new numberers. This is going

2:47:11

to remain 15 divided into the product of

2:47:15

the new denominators that will be 1

2:47:19

and 1. And 1 * 1 is 1. 15/ 1 is 15. And already the

2:47:26

We have a list. The key to simplifying

2:47:29

It's about being very organized. In this case,

2:47:32

I left it with colors so that it would be

2:47:34

could see. If you are tidy or

2:47:36

ordered with the simplifications, the

2:47:39

You'll get questions about fractions

2:47:40

make them simpler.

2:47:43

Now it's time to remember a

2:47:45

fundamental concept

2:47:47

in mathematics, which is the inverse

2:47:50

multiplicative or also called

2:47:52

reciprocal. If we have a number

2:47:55

n not equal to zero, its inverse

2:47:59

multiplicative or reciprocal is the number

2:48:02

which when multiplied by n gives us as

2:48:05

Result 1. This number will always

2:48:08

be given by 1 match in n again

2:48:12

with n not equal to 0. So here

2:48:15

Again, if I multiply a number

2:48:17

with its multiplicative inverse or also

2:48:19

called reciprocal, the result will be

2:48:22

1. Look, notice here you are multiplying

2:48:25

n. n is the same as n born in 1 * 1/

2:48:29

n. And this, notice that it is the same as 1

2:48:32

* n, which is n, divided into 1 * n, which is

2:48:37

n, and n born at n is 1. Therefore,

2:48:42

Let's look at some examples of it here.

2:48:45

multiplicative inverse.

2:48:47

Yes, 3, its multiplicative inverse, is

2:48:50

1 game in 3. The 5 is 1 game in 5. And

2:48:55

Here we have the 3rd in 5. Look, from

2:49:00

For now, I want you to keep this in mind

2:49:02

following. If I have a number, your

2:49:04

The reciprocal is 1/ido in n, right? Further

2:49:07

We'll see what happens when I have

2:49:09

I divide a whole into a fraction. Of

2:49:11

For now, I just want you to have in

2:49:13

He says that what one does is turn around

2:49:16

to the fraction. In this case, you would have

2:49:19

5/

2:49:21

3. For now, I want you to stay with

2:49:23

that. We'll explore in detail why that is.

2:49:27

occurs. And now let's look at the operation

2:49:30

that we were missing, which is the division of

2:49:32

fractions. In the division of

2:49:34

fractions, we can change the

2:49:37

divisor times its multiplicative inverse,

2:49:40

In other words, we turn it over and operate

2:49:43

as if it were a multiplication.

2:49:46

Look, here we had a divided b

2:49:49

in C/ido in D. This will be equivalent

2:49:53

to have given birth in B multiplied by

2:49:56

the reciprocal of this fraction, which in

2:50:00

This case would be the fraction

2:50:02

The game was turned around in C. And then

2:50:06

we operate just as it is done in a

2:50:08

multiplication.

2:50:10

So, let's look at an example that

2:50:11

encapsulates all the operations that

2:50:13

we have learned so far.

2:50:17

So, look, here we have this

2:50:19

operation. We're going to follow the silent papo

2:50:21

And we're going to resolve what's inside.

2:50:23

from the parentheses. Since it is a subtraction of two

2:50:26

fractions, I'm going to use the method of

2:50:27

the butterfly. I have here 5 * 4 20 -

2:50:34

6 * 7 42

2:50:38

divided into 6 * 4 which is 24

2:50:44

divided into 11/ into 3. Let's continue. It

2:50:48

I'm going to leave it with this color.

2:50:51

20 - 42 is -22

2:50:56

divided into 24.

2:50:59

All of this divided into 11/3. Like

2:51:04

Here we find a division of

2:51:08

fractions, what I'm going to do here is

2:51:10

Take my -22/24 and multiply it

2:51:16

by the reciprocal of the fraction by the

2:51:19

which we are dividing. In this case,

2:51:21

We simply reverse the fraction and

2:51:25

We have 3 matches left in 11. And here, like

2:51:30

we have a multiplication of

2:51:31

fractions, let's simplify them

2:51:34

to the extent possible. Attention and

2:51:37

Careful, we have a number here

2:51:38

negative. I'm going to write it in a way

2:51:40

more organized so that there is no confusion.

2:51:43

Here we have a -22

2:51:46

divided into 24. Already. Then we'll see if

2:51:51

we can cross simplify or

2:51:53

within the same fraction as you

2:51:54

accommodate. In this case, I'm going to do it.

2:51:56

in a cross fashion. For example, we can

2:51:58

Simplify 24 by dividing 3

2:52:02

times 3. Here 3/3 is 1. 24/3 is 8. From the

2:52:09

In the same way, I can simplify the

2:52:12

-22 with 11 dividing by 11. 11/11

2:52:18

is 1. -2/

2:52:21

11 is -2.

2:52:24

For the purposes of this explanation, I now

2:52:27

I'm going to rewrite it here with the new ones

2:52:29

numerators and denominators that we

2:52:31

They remained. Here the numerator is -2

2:52:35

divided into denominator 8 by numerator

2:52:39

1 divided by a denominator of 1. And here I have

2:52:42

a 1-on-1 match which is the same as

2:52:44

Multiply by 1. And 1 times this value is

2:52:48

simply the same value. And here

2:52:51

Notice that we can continue simplifying.

2:52:54

For example, I could simplify -2

2:52:56

with 8 dividing by 2.

2:53:00

And if we do that, we'll be left with

2:53:02

Dividing by 2 we get -1.

2:53:06

Dividing 8 by 2 gives us 4.

2:53:09

So we are left with -1/

2:53:13

And we have it ready. As a tip too

2:53:16

You can simplify sooner, but when? As

2:53:19

I told you, it was for the purpose of the

2:53:20

I explained that I did this so that...

2:53:22

see the effective result you are aiming for

2:53:24

to arrive. But you too could

2:53:26

What to do was simplify this -2 with the

2:53:32

corresponding denominator that was going

2:53:34

to stay here, which was eight. So, you

2:53:36

You could simplify here by dividing by

2:53:40

two again. Here you had -1, but

2:53:44

The colors didn't turn out well. Give me a

2:53:46

second. Let's do it with this color.

2:53:48

Already. So, we simplify by dividing

2:53:50

For 2 you got -1. Dividing by 2

2:53:53

There were 4 left. So, what was happening here? -1

2:53:57

* 1 - 1 divided into 4 * 1 4 and we arrived

2:54:06

exactly the same result.

2:54:09

Now let's remember what the

2:54:12

ear rule. And that's because many times

2:54:15

The division between fractions will be

2:54:18

represent in the following way. a

2:54:20

fraction, let's say, a divided by b

2:54:24

in another fraction, let's say c divided into

2:54:26

D. The ear rule tells us that

2:54:29

We can multiply these here

2:54:32

extremes, in this case A * D, and

2:54:37

place it in the numerator

2:54:41

and divide it into the product between these

2:54:45

which we have in the middle, in this case B *

2:54:48

C. This is equivalent.

2:54:51

Now, one very important thing, this is not

2:54:54

It's nothing new because what we have

2:54:56

Here it's the same as having given birth to B

2:54:59

divided into C, which is part of D. So, here

2:55:03

We have a division of fractions. This

2:55:05

is the same as A * B. A born in B,

2:55:09

Sorry, because of B matched to C. And here's this

2:55:12

We're going to be left with * Divided

2:55:15

In B*C, it's exactly the same, but

2:55:18

to avoid doing all these steps,

2:55:21

We use the ruler of this little ear.

2:55:25

Now, let's look at some examples. Here we have

2:55:28

These two fractions that are being

2:55:30

dividing among themselves. So

2:55:33

we multiply the extremes,

2:55:35

We'll end up with 5 * 4 divided into the

2:55:41

product among those we have in the middle.

2:55:44

12 * 15. Now, as always, before

2:55:49

Let's try to simplify the multiplication.

2:55:52

You must remember that when in a

2:55:55

We only have a fraction of products.

2:55:58

between factors, both in the numerator

2:56:00

as in the denominator, we can

2:56:02

simplify as much as possible

2:56:04

possible. For example, you can simplify

2:56:08

5 with 15 dividing by the maximum

2:56:12

The common factor is 5. Here you go

2:56:14

one and here you have three. From the same

2:56:17

one way you can simplify 12 with the

2:56:21

factor 4, since if both of them

2:56:24

We divide by 4, so here we'll have 1 and

2:56:27

Here we'll have 3. So, here we are

2:56:29

would remain 1 * 1

2:56:34

divided into 3 * 3 which is 9. And that's it

2:56:40

We have a list. Now we're going to look at some

2:56:43

examples. For example, here we have the

2:56:46

division between these two fractions.

2:56:50

To solve this operation,

2:56:52

We will simply use the rule of the

2:56:54

ear. We multiply the extremes with

2:56:57

the extremes. In this case we have 5* left

2:57:02

4 divided into the product among those that

2:57:07

We have the middle one. In this case 12 * 15.

2:57:14

Already. So here before multiplying

2:57:18

Remember that we can simplify. By

2:57:22

that? Because when you only have

2:57:24

the product between factors, both in the

2:57:28

numerator as in the denominator,

2:57:30

we can simplify with

2:57:33

certain factors. For example,

2:57:35

Obviously, it's whatever measure is possible.

2:57:37

Look, let's look at a practical example. Here

2:57:40

You have the 5 and you have the 15.

2:57:44

Both factors are divisible by 5.

2:57:49

So here we're going to divide both by

2:57:51

5.

2:57:54

1 left.

2:57:58

There are 3 left. And we've already simplified to

2:58:01

minus those factors. Now, what happens?

2:58:04

here? Have

2:58:07

12 and you have the four. Both factors

2:58:11

are divisible by four. So, I

2:58:13

Here I could divide both by four and

2:58:16

We'll have one left here, and here we'll...

2:58:19

three to remain. So now only

2:58:22

We multiply because we can't continue

2:58:23

simplifying. We multiply 1 * 1, we get

2:58:28

The result will be 1, divided

2:58:32

in 3 * 3, which will give us 9 and the

2:58:37

The result will be a ninth place.

2:58:40

Now let's see what happens when

2:58:43

We divide, for example, an integer into a

2:58:46

fraction. Now, how do I know that we are

2:58:48

Dividing an integer into a fraction?

2:58:50

Simple. Here in this operation, look

2:58:55

that the largest dividing line you

2:58:58

separate this whole number from the fraction that

2:59:01

We have it here. So, what's the key?

2:59:04

to solve this division and how

2:59:06

What could we do? simple. Look, this

2:59:09

I'm going to rewrite the whole thing too.

2:59:11

as a fraction. Remember that five is

2:59:14

You can write it as a fraction like 5

2:59:16

It came to 1, and all of this divided into 15

2:59:21

Born in 4. So, now we do use

2:59:25

the ear rule. 5 * 4

2:59:30

divided into 15 * 1, which directly gives

2:59:35

15.

2:59:36

Now we're going to simplify the 15 with

2:59:41

Dividing 5 by 5 gives you 1, and here

2:59:45

You have 3 left. So 1 * 4 is 4 divided

2:59:52

in this 3 that we have here. Therefore, it

2:59:57

We have it ready. I told you before that

3:00:01

if we had a fraction and

3:00:04

we would take its inverse

3:00:05

multiplicative, what we did was give

3:00:07

return to the fraction. Now we'll see why

3:00:10

what happens. Look, let's suppose that I

3:00:11

It had the fraction 5 divided into 3 and therefore

3:00:16

as I told you before, its reciprocal or

3:00:18

The multiplicative inverse is the fraction

3:00:21

turned upside down. But why? Because

3:00:24

definition, if I have a number, that

3:00:26

In this case it is 5/3, its inverse

3:00:29

multiplicative is 1 divided by that

3:00:32

worth. And what was that value? A 5/3.

3:00:37

And here we apply exactly this logic.

3:00:40

Look, the integer 1 can be rewritten

3:00:44

Since fraction 1 resulted in 1. Therefore

3:00:47

Therefore, we use the 3 * 1 rule of thumb

3:00:50

We were left with 3 divided by 5 * 1, which is

3:00:54

5. Therefore, what happened was that

3:00:57

the fraction was turned around. Obviously

3:01:00

Here we saw the step-by-step process, but when you

3:01:03

They ask for the reciprocal of a fraction, you

3:01:04

You simply turn around and there it is

3:01:07

We have a list. Finally, we're going to see the

3:01:10

ownership of the lock. What does it tell us?

3:01:13

as follows? When performing the operation

3:01:16

of addition, subtraction, multiplication and

3:01:18

division, except division by cer

3:01:21

between two rational numbers, the

3:01:24

The result is always a rational number.

3:01:29

For example, if I add the fraction 1/2

3:01:33

with the fraction 3/, the result of this

3:01:37

It's going to be, we keep the denominator that

3:01:39

It is 2. 1 + 3, 4. 4/2 is 2 which is a

3:01:45

rational number. Remember that the

3:01:47

All integers are rational.

3:01:50

Now, the same thing happens with subtraction,

3:01:53

exactly the same. The same with the

3:01:55

multiplication. For example, if I

3:01:56

I multiply 3/ 2 * 4/ by 5, here I'm not going to

3:02:02

simplify, but directly it would be

3:02:05

3 * 2 12/ 5 * 2 10 and has the division

3:02:09

between two integers. Therefore, this is

3:02:12

a rational number.

3:02:15

The division applies exactly the same way.

3:02:17

same, except for a division by cer.

3:02:20

What do I mean by this? Look, if I

3:02:23

For example, if it were to divide 2/3 by 0,

3:02:29

I'm here dividing two numbers

3:02:31

rational, but I'm dividing by

3:02:34

and division by cer are not

3:02:37

defined in the real numbers. Therefore,

3:02:41

here excepting a division by cer

3:02:45

all the operations that I just told you

3:02:46

They will always mention that they will give as

3:02:48

result in a rational number. Now

3:02:52

We are going to study mixed numbers,

3:02:55

where you know that a mixed number looks

3:02:57

as follows. Here you have it

3:02:59

the whole part and you'll also have the

3:03:03

fractional part. Let's look at some here

3:03:06

examples. Look, let's get to work now.

3:03:09

to convert this mixed number to a

3:03:13

fraction as such. How do we do it?

3:03:16

Look, here's the whole part:

3:03:20

five and the fractional part is 1/2. Tea

3:03:23

I'm going to show you the most step-by-step way and

3:03:26

Then I'll show you the fastest way.

3:03:29

Let's begin with the most step-by-step approach.

3:03:31

Look, for positive mixed numbers,

3:03:33

Simply put, what we do is take the

3:03:36

whole part and add the part

3:03:39

fractional.

3:03:41

In this case you get 5 + 1/2. Now

3:03:46

It is adding an integer, which is 5 with a

3:03:49

fraction that is 1/ido in 2. Therefore, of

3:03:52

I'm going to rewrite this 5 as a

3:03:55

fraction, like a 5 divided into 1.

3:03:58

So I'm going to make the denominators the same.

3:03:59

And for that, I multiply by two here.

3:04:02

the numerator as the denominator. You're going

3:04:05

to remain 10/

3:04:07

2 + 1/ 2. Addition of equal fractions

3:04:12

denominator. I keep the denominator.

3:04:14

I add the numerators. 10 + 1 will give us

3:04:18

Stay here 11. And this is exactly what

3:04:21

same as 5.5 if you perform the

3:04:24

division. Therefore, here we have

3:04:27

represented as

3:04:28

fraction and at the same time this fraction

3:04:30

then if we perform the division we

3:04:32

The resulting number remains,

3:04:35

which is the number 5.5.

3:04:38

Now there are 1000 more ways to do this

3:04:40

fast. For example, you know that you

3:04:42

You have the five, you are the five

3:04:46

adding one half and one half if you

3:04:47

You perform the division and it will give you as follows:

3:04:49

The result is 0.5 and 5 + 0.5 is 5.5. Sale

3:04:54

much faster. Now I told you that

3:04:57

There is a way that I, at least, do to

3:04:59

quickly convert the mixed number to

3:05:01

fraction. What I do is

3:05:03

following. I take the whole part, the

3:05:05

I multiply by the denominator. It already gives us

3:05:09

5 * 2, 10 plus the numerator which is 1 and it

3:05:12

we divide in the denominator. So

3:05:15

Here we have 10 + 1, 11 divided by 2 and

3:05:19

We are king. As I said, there are several

3:05:22

forms. Do it however works best for you.

3:05:24

more comfortable. If it comes out faster and that's you

3:05:26

It's more comfortable, great. If so

3:05:28

If you want to do it more step by step,

3:05:29

no problem. Already. Pay attention here for

3:05:34

avoid mistakes. What happens when I have

3:05:36

Negative mixed numbers? What about

3:05:39

This one less? Yes, fundamental. This one less

3:05:43

It includes all this little number I have

3:05:47

Here, it's not just number five, it includes...

3:05:50

everything we have. Therefore, here

3:05:54

Simply put, what one does is take

3:05:56

the least and here the mixed number

3:05:59

work as if it were positive within

3:06:02

a parenthesis. For example, here's what you need.

3:06:04

5 + 1/2, right?

3:06:08

So here it's less. We already saw that

3:06:11

This leaves 11 games in 2, then the

3:06:15

The result is -11, split in 2. Nothing more

3:06:21

That's it. I suggest you leave those alone

3:06:23

parentheses so you never make a mistake.

3:06:26

Now, what is the most common mistake? And you

3:06:29

I'm going to mention it here. Yes, this is the

3:06:32

The most common mistake, which is the least only

3:06:36

Give it to the whole part, that is,

3:06:40

Ah, I see, I have a -5, I multiply it

3:06:42

Multiplying by 2 gives me -10, so I add the numerator

3:06:46

which is 1 and I divide it by 2 and this gives me

3:06:49

-9/ 2. But this question is wrong. That

3:06:54

The process is not correct. The correct one

3:06:57

It's the one I just mentioned here.

3:07:01

Finally, we're going to look at the fraction of a

3:07:03

number. How do we calculate the fraction of

3:07:06

any value? And this is simply

3:07:08

multiply the number by the fraction

3:07:10

that they ask of you. For example, let's suppose

3:07:12

They're asking you what 5/ths of 36 is. Here

3:07:19

All one does is multiply the

3:07:21

value for the fraction they ask for, which

3:07:24

It's 5/12. Remember that before

3:07:28

You can simplify multiplication. If you

3:07:30

It fits a size 36, you could put a size 36 on it

3:07:33

Part 1 so you can visualize it as

3:07:36

a fraction, but it's not necessary. Already

3:07:39

In this case, I'm going to leave it like this. Look,

3:07:42

we can cross-simplify the

3:07:43

36 with 12 dividing by 12. Here you go

3:07:47

There's one left, and here you have 3. So go

3:07:51

Since 3 * 5 we get 15 divided into 1 *

3:07:59

1 which is 1 and 15/ 1 is only 15 and that's it

3:08:05

We have it ready. Like I said, it's not

3:08:08

It's not necessary to write this one, it's not

3:08:11

requires.

3:08:12

So, look, here in the next one we

3:08:14

They're asking what 4/7 of 5 is. Okay.

3:08:17

We multiply 5 * 4.

3:08:21

We can't simplify things here, so

3:08:22

Let's multiply directly. When

3:08:25

multiply an integer by a fraction,

3:08:27

You simply multiply the integer by the

3:08:29

numerator. In this case, we have 20 left. And

3:08:33

you divide it by the denominator that

3:08:35

we had here. This is exactly what

3:08:38

same. Having written the 5 as a 5

3:08:41

split into 1 and multiply 5 * 4 20. 1 *

3:08:45

7. It's exactly the same. But, for

3:08:47

Why are we going to be writing that?

3:08:49

There's no need. Already. What is 2/5 of

3:08:54

2/3 of 60? Typical question that might

3:08:58

to go out on a rehearsal or test.

3:09:00

Simple. Here we're going to keep multiplying.

3:09:03

We multiply everything.

3:09:06

2/3 of 60 is 60 * 2/3. And if all this...

3:09:11

We want to find 2/5, we multiply everything

3:09:13

This is for 2/5. Basically we multiply

3:09:17

all. And now, before we multiply,

3:09:20

As always, let's try to simplify in

3:09:22

to the extent possible. For example,

3:09:25

You can simplify the 3 with the 60

3:09:27

Dividing by 3. 1 remains, and here it is

3:09:31

20.

3:09:32

Now you can also simplify this 20

3:09:36

with this COC that we have here. dividing

3:09:38

Multiplying by 5 gives you 1, and here dividing by 5

3:09:42

You have 4 left. And finally we multiply

3:09:46

because we cannot continue simplifying.

3:09:48

So here we have 4 * 2 * 2. 4 * 2 = 8

3:09:55

* 2 is 16 divided into 1 * 1 which is 1 and

3:10:02

16/1 is simply

3:10:06

16.

3:10:08

And that's how the fraction is calculated.

3:10:11

a number. It's important that you have in

3:10:14

It is understood that simplification is not necessary.

3:10:17

Here, but it is desirable because that way you

3:10:21

You then avoid ending up with very large numbers

3:10:23

large ones here and have to simplify them.

3:10:25

You arrive at the same result, but in a different way

3:10:28

faster, simplifying here.

3:10:32

Now we're going to learn how to solve it step by step.

3:10:34

I'll pass on the questions from this content that

3:10:37

They might come out in peace. To do this,

3:10:40

Go down to the description and you'll find them.

3:10:42

to find all the questions and then

3:10:45

return to this part of the video so that

3:10:48

Let's keep learning.

3:10:50

And we begin the summary of percentages,

3:10:53

where we will learn the fundamentals for

3:10:56

that you can answer every question that comes to you

3:10:58

appear in the test. First of all,

3:11:01

We must remember what it means.

3:11:03

percent symbol. And it's that every time

3:11:06

I want you to find it.

3:11:08

Remember that this is equivalent to a 1

3:11:12

match in 100.

3:11:15

So, if you come across a

3:11:17

percentage, for example, like 25%,

3:11:22

this 25%

3:11:24

is equivalent to 25 * 1/ in 100 and 25 * 1/ is

3:11:34

25/100.

3:11:37

So, we have expressed this

3:11:39

percentage as a fraction and of the

3:11:44

You can express it in the same way as

3:11:47

a fraction,

3:11:49

If you perform the division, you can

3:11:52

express as a number, for example,

3:11:54

decimal. If I divide 25 by 100, this is

3:11:59

0.25.

3:12:01

[Music]

3:12:02

And we have now expressed the percentage

3:12:06

as a decimal number.

3:12:09

Now, how do we calculate

3:12:12

percentages?

3:12:14

The truth is that there are many ways,

3:12:17

There is no single way to do it.

3:12:20

I'm going to show you two paths. The first

3:12:22

It's going to be multiplied and the second one is going to

3:12:25

to be using the famous rule of three.

3:12:29

We'll start with the first way. Look,

3:12:33

20% of 50 is already path one. The path

3:12:39

One involves taking 50

3:12:42

and multiply it

3:12:44

for this 20%.

3:12:47

As we learned earlier, this 20%

3:12:51

can be expressed as a fraction or

3:12:54

as a decimal number. I recommend

3:12:57

To work on it in this case, the way you

3:12:59

more comfortable, than for me

3:13:01

particularly it's like a fraction,

3:13:04

because that way we can try to simplify.

3:13:07

So here we would have 50 * 20%

3:13:12

It's the same as 20 born out of 100.

3:13:17

Therefore, here we will try

3:13:21

simplify.

3:13:23

Here I can simplify, for example, from

3:13:25

cross shape the 50 with the 100

3:13:28

Dividing by 50. Here we get 1 and here

3:13:32

There are two left. On the other hand, we can now

3:13:35

simplify within this same

3:13:38

fraction too. For example, here

3:13:41

We can simplify the 2 with the 20

3:13:44

Dividing by 2, here we'll have 1 and

3:13:48

It will end up being 10 here. Therefore, here

3:13:52

All that remains is to multiply 1 * 10 is 10

3:13:58

divided into 1 and 10 div.

3:14:04

And we have the result ready.

3:14:09

Now, if we want to do it with the

3:14:11

famous rule of three, how are we going to

3:14:14

do? Okay, here we're going to put that

3:14:16

The result was 10.

3:14:19

Look, using the rule of three, we

3:14:22

We're going to say the following. In this

3:14:24

In this case, our number is 50, right?

3:14:28

We have our 50 and we're going to say that

3:14:32

50 is equivalent to 100%

3:14:38

which represents the total. When you speak

3:14:41

By 100% you mean the entire total

3:14:45

and we want to determine the

3:14:48

number, let's call it x, that represents

3:14:53

20% of this value. So, how

3:14:58

We worked on the rule of three for the

3:15:01

percentages?

3:15:02

Simple. Here we're going to take the value that

3:15:06

we do not know, in this case, who

3:15:08

we call it x.

3:15:11

And this value will be equal to, lend

3:15:13

attention, the product

3:15:17

crossbreed of these that I know in this

3:15:20

case is 50 multiplied by 20%

3:15:28

divided into the one that remains alone, which is

3:15:32

100%.

3:15:36

Now one can simplify these

3:15:40

percentages because remember that the

3:15:44

percentage is equivalent to having a number

3:15:47

Which is 1 multiplied, right? 1

3:15:54

multiplying and here you are cancelling

3:15:58

this common factor. Therefore, here it is

3:16:00

They can simplify.

3:16:03

So this is all we're left with. Now

3:16:07

Let's try to simplify now

3:16:10

because we have the product between

3:16:11

factors and here we are dividing by

3:16:13

100. Let's note that we can simplify

3:16:16

50 divided by 100 equals 50

3:16:19

1 and here it is 2. And we can also

3:16:23

Simplify the 2 with the 20. Dividing

3:16:26

Dividing by 2 gives 1. Dividing by 2 gives

3:16:30

10. Therefore, 1 * 10

3:16:35

divided into the 1 that remains here and 10 stop

3:16:39

1 is 10. And we arrive at exactly the same

3:16:43

result.

3:16:45

Now we're going to do

3:16:50

the second case we have below, the

3:16:52

second exercise. Already. Here I'm going to

3:16:55

solve it the first way, but if

3:16:57

You want to do it with a rule of

3:16:59

Three, no problem.

3:17:01

So, 30% of 120 is, let's see, now,

3:17:07

120

3:17:09

multiplied by

3:17:12

30%.

3:17:16

So here, let's note that this 30% is

3:17:21

can be expressed as 30 in

3:17:26

100.

3:17:27

So here, before arriving and

3:17:29

Let's try to multiply as much as possible.

3:17:32

simplify. For example,

3:17:35

we could simplify within the same

3:17:37

fraction divided by 10. Here we get 3

3:17:40

And there are only 10 left here. Also

3:17:43

we could simplify crosswise

3:17:46

the 10 that we had left here in the

3:17:48

denominator with 120 dividing by

3:17:51

10. This is left as 1 and this is left as 12.

3:17:57

So, let's finish this. 12 * 3 is 36

3:18:03

divided into the number we have here and

3:18:06

36/1 is only 36.

3:18:10

And that's how we have it. Now you

3:18:14

I'm going to give a little tip for calculating

3:18:16

percentages. Look, we're going to solve this here.

3:18:20

exactly the same, but remembering the

3:18:22

following. Look, always keep this in mind

3:18:25

that when I calculate 10% of a value

3:18:31

This is equivalent to taking that value and dividing it

3:18:34

by 10.

3:18:36

So, for example, if I have the

3:18:38

50, 10% of 50 is 50, which gives 10, which is

3:18:44

5. So here I am calculating the

3:18:48

20%, which is double 10%.

3:18:53

So, since 10% is 5, double that

3:18:56

5 is 10. And we have it ready. Look, here

3:19:01

We apply the same logic. 10% of 120 is

3:19:06

12. Then I want to calculate 30%.

3:19:10

30% is three times 10%. Therefore,

3:19:15

What is three times 12? 36. and

3:19:19

We arrived at exactly the same conclusion.

3:19:23

Now, suppose we are asked to calculate

3:19:25

100% of a value. Look, let's apply the

3:19:29

same logic we were using. Already.

3:19:32

100% of 500 is 500 times 100%.

3:19:38

and 100% is equivalent to having 100 divided into

3:19:43

100 and 100 say 100 is 1 and 500 * 1 is 500

3:19:50

Therefore, simply 500. So,

3:19:53

When you calculate 100% of a number,

3:19:57

It's simply that number, because

3:19:59

You're taking the total, no more and no less.

3:20:04

But what would happen, for example, if you

3:20:07

Do you want to calculate 200% of a number?

3:20:10

Okay, look, let's do it the same way.

3:20:12

that we've been doing.

3:20:15

I have 500 multiplied by 200%

3:20:20

And you know that 200% is equivalent to 200.

3:20:25

divided by 100. Therefore, here 200

3:20:30

Say 100, what is the total? 2. So I have

3:20:34

500 * 2 and 500 * 2 is simply

3:20:40

1000. Therefore, 200% of a number

3:20:45

It is double the number. Now, if we

3:20:48

They asked, for example, for 300%

3:20:52

Out of 500, I want you to tell me which one

3:20:56

That would be the result.

3:20:59

And as you probably already know, 300% of this number

3:21:03

It would be three times a number.

3:21:05

In this case, three times, sorry, the

3:21:08

Triple 500 is 100. I'll do it again.

3:21:12

Here's the development. 500 * 300% which is the

3:21:15

same as 300/gone in 100. 300/100 is 3.

3:21:19

And 500 * 3 is simply 1500.

3:21:23

We're ready with the calculation. Now

3:21:26

Let's answer this question, PES, with someone

3:21:29

of the methods we have learned. In

3:21:31

In this case, what is 15% of 60,000?

3:21:36

We've been doing it with it the whole time.

3:21:37

multiply. You probably already

3:21:39

You handle it with the rule of three, so I

3:21:41

I'm going to do it with the trick. So,

3:21:44

See how the trick works. Here

3:21:47

I want 15% of 60,000 and we'll do it.

3:21:52

Same as always. 10% of 60,000, how much?

3:21:54

is? Divide it by 10 and you get 6,000. AND

3:21:58

Since 15% is greater than 10%, this tells you

3:22:03

It leads to discarding A. It leads you to

3:22:05

Discarding B leads you to discard the

3:22:07

C and the correct one is D. But why?

3:22:11

D and how we can calculate it with the

3:22:13

clever trick? Look, it's simple. 15% is what

3:22:16

same as 10% plus 5%. I mean, I know

3:22:22

that 10%

3:22:24

My number is 6,000 and I have to

3:22:27

add 5%. 5 is half of 10.

3:22:31

Therefore, here 5% is half of

3:22:36

6,000. In this case it would be 3000

3:22:40

and 6000 + 3000 is 9000 and we have it

3:22:45

list. Like I said, you could do it too

3:22:47

do by multiplying using the rule of

3:22:49

three. Exactly. You arrive at the same

3:22:52

result, but in your case, it helps

3:22:55

It saves a lot of time.

3:22:59

Let's look at another example. If 30% of x

3:23:03

It is 6, so the value of x is Ya. For

3:23:09

To answer this question, I will tell you

3:23:10

I would recommend, based on what we have learned,

3:23:13

use only the rule of three. It is also

3:23:16

You can put together an equation if that suits you.

3:23:19

but at the moment we have not studied the

3:23:20

equations, so I'm going to do it with

3:23:23

TR rule. Yeah, look, here you have to be

3:23:26

very tidy.

3:23:28

So, look, we have here that 30%

3:23:30

The number of a certain number x is 6. There is already a certain

3:23:34

value x that will correspond to the total,

3:23:39

100%

3:23:42

And I know that 6 corresponds

3:23:46

at 30%

3:23:49

of that value. As a tip, remember that

3:23:54

On one side you're going to place the numbers in

3:23:57

the rule of three and on the other side the

3:23:58

percentages and that way you'll never

3:24:00

to be wrong.

3:24:02

So, using the rule of three, I know

3:24:04

that x

3:24:08

It will be equal to we multiply

3:24:11

cross-pollinated, those we know, that

3:24:13

is 6 * 100%

3:24:17

and we're going to divide it into what remains

3:24:21

alone, which is 30%.

3:24:23

As we saw earlier, it is possible

3:24:25

Simplify these percentages there, now

3:24:28

that are multiplying. And here we go

3:24:31

Simplify the numbers too.

3:24:34

We can simplify 30 with 6 or with

3:24:38

100. Look, notice, with 100

3:24:39

Dividing by 10 is also possible. Tea

3:24:41

three left. Here's 10 for you. And now

3:24:43

We can simplify 3 with 6 and

3:24:47

Dividing by 3 you get one and here you

3:24:49

There are two left. So, this is going to be 2 *

3:24:54

10 which is 20 divided by what remains

3:24:58

down below, which is 1. And 20 gave in 1 is

3:25:03

simply

3:25:04

20. And now we have it ready. We have

3:25:08

solved this exercise.

3:25:13

Now let's look at a question that came up in

3:25:15

the test. It says, "If 30 corresponds to the

3:25:19

20% of an amount, what is that amount?

3:25:23

quantity?" Yeah, let's say that said amount?"

3:25:25

quantity is x. So, we use the rule of

3:25:30

three. Quantity, our benchmark

3:25:33

corresponds to 100%.

3:25:37

And I know that my number 30 corresponds to

3:25:41

20% of that amount. Therefore, we use the

3:25:45

famous rule of three. X will be equal to

3:25:49

cross-multiply what we know

3:25:52

30 * 100%

3:25:55

divided into the one we have down here.

3:25:59

We simplify the percentages, we

3:26:01

They go. Now we can simplify things here.

3:26:05

Dividing, for example, by 20. 20/20

3:26:09

1. 100/20 is 5. Therefore, this

3:26:14

It's going to be 30 * 5 150

3:26:19

divided into

3:26:22

1 and 150, so 1 is 150. Therefore, the

3:26:27

The correct answer here is C.

3:26:31

Now we are going to solve an exercise that

3:26:35

It appears quite frequently in the

3:26:37

proof. Look, many times you're going to be

3:26:40

ask to calculate the percentage of

3:26:42

percentage of the percentage of the percentage

3:26:45

of a number. For these cases, I will tell you

3:26:49

I recommend using the first method,

3:26:51

which is the method of multiplication, since

3:26:53

It's the fastest. Using the rule of three, you

3:26:56

It can take considerably longer.

3:26:59

So, let's use the method. Look, 10%

3:27:02

60% of 150,

3:27:04

What is 60% of 150?

3:27:08

150 * 60%.

3:27:12

And if we calculate 10% of this, it

3:27:16

We multiply by 10%. The key is

3:27:19

find in multiplying all this that

3:27:22

We have it here. So, I'm going to pass it on.

3:27:26

a fraction. This is 150 multiplied

3:27:31

because of the 60% which is 60 born in 100 and the

3:27:37

10% which is

3:27:40

10/ido

3:27:41

in 100. And here you can simplify the form

3:27:44

whichever is most comfortable for you. In this case

3:27:48

I'm going to simplify it this way. Here

3:27:50

we can simplify within this same

3:27:52

fraction divided by 20. Here you get

3:27:55

3es and here you have C. Here we can

3:27:58

Simplify by dividing by 10. You get

3:28:01

1 and you have 10 left. Now, for example,

3:28:05

we could simplify crosswise

3:28:08

10 with 150 dividing by 10

3:28:11

There's 1 left and here you have 15. And he...

3:28:15

We marked it with another color, and the 5 with the 15.

3:28:19

Dividing by 5 leaves 1, and here there is 3. By

3:28:24

Therefore, we're just going to...

3:28:26

multiplying the little numbers that we

3:28:27

We agreed, the little numbers that we

3:28:29

They remained. So here we have 3 * 3 *

3:28:34

1 which gives us 9 divided

3:28:38

in 1 * 1 which is 1 and 9/ 1 is 9. And already the

3:28:45

We have a list.

3:28:48

Now let's answer a question that came up

3:28:50

in the test. What is 1% of 200%?

3:28:56

of 20? Yeah, we simply don't

3:28:59

We complicate and apply the method of

3:29:01

multiply. We multiply 200 *

3:29:05

200%

3:29:07

which is 200% of 20 times the 1% that we

3:29:12

They are asking. So this is 200 *

3:29:17

200 pairs in 100

3:29:21

multiplied by 1/.

3:29:25

So here before arriving and

3:29:28

Let's try to simplify multiplying in the

3:29:30

to the extent possible. Look, I want you to

3:29:33

Notice something before continuing. Here

3:29:36

I have a 200 pair for 100.

3:29:39

If I perform the division, this is a

3:29:41

two. Do you realize? And here, because

3:29:44

For example, we could simplify 100

3:29:46

with 200. Dividing by 100 gives 1.

3:29:49

There are 2 left here. And now we only have one left.

3:29:53

Multiply 2 * 2 * 1, what is it? 4

3:29:58

divided into the one we have here and 4

3:30:02

Say 1 is 4. The correct one is letter B.

3:30:08

Now we are going to learn how to calculate what

3:30:11

A percentage is a number of another number. Already, in

3:30:15

In this case, we have that the percentage is one.

3:30:18

of four. I'm going to show you two paths.

3:30:21

The first one is using the rule of three. In

3:30:24

In this case, how do you want to see what

3:30:25

percentage is one of cu, four is your

3:30:30

total.

3:30:32

This is from copper and 4 corresponds to 100%.

3:30:39

Now we're going to say that one is going to

3:30:41

correspond to a certain percentage,

3:30:44

Let's call it x.

3:30:47

So, x using the rule of three will be

3:30:50

equal to the product of those we know

3:30:53

Cross-tabulation leaves you with 1%

3:30:58

divided into

3:31:00

The one left all alone is 4. Therefore

3:31:03

Therefore, you can perform this division here.

3:31:05

directly. 100 times 4 is 25%

3:31:12

And we have it ready.

3:31:14

Now, another way to look at it is the

3:31:17

following. This was the first path. He

3:31:20

The second path is as follows. Look, if

3:31:23

I want to see what percentage is a

3:31:25

number of another one, this one we have here,

3:31:29

This one from another will be the total. This is

3:31:32

your total. So, what can you do?

3:31:34

It is also the following. Tomas the

3:31:37

number, which in this case is the

3:31:39

one, the one they ask for, you divide into the

3:31:42

total, which comes to four, and it

3:31:46

multiply by 100%.

3:31:49

And this leads you to exactly the same place.

3:31:52

result. Look, 1 * 100%

3:31:56

divided into 4 and we already saw that

3:31:59

This results in 25%.

3:32:03

And this is also quite a method

3:32:05

quite fast. Look, I want you to

3:32:07

Let's do it again one more time, but now

3:32:09

We're going to assign it another value. Look,

3:32:11

I want you to tell me

3:32:13

What percentage is 3 of when this

3:32:17

method.

3:32:18

I'm going to do it right away. Already. That

3:32:21

What percentage is it? 3 divided into 4, which is

3:32:27

my total and I multiply this by 100%.

3:32:32

So, this is good. Here we can

3:32:34

simplify. We simplify by dividing

3:32:36

Multiplying by 4 gives you 1, so you have 25 left. 3 * 25 is

3:32:42

75%.

3:32:45

And now we have it ready. In the book

3:32:48

I'll also leave you with this summary.

3:32:50

formula, so don't worry, there

3:32:52

I'm going to give you the details so that you can

3:32:55

use it when you deem it appropriate

3:32:57

That's convenient, if this suits you better

3:32:59

way, but you can always do it by

3:33:02

Use the rule of three and you arrive at exactly the

3:33:04

same. Now let's answer a question,

3:33:07

PES, from what we just saw. That

3:33:10

What percentage does 25 out of 125 correspond to?

3:33:16

They already have both paths. I will use here

3:33:18

TR rule, which is what the

3:33:20

most, but if you want to use the other

3:33:21

method, which is quite fast, no

3:33:23

problem. So, look, I'm going to say

3:33:26

Since this is 125,

3:33:30

that 125

3:33:32

This corresponds to 100% of me.

3:33:37

Therefore, I will now say that 25

3:33:39

corresponds to a percentage, let's say, x.

3:33:43

Therefore, x is equal to 25

3:33:49

* 100%

3:33:51

divided into the one that remains alone, which is

3:33:54

125. And here we simplify. I'm going to

3:33:58

Simplifying by dividing by 25 will give you

3:34:02

stay here 25.

3:34:05

And 125/25 will give you 5. Also

3:34:10

We can simplify 5 with 100

3:34:13

Dividing by 5 gives you 1, and here you go

3:34:17

to remain 20. Finally 1 * 20%

3:34:22

It's 20%

3:34:25

divided into the one we have here. AND

3:34:28

Since we're talking about one, it's not

3:34:29

necessary to write that therefore, the

3:34:33

The correct answer is B.

3:34:36

Now we're going to study the increases and

3:34:39

the percentage decreases.

3:34:42

Here, language is very important because

3:34:46

a single word can change the

3:34:48

result, as we had seen

3:34:50

previously when we studied the

3:34:52

language in integers. Look,

3:34:54

We will take the following into account.

3:34:57

We're starting with the increases. If I have

3:34:59

a number x that increases by, attention

3:35:04

Here, at i%, it will result in

3:35:08

as follows. Pay attention. This is

3:35:12

the same as taking x and adding

3:35:16

the i% of x. That's exactly it.

3:35:23

the same. Every time I say that

3:35:25

increases in or increases a or in a or in its,

3:35:33

etcetera means that your number

3:35:35

You're going to add the original to, in this case,

3:35:39

i% of that value. This calculation is

3:35:44

equivalent, pay attention here, to take your

3:35:47

original value and multiply it by the

3:35:51

100% of what you initially had

3:35:54

plus this new 1%. You close parentheses and

3:35:58

You put it as a percentage. You arrive

3:36:01

exactly the same result.

3:36:04

Now we will study the second case.

3:36:07

If we have a number x that

3:36:10

increases to y% of its original value, goes

3:36:15

resulting in the following.

3:36:17

Look, here's something very important that

3:36:20

You have to keep in mind that here

3:36:23

There is the word A. It will increase to

3:36:27

a certain value, therefore, means that

3:36:29

as we have one and had seen before,

3:36:31

It's going to be transformed.

3:36:34

In other words, we go from having x to having

3:36:37

directly

3:36:39

x * i%

3:36:42

And there we have the value we need.

3:36:46

This is going to be the result. Remember that

3:36:50

this Aua

3:36:52

transformation.

3:36:54

In this case, X is transformed to 1% of

3:36:59

its original value. It is very important that

3:37:02

Please note that since this is a

3:37:06

increase, we are in the case of the increase

3:37:09

that increases to something, in this case

3:37:11

Specifically, we have to when we have

3:37:15

It increases to and must be greater than 100.

3:37:21

Because? Because otherwise it wouldn't exist.

3:37:23

increasing, it would remain the same if

3:37:25

Let it be 100. And if, for example, it says it increases

3:37:28

30% in that case doesn't make sense.

3:37:32

since it is increasing to 30%

3:37:35

It's going down there. So in this case

3:37:38

and must be greater than 100. In this case, that

3:37:44

What we had up here is irrelevant,

3:37:45

It can be any value, but here it must

3:37:49

be greater than 100 so that it effectively

3:37:52

there is an increase.

3:37:55

Now, with what we have learned,

3:37:56

Let's answer a question that might...

3:37:58

to go out in the test. In a store

3:38:01

decides to raise all prices in a

3:38:04

15%.

3:38:05

By what number should the

3:38:08

old prices to get the new

3:38:11

price? I really want you to lend a lot.

3:38:14

Pay attention because this is going to go up, it's

3:38:18

That is, it will increase by 15%. By

3:38:22

Therefore, we are going to encounter this

3:38:24

case, which is going to be the most typical case

3:38:26

that you're going to catch. This one here

3:38:29

It's a bit convoluted, but this is going to be

3:38:31

the most typical one. So, here you'll have

3:38:35

two paths. To express it this way,

3:38:37

that is, as a sum, or express it

3:38:39

as a product. The result. In this

3:38:43

In that case, how are they going to ask you to take the

3:38:45

original price and multiply it by

3:38:47

Something, I'm going to express it this way

3:38:49

manner. So, pay attention. Let's suppose

3:38:52

that I had a price of P and like this

3:38:57

It increases by 15%, I'm going to

3:39:00

multiply by the 100% that I have

3:39:03

initially

3:39:05

plus this new 15%.

3:39:08

Therefore, we're going to be left with p*

3:39:11

115%

3:39:15

and this is equivalent to having

3:39:18

115

3:39:20

born in 100. And if you divide 115 into

3:39:24

100, the result of this will be 1.15.

3:39:30

Therefore, the correct one is letter D.

3:39:34

And now we have it ready.

3:39:37

Now, what would happen, for example, if

3:39:40

Now we have this case? Look,

3:39:43

the flow rate of a river is from pubic areas per

3:39:47

second. If upon receiving a tributary its

3:39:51

flow rate increases by 15%,

3:39:55

What is its new flow rate? In meters

3:39:57

cubics per second. Already. Here's our

3:40:00

The number increases by 15%. Like I said,

3:40:04

This is going to be the case that you're going to

3:40:05

find in 99.9%

3:40:08

most of the time.

3:40:11

So how do we do it? Look, I want you to

3:40:13

notice that for the most part

3:40:16

You have nothing but sums. Here's a

3:40:18

product, but if you look closely, this is

3:40:21

15% of P, but here this is

3:40:25

increasing, you won't be left with 15% of

3:40:27

something, but it will be greater than that

3:40:29

worth. So what's going on here?

3:40:32

simple. Occupy this space that we had

3:40:35

I've learned it and with this I'll solve it.

3:40:36

touch. Look, I want to express it as

3:40:38

addition. Yeah, cool. It had a P-value that

3:40:43

We are going to increase it by 15%. Already. And this

3:40:48

I increase it by 15% of P. And we are

3:40:53

almost ready. This is P plus P * 15% which is

3:40:59

the same as 15/ in 100. And this is p + p

3:41:04

* 15, 15p divided by 100. And which one

3:41:10

Is that the alternative? It is alternative D.

3:41:14

And now we have it ready. So, here

3:41:17

I want to emphasize something very important to you.

3:41:20

Both paths, whether adding them up or

3:41:24

Multiplying, they lead you exactly to

3:41:27

same result, but many times it will

3:41:30

depend on how the

3:41:33

alternatives. That's why here you

3:41:35

I ask that you always remember those two

3:41:38

methods and you'll never fail at this

3:41:41

type of questions. Now we're going to

3:41:44

to answer a question that came up in a

3:41:46

peers. I'm going to show you two paths. He

3:41:49

first using the rule of three and the

3:41:52

second, with what we have learned. Without

3:41:54

However, we're going to have to resolve this here.

3:41:56

in this second method with an equation.

3:41:59

But we'll get there later anyway.

3:42:01

to study the equations, so don't

3:42:03

don't worry. Look, method number one, let's go

3:42:06

read it. If P increased by 40%

3:42:11

If 150 is the number of 150, which of the following is the number of 150?

3:42:15

expressions correspond to P? So,

3:42:18

Here we want to increase P by 40% and

3:42:24

When this is done, it means that the

3:42:26

The result is 150.

3:42:29

Therefore, using the rule of three,

3:42:31

What would this be like? I know that P

3:42:33

corresponds to 100% of the value and 150,

3:42:40

which is, remember, is the number that

3:42:42

We have here, it will correspond to the

3:42:44

next percentage. We increased it here.

3:42:46

by 40%, therefore, 100% is

3:42:51

It added 40% and this makes it

3:42:55

140%.

3:42:57

So here you just need to use

3:42:58

rule of three, where p equals

3:43:04

of P is equal to

3:43:07

We multiply 150 * 100%

3:43:13

divided into the one that remains alone, which is

3:43:15

140%.

3:43:18

And here it's enough to simply simplify

3:43:20

the percentages, since the

3:43:23

alternatives are only expressed

3:43:25

as an operation. In this case 150%

3:43:30

divided into 140 and the correct one is the

3:43:33

Letter B. It's exactly the same. He

3:43:37

the order of the factors does not alter the

3:43:39

product. Already? So this is a

3:43:43

a path that, as I say, is quite

3:43:45

useful and you can do it using the rule of

3:43:47

TR. Now, the second path is by assembling

3:43:51

an equation that, how is it going to be? Look,

3:43:54

They tell you that P has increased by 40%.

3:43:58

We know this is P because of how

3:44:00

It's an increase of 40%. We entered

3:44:05

This case again, as I said,

3:44:07

This is the most typical case.

3:44:10

And here this is going to be 100%. You

3:44:13

We added 40%

3:44:15

And they tell you that this means that it is

3:44:20

equal. Here we build equality,

3:44:24

It's 150.

3:44:27

So, this is P * 140%

3:44:33

= 150.

3:44:36

Remember that this 140%

3:44:38

is the same as the fraction 140/ido in

3:44:42

100. Now, how do we solve for P? That

3:44:45

Is that what interests us? Simple. When

3:44:48

you are multiplying pcon

3:44:50

And if you want to clear P, the only thing you're going to do is

3:44:53

To do is multiply by the reciprocal of

3:44:55

the fraction. which causes it to happen there

3:44:58

simplify completely. I'm going to do

3:45:01

the step-by-step, but

3:45:03

It's quite simple, as I said, these p

3:45:06

* times 140 divided by 100. Remember that

3:45:10

When you multiply in an equation you must

3:45:12

multiply on both sides. Here you go

3:45:14

100 born in 140

3:45:17

= 150 * 100 born in 140. And as you

3:45:23

I mean, here the 140 is simplified with the

3:45:25

140, the 100 with the 100. It is

3:45:27

multiplying a number by its

3:45:28

reciprocal. The result will be 1. And p

3:45:32

* 1 is simply p. And if you look closely,

3:45:35

You arrive at exactly the same place. This says

3:45:37

that p equals 150%

3:45:41

divided into 140. You arrive exactly at

3:45:46

same result.

3:45:49

Now we will study the decrease

3:45:52

percentage. And here we're only going to

3:45:54

express how it will look on you

3:45:56

result. It's the same logic. Yeah

3:45:58

We have a number x that decreases by one

3:46:02

i%, results in. Already. This could be

3:46:06

an n, can be an n, a, can be a,

3:46:12

It can be in, his, etc. Always there

3:46:16

It will be expressed in these ways. And the

3:46:18

You can calculate the result of this from

3:46:19

two ways. The first is that you take x and

3:46:24

subtract y% from x. You do this and we're in.

3:46:29

Ready. But it will also be

3:46:31

exactly the same as taking x and

3:46:34

multiply it by the 100% you had

3:46:37

initially

3:46:39

and subtract

3:46:41

the i% that we are taking away. You arrive

3:46:44

exactly the same result. It is the

3:46:47

same logic we just saw. And in the

3:46:50

in case they tell you that x decreases to a

3:46:53

i% of its original value, as we have

3:46:57

Here, this 'a' means that it will be

3:47:00

transform at i% of its value

3:47:03

original. Therefore, a equals

3:47:06

transformation. Therefore, x becomes

3:47:09

be directly

3:47:11

x by

3:47:14

and%. And that way you have it ready

3:47:18

result. Like I said, it's the same

3:47:21

logic that we are seeing in the

3:47:23

increases, only here it changes to a

3:47:26

decrease, but it is exactly the

3:47:29

same logic.

3:47:30

Now we are going to study what the

3:47:33

discounts and for that we're going to do it

3:47:35

with a practical example. Look, the price

3:47:38

from the UIM, the ultra-intensive M was of

3:47:42

50,000 pesos. However, it is found

3:47:45

with a 40% discount.

3:47:48

What is the discount amount? Already here

3:47:52

I want you to keep something very important in mind

3:47:55

important for discounts.

3:47:58

Attention. When one performs a

3:48:01

discount, what happens is the

3:48:03

following. You take the original price and

3:48:07

You subtract the discount amount and this gives you

3:48:12

gives the new price, that is, the

3:48:16

The original price is the same as the new price.

3:48:20

plus the discount amount. And this is

3:48:24

It's very important that you keep this in mind.

3:48:26

because depending on what they ask you,

3:48:29

You're going to have to do one calculation or another.

3:48:31

So, I'm going to give you an example.

3:48:33

practical. Look, let's suppose that you

3:48:34

I bought a TV that was 100

3:48:36

cheap luquitas and they made you a lot

3:48:39

a discount of 30 bucks and this makes

3:48:44

that the price you paid

3:48:45

It is indeed 70 grand. That's the

3:48:49

logic. So what's going on here?

3:48:53

When they ask you, for example, the

3:48:56

discount amount, they are not

3:48:58

asking how much you paid. In fact, it

3:49:01

I'll leave it here. Look, they're not on your watch.

3:49:03

They're asking you how much you paid.

3:49:06

asking how much they discounted you.

3:49:09

And this is simply done by taking, in

3:49:12

In this case, since it's a 40% discount,

3:49:15

taking 40% of your original value.

3:49:18

So, 50,000*

3:49:21

40%.

3:49:24

Already. If you perform this operation, you will

3:49:27

resulting in 20,000.

3:49:31

Because? Look, let's use the logic of

3:49:34

always. What is 10% of 50,000?

3:49:38

Five grand, right? And five

3:49:41

luquitas 10%. Therefore, if they ask me

3:49:43

40%, which is four times more, 4 times

3:49:46

5,000 is 20,000. You arrive exactly at the

3:49:49

same. So this is the amount of the

3:49:54

discount. It's this thing you have here, that

3:49:56

That's what they're asking you.

3:49:59

But what would happen, for example, if

3:50:01

now instead of the discount amount you

3:50:04

They ask, let's say, the price that

3:50:06

Did you pay? What's the price

3:50:10

What did you pay?

3:50:12

Already. And here I want you to pay attention.

3:50:15

Here we are looking for the price that

3:50:17

You did indeed pay. Look, I already did it.

3:50:20

You can calculate by difference. Like you

3:50:22

You had to say the price was 50 luquitas

3:50:26

and they gave you a discount amount of

3:50:28

20,000 pesos, what was paid was 30

3:50:31

Lucas, right? That's the price that

3:50:34

You had to pay. However, and here

3:50:37

I want you to pay attention to this.

3:50:39

It can also be calculated this way. you

3:50:41

you were taking the original price which was

3:50:43

50,000 and since the discount is a

3:50:46

decrease, in this case a

3:50:48

a 40% decrease, this is equivalent to

3:50:51

50,000 percent less the 40% that he

3:50:55

We remove, therefore it is 50,000

3:50:59

by 60%.

3:51:03

and 60,000 times 60% if you do the calculation,

3:51:06

It will give you those same results.

3:51:09

30,000.

3:51:10

Therefore, here's the learning I want

3:51:13

What you should keep in mind is that when

3:51:15

Please talk about discounts, lend a hand.

3:51:18

Pay attention to what they ask of you. They can

3:51:20

ask for the new price, that is, the

3:51:22

the price you will actually pay, or

3:51:24

They may ask you for the discount amount,

3:51:27

which can also be

3:51:30

expressed as the money that you

3:51:32

You saved. In this case we save 20

3:51:34

luquitas. They can ask you about it.

3:51:36

both ways. They might say to you, "Hey,

3:51:37

What was the discount amount or

3:51:39

How much did you save? And both are

3:51:41

exactly the same.

3:51:43

Now, suppose they tell you that

3:51:46

following. Look, the price of the UIM was

3:51:50

of 50,000 pesos, but at the time of payment

3:51:53

They apply a discount to you and you just have to

3:51:56

pay 30,000es.

3:51:58

What percentage discount was granted?

3:52:02

Yes, you have to be very careful here.

3:52:05

because you need to understand the

3:52:07

context. Look, here's what I suggest you do it.

3:52:09

by the rule of three when they ask you

3:52:11

get the discount percentage.

3:52:14

So what do we need to get the

3:52:17

discount percentage? to know the

3:52:20

The discount amount is fundamental; this is crucial.

3:52:23

So, look here at the original price,

3:52:27

Remember that it's the same as the new price.

3:52:31

plus the discount amount. Price

3:52:33

original 50 luquitas. New price, 30

3:52:36

luquitas. Therefore, what was the amount?

3:52:39

of the discount?

3:52:40

20 luquitas. Well, let's leave it at that.

3:52:42

color. 20 luquitas. Already. So, here

3:52:49

to use the rule of three and obtain the

3:52:51

percentage discount, we have to

3:52:52

use the discount amount. Therefore

3:52:54

Therefore, 50,000

3:52:57

It was 100%.

3:53:00

And now I know the discount amount

3:53:03

It was 20,000,

3:53:06

Therefore, this corresponds to a

3:53:08

percentage let's say X and that X is the

3:53:11

discount percentage. But remember

3:53:14

always with the discount amount, for

3:53:16

Please, when they ask you for the percentage of

3:53:18

discount. Okay, now we're going to

3:53:21

solve. X will correspond to 20,000

3:53:27

100%

3:53:29

divided into the one that remains alone, which is

3:53:32

50,000.

3:53:34

So, let's simplify things. Here

3:53:36

You can simplify by dividing by 10,000

3:53:39

You have 20 left and here you will have 50.

3:53:43

You can also simplify the 50 with the

3:53:46

100. Dividing by 50 gives you 1 and here

3:53:50

You have 2 left. So

3:53:53

* 2 is 40%

3:53:57

divided into the one who's left all alone here

3:53:59

down below, which is 1. And it's not necessary

3:54:01

divide, or rather, it is not necessary

3:54:03

write this match in one,

3:54:05

It's simply 40%, the percentage of

3:54:09

discount, which if you realize how it is

3:54:11

The same context is this percentage that

3:54:14

we had here. And in this way you will

3:54:17

be able to answer any question that

3:54:19

discounts will appear.

3:54:23

Many times you will come across

3:54:25

situations where there will be certain

3:54:27

amounts that will change over time

3:54:29

weather. For example, the product

3:54:32

a country's gross domestic product, the height of

3:54:34

someone, someone's body mass, eh

3:54:38

a company's sales, etc. AND

3:54:43

What they're going to ask you for is the variation

3:54:45

percentage over time. And for

3:54:48

I want you to always remember this

3:54:51

percentage variation formula that

3:54:54

It will simply be the final value

3:54:57

less the initial value always divided,

3:54:59

always, always at the initial value by

3:55:02

100%.

3:55:04

If we have here the result of this

3:55:09

It is positive, it means and it is interpreted

3:55:13

It seems like there was an increase. If it is

3:55:15

negative, it is interpreted as there being a

3:55:18

decrease. And if it's zero, it means that

3:55:21

It remained exactly the same.

3:55:24

Now I want us to resolve some

3:55:26

examples to make this much clearer

3:55:28

clear. Look, the price of a share

3:55:30

It went up from 100 pesos to 120 pesos. What was

3:55:35

the percentage change in its price?

3:55:38

Yes, the percentage change.

3:55:42

So, here in the variation

3:55:43

percentage, you know this is going to be

3:55:45

the final value minus the initial value

3:55:50

always divided by the initial value

3:55:54

multiplied by 100%.

3:55:57

The key, obviously, lies in

3:55:58

determine which is the initial one and which is the

3:56:00

the end. In this case, the initial one is

3:56:03

100 and the final number is 120. Therefore,

3:56:08

This is going to be 120

3:56:10

- 100 divided by 100 multiplied by

3:56:16

100%.

3:56:18

So this is going to be 120 - 100 is 20

3:56:22

divided by 100 multiplied by 100%. AND

3:56:28

Here we can simplify things. Can

3:56:30

Simplify by dividing by 100. Here you go

3:56:33

There will be one left, and here too you will...

3:56:35

one to remain. It's important here that the sign

3:56:38

the percentage remains unchanged.

3:56:41

So, what would this look like? 20 * 1%

3:56:45

which is 20%

3:56:48

divided into the one we have here which is 1.

3:56:51

And we simply don't write that.

3:56:54

Therefore, here the result is

3:56:56

Positive means there was an increase

3:56:59

of 20%. And this is the result of the

3:57:03

percentage change.

3:57:06

Now, what would happen, for example, if the

3:57:10

a low stock price happens in this

3:57:12

case of 100 pesos to 70

3:57:16

pesos? What was the percentage change?

3:57:19

of the price? Yes, in this case,

3:57:22

Again, the percentage change

3:57:24

It will always be final value minus value

3:57:26

initial always divided by the value

3:57:29

100% initial payment.

3:57:33

So, this is my starting value, this

3:57:36

This is my final value. This is going to be 70 -

3:57:40

100 divided into 100 * 100%.

3:57:47

So, 70 - 100 is -30, say in 100 *

3:57:55

100%.

3:57:57

Therefore, we can simplify here

3:57:59

Dividing by 100 you get 1, you get

3:58:02

1. And finally this is going to be -30 * 1%

3:58:07

- 30%

3:58:09

divided into 1. But it's not necessary

3:58:12

Write that 1. Therefore, the variation,

3:58:15

Attention, here it's -30%.

3:58:19

When we talk about variation

3:58:20

The percentage result can be

3:58:23

No problem, because here

3:58:25

We're simply talking about variation,

3:58:26

which can be positive, negative, or zero.

3:58:30

Now, if we talk about interpretation

3:58:34

It's something else, because in this case, as

3:58:36

we know that the variation was negative,

3:58:40

It means that here, and as again, you

3:58:43

I mean, this is the interpretation

3:58:45

This means that this decreased.

3:58:50

30%.

3:58:53

That's the interpretation.

3:58:57

And in this way we have, well, already

3:58:59

solved our exercise where

3:59:01

They only asked us for the variation

3:59:04

percentage.

3:59:06

As I mentioned a few seconds ago,

3:59:09

They often talk to you about the

3:59:11

interpretation

3:59:13

instead of the variation. In other words, you

3:59:16

They ask what percentage it increased or how much

3:59:19

what percentage did it decrease? And the truth is

3:59:22

that the formula of the variation

3:59:24

Percentages will always be useful, but

3:59:27

with certain nuances. Because? Because

3:59:30

Here's what the result might look like

3:59:32

positive or negative. So, because

3:59:34

For example, if you happen to see a question

3:59:36

where here instead of the variation you

3:59:39

Ask about the decrease, you're not going to

3:59:41

answer - 30%, but you're going to

3:59:44

reply, "Hey, it decreased by 30%." By

3:59:47

Therefore, this formula, as I say, the

3:59:50

You can always use it, but always

3:59:52

Be careful with the interpretation.

3:59:55

The formulas I'm going to show you

3:59:57

The following are formulas that are for

4:00:00

to arrive directly at the result without

4:00:03

having to change the signs,

4:00:05

particularly useful for when

4:00:08

You work with letters. However, and you

4:00:12

I'll repeat myself, now that I know the formula

4:00:15

of percentage variation, you can

4:00:17

answer any questions about the increase

4:00:19

or decrease, only that in the case

4:00:21

of a decrease you would have to

4:00:23

later you when you express

4:00:25

the answer change the sign. By

4:00:28

Therefore, this part here is going to be

4:00:31

Opendas, but I recommend it to you. Look,

4:00:34

Let's begin with the increase. On the rise

4:00:38

It's simply the same formula as the

4:00:41

variation, since it will always

4:00:43

test positive. There's no need to do it

4:00:45

no change. For example, the price of

4:00:48

One share rose from 50 pesos to 80 pesos,

4:00:51

By what percentage did its price increase?

4:00:53

Yes, simple ones, the same formula. Worth

4:00:55

final minus initial value divided into

4:00:58

initial value per 100%.

4:01:01

So, 80, which is your final value, 50

4:01:06

which is your initial value, we replace it

4:01:09

and we solve it, no more. So here it goes

4:01:13

30 divided into 50 * 100%.

4:01:20

And now we're going to simplify things as much as possible.

4:01:23

that it is possible. Podos simplify

4:01:24

Dividing by 50 you get one and here you

4:01:29

There are two left.

4:01:31

So, this is going to be 30 * 2%, which is

4:01:35

60%

4:01:37

divided into the one we have here by ourselves,

4:01:39

which is 1, which is not necessary

4:01:41

write it. So, we have 60% here.

4:01:45

As a result, it means that it increased in

4:01:47

60%

4:01:50

and nothing more than that.

4:01:53

Now, in the case of the decrease, if

4:01:55

Something changes. And here, listen up, here's what

4:01:59

We're going to do what we can to make sure the result doesn't

4:02:01

we then have to change the sign

4:02:03

as we had to do with the

4:02:04

percentage change, is simply

4:02:07

in the numerator take the initial value and

4:02:12

subtract the final value. It's the only thing that

4:02:16

changes. Everything else remains the same

4:02:18

exactly intact.

4:02:21

So,

4:02:23

For example, at the beginning of the week, a

4:02:26

The container held 25 L of water. Upon completion

4:02:32

Only 10 L remained. What percentage

4:02:36

Did the amount of water in the container decrease?

4:02:39

Already. Please note that this question here is from

4:02:43

a decrease

4:02:45

where we have the initial value here, here

4:02:49

We have the final value and how we want it

4:02:52

to obtain the decrease directly, one

4:02:54

What it does is the following. Take the

4:02:58

initial value, subtracts the final value and

4:03:02

You always divide it by the initial value and

4:03:05

all this at 100%.

4:03:08

So, initial value 25, we subtract

4:03:11

the final value 10

4:03:14

divided into always in the initial value

4:03:17

which is 25 * 100%.

4:03:21

This is 15 divided by 25

4:03:26

* 100%

4:03:28

And here we're going to simplify things as much as possible.

4:03:30

that it is possible. We can simplify here

4:03:33

Dividing by 25 gives 1 and here we get 4.

4:03:38

So

4:03:40

* 4% is 60%

4:03:43

divided into this one that remains all alone,

4:03:46

But it's not necessary to write it.

4:03:49

So here's the thing, which decreased by one

4:03:53

60%.

4:03:55

And in this way we arrive directly at the

4:03:58

result that they ask for and possibly

4:03:59

The alternatives that appear for you are...

4:04:01

60% appears directly.

4:04:04

And as I said, this formula helps you.

4:04:07

enough to get directly to the

4:04:09

decrease and if they were to appear

4:04:10

lyrics, this will help you a lot

4:04:13

so that later we don't have to keep moving it

4:04:15

the letters and changing signs.

4:04:17

Finally, let's review what they are

4:04:19

the percentage points. Remember that

4:04:22

The percentage points represent

4:04:25

absolute differences between two

4:04:28

percentages. Nothing more than that.

4:04:31

Absolute difference between two

4:04:34

percentages.

4:04:36

They are used when we compare rates or

4:04:39

indices that are already expressed in

4:04:41

percentages,

4:04:43

avoiding confusion with increases or

4:04:45

decreases

4:04:47

relative.

4:04:49

Very important, this takes up quite a bit of space.

4:04:52

uh, many times in the news, in the

4:04:55

surveys, etc. For example, in

4:04:57

Election periods tell you, hey,

4:04:59

certain candidate

4:05:02

increased by so many percentage points.

4:05:06

That's just how it's done.

4:05:09

absolute differences and it does more

4:05:12

The calculation is simple. So, look, here

4:05:16

Let's look at the next question where

4:05:19

Let's explore the difference between

4:05:22

percentage points and variations

4:05:25

percentages that we studied

4:05:27

previously. Look, 100 people were surveyed

4:05:31

people in April to find out if they would vote

4:05:34

by candidate A, where 50% stated

4:05:38

that I would vote for him.

4:05:41

The same was carried out in May

4:05:43

survey of the same 100 people

4:05:46

indicating that 60% would vote for him.

4:05:51

First question, in how many points

4:05:54

The percentage increase in voting for the

4:05:57

Candidate A? Yes, look, they're talking to you about

4:06:00

percentage points, therefore

4:06:03

We are only interested in the difference.

4:06:05

absolute between the percentages.

4:06:08

So, I have 60%.

4:06:10

I have 50%.

4:06:13

Their difference 60 - 50 is 10. Therefore,

4:06:20

It's 10 percentage points and nothing more

4:06:24

That's it. It's quite fast. Now,

4:06:28

Pay attention here. If they ask you

4:06:31

Next, by what percentage did it increase?

4:06:34

number of people who would vote for the

4:06:38

Candidate A? They're talking about a

4:06:42

An increase, right? a percentage of

4:06:45

increase in relation to the amount

4:06:49

previous, that is, a relative change.

4:06:53

And you remember that I had you here

4:06:54

mentioned that confusion is avoided here

4:06:57

with the increases or decreases

4:06:59

relative. In this case, in the second

4:07:02

They're asking me about a raise.

4:07:05

percentage of an amount that increased to

4:07:07

through time. Look, in April,

4:07:11

In April we had that 50% of the 100

4:07:14

people

4:07:16

I would vote for him. So, we have 50 here.

4:07:19

people. Then in May it's 60% of

4:07:23

100, right? There are 60 people. Therefore,

4:07:26

Here we do the increase formula

4:07:29

percentage. final value less value

4:07:32

initial divided by the initial value

4:07:36

100%.

4:07:38

Therefore, final value 60, initial value

4:07:41

50 divided by the initial value which is

4:07:43

50 * 100%.

4:07:47

This is 10 times 50 * 100%. And here we go

4:07:54

Simplify 50 with 100 by dividing

4:07:57

Dividing by 50 gives 1. Dividing by 50 here

4:08:00

This leaves 2. Therefore, 10 * 2% is

4:08:06

20% divided into this remaining portion here, which

4:08:09

It is the one that is not necessary

4:08:10

write it. Therefore, notice here that the

4:08:14

increase in relation to the amount that

4:08:17

The voting rate before is 20%. and you realize

4:08:21

that there is a difference there in those

4:08:22

results depending on what it is

4:08:24

ask me. Here they talk about points

4:08:28

percentages is simply the difference

4:08:30

absolute between percentages. If they talk to you

4:08:33

By what percentage did the amount increase?

4:08:36

people who would vote in this case for

4:08:38

Candidate A, we're talking about a

4:08:41

change in relation to a quantity

4:08:43

initial of people and in this case it is a

4:08:47

relative change that in this case will

4:08:48

to be a 20% increase and we use the

4:08:52

percentage increase formula that

4:08:54

we studied previously.

4:08:58

In conclusion, let's establish

4:09:00

again the key difference between a

4:09:03

variation and percentage points.

4:09:06

When calculating the variation in

4:09:10

in relation to an initial value, by

4:09:13

For example, the price, a quantity of

4:09:16

people, some units of something,

4:09:19

etc., we speak of variation

4:09:22

percentage.

4:09:24

However, when comparing the

4:09:26

difference between only two

4:09:30

percentages, for example, the rate of

4:09:32

Unemployment rises from 5% to 7%,

4:09:36

Let's talk about percentage points.

4:09:41

Generally, the questions will help you.

4:09:43

to indicate exactly that they are

4:09:45

by asking, but this way you can

4:09:48

to make a difference.

4:09:51

Now we're going to learn how to solve it step by step.

4:09:54

I'll pass on the questions from this content that

4:09:57

They might come out in peace. To do this,

4:09:59

Go down to the description and you'll find them.

4:10:01

to find all the questions and then

4:10:04

return to this part of the video so that

4:10:07

Let's keep learning.

4:10:09

And we begin the summary of powers.

4:10:14

First, let's remember the

4:10:16

definition of powers and that is that a

4:10:19

Power is a way of expressing

4:10:23

repeated multiplication of the same

4:10:26

number. Let's remember that a power is

4:10:29

It goes like this, where a

4:10:33

corresponds to the base and n to the exponent.

4:10:38

And this is calculated as follows:

4:10:40

manner. If I have a raised to the power of

4:10:43

exponent n, we're simply going to

4:10:47

multiply by itself so many times

4:10:51

as indicated by the exponent. In this case

4:10:55

We are going to multiply a total of n times

4:10:59

on its own. Now let's look at some

4:11:04

Examples to make this clearer.

4:11:08

Suppose we have a 3 raised to the power of 2,

4:11:12

which is also called a 3 square when

4:11:15

The exponent is 2. So here we go

4:11:20

multiply 3 by itself twice.

4:11:25

3 * 3 and 3 * 3 9 and we have it. List.

4:11:33

Now we have a 5 raised to the power of 3. When the

4:11:38

If the exponent is 3, we say that the number

4:11:40

It's cubed. In this case, 5³.

4:11:45

Already? So let's multiply the 5

4:11:48

three times by itself. We're going to be left with

4:11:51

5 * 5 * 5. We do the calculation. 5 * 5 25

4:11:59

and times 5 it will result in 125.

4:12:05

Finally, let's get to this power that

4:12:07

is a power of a fraction. Look at this.

4:12:11

Later we'll see how to do it more

4:12:13

fast. For now, we're just going to

4:12:15

to stay with the definition. Let's go

4:12:18

multiply 2/3

4:12:21

three times by itself. Then he's going to

4:12:24

remain 2/3 * 2/3 * 2/3.

4:12:29

And what do we have here? 2 * 2 * 2 we're good

4:12:32

resulting in 8 divided by 3 * 3 * 3

4:12:38

which results in 27. And we have

4:12:42

This power has been resolved. Now let's see

4:12:46

Some examples of powers of numbers

4:12:48

negative. Here, parentheses play a role

4:12:51

fundamental role. We will see later

4:12:54

because. Look, here we have -2².

4:12:58

-2²

4:12:59

is the same as -2 * -2

4:13:04

And this is less is more, and we're left with 4

4:13:08

as a result.

4:13:10

Now we have -2 raised to the power of 3. So

4:13:15

It's going to be -2 * -2 * -2. Please don't

4:13:21

Don't skip any parentheses in these

4:13:23

numbers. which are negative.

4:13:26

So, -2 * -2

4:13:30

And if this is multiplied by -2, the

4:13:32

The result will be -8. Remember,

4:13:36

Positive times negative is negative.

4:13:40

So, here's the result we have

4:13:42

-8.

4:13:45

Now, taking this into account, I want

4:13:48

that we see a classic mistake. Look,

4:13:51

we have in the first power a -3².

4:13:57

Since we have a parenthesis, we already saw that

4:13:59

This is the same as -3 * -3, which gives

4:14:04

as a result

4:14:06

9. And now we have it ready. But what

4:14:10

This happens when we don't have a

4:14:14

parenthesis? How is the case of what

4:14:17

What do we have down here? Pay attention. It

4:14:22

What's happening here is that these two, this

4:14:26

exponent is only raising to the

4:14:29

base 3, nothing more. Since there is no

4:14:33

parentheses, the 2 only considers the

4:14:36

three. Therefore, when calculating

4:14:40

The result, at least, stays here and

4:14:44

one calculates the power 3 raised to 2, which

4:14:48

It's 3 * 3. So, here's what we'll have.

4:14:52

- 9 as a result.

4:14:56

Therefore, never forget the role of these

4:15:00

parentheses at the time of calculating

4:15:02

powers, because they make the difference

4:15:05

in the result you can achieve

4:15:08

obtain.

4:15:10

Now we are going to study the properties

4:15:11

of the powers, which are fundamental

4:15:14

to answer the questions you have

4:15:15

can come out in the test. Well,

4:15:18

We begin with a common good that says

4:15:21

as follows. If I have a base a

4:15:24

different from 0, a raised to the power of 0 will give

4:15:28

as a result 1. For example, if I have

4:15:31

a 2 raised to the power of 0 per property, this goes

4:15:35

to be 1. If I have a 3 raised to the power of 0, it will be

4:15:39

to be 1. If I have -5 raised to the power of 0, the

4:15:44

the result will be.

4:15:47

Now it's important, if you have a 0

4:15:50

raised to the power of er, this is not defined. By

4:15:53

Therefore, the base here must be different from

4:15:57

cer.

4:15:58

Now, if I have 1 raised to an exponent

4:16:02

n, the result of this will be 1. By

4:16:05

For example, if I have 1²AD

4:16:08

is 1. 1 raised to the power of 3 1, 1 raised to the power of 500 1.

4:16:15

Nothing more than that. And this happens because

4:16:17

is multiplying one so many times

4:16:20

by itself and pure 1 by 1 by 1

4:16:22

It always results in one.

4:16:25

So, what else do we have here? If I have

4:16:30

a base zero and I have an exponent

4:16:33

positive, I'm going to have to 0 raised to the power of

4:16:36

That exponent will be. For example, 0

4:16:40

quad is 0* 0 which is 0. 0 raised to the power of 5

4:16:45

It will also be 0. And so on.

4:16:48

And now we enter the properties

4:16:51

more fundamental.

4:16:53

The first one will be the multiplication of

4:16:55

powers with the same base. What does this tell me?

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